Application Flashcards

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1
Q

scientists investigated the movement of iron ions (Fe3+) from the soil to old and young leaves of heat-treated barley plants and to leaves of plants that were not heat treated.

heat treatment was applied half way up to the leaves. the scientists determined the concentration of Fe3+ in the top and lower halves of the leaves of each plant.

Figure showed old leaf being similar in both heat treatment and untreated showed young leaf having lower ratio in treated than untreated.

what can you conclude about the movement of Fe3+ in barley plants?

A
  • heat treatment has greater effect on young leaves than old
  • heat treatment damages phloem
  • Fe3+ moves up leaf
  • Fe3+ transported in xylem in older leaf
  • in young leaf, some in xylem, as some still reaches top part of leaf
  • all ratios show there is less Fe3+ in old leaves than yong
  • no statistical test to show significant difference
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2
Q
A

genus

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3
Q
A

spores spread

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4
Q
A
  • measure diameter of large number of spores
  • divide measured values by 700 to get actual diameter
  • using volume of sphere
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5
Q

explain the shape of curves between 50 and 60 degrees

A
  • denaturation at both
  • at 60 is faster - more KE
  • active changes shape - no ESC
  • hydrogen bonds broken
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6
Q
A
  • rapid digestion of proteins
  • can absorb more amino acids for growth, reprod etc
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7
Q
A
  • hydrolyse peptide bonds to rel amino acids
  • amino acids can cross cell surface membrane
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8
Q
A

kingdom - mammalia

phylum

class

order

genus - cavia

species - porcellus

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9
Q

what limits the rate of this reaction between points A and B

give evidence from graph

A
  • substrate concentration
  • as substrate concentration inc, rate inc
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10
Q

suggest a reason for the shape of the curve between C and D

A

all active sites filled up

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11
Q
A
  • similar shape
  • less ESC formed
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12
Q

explain why doctors stopped measuring the amounts of 14C

explain how 14C in CO2 came from 14C in glucose in the blood?

A
  • little or no difference at 8 hours
  • between ALL groups
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13
Q

CO2 in the breath contained in the radioactive form of carbon, 14C

explain how 14C in carbon dioxide came from 14C in glucose in the blood

A
  • respiration occurs
  • by cells/tissues
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14
Q

doctors concluded that measuring the amount of 14C in the carbon dioxide in the breath after 3 hours was a better way of diagnosing lactose deficiency than the lactose intolerance test

do you agree

A
  • clear difference
  • between lactose deficient and IBS group
  • as SDs dont overlap
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15
Q
A
  • greater rate of oxygen consumption - greater rate of resp - greater rate of uptake
  • oxygen needed for resp
  • respiration produces ATP
  • K+ uptaken by active transport which needs ATP
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16
Q

explain why 2cm3 of water was added to tubes A and C

A
  • give same vol of B
  • to keep conc of gelatine constant
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17
Q

explain results of A and B

A
  • enzyme in pineapple digested gelatine
  • no gelatine - no jelly
  • enzyme denatured due to hydrogen bonds, ionic and disulfide bonds broken
  • by HCl - due to change in pH
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18
Q

what is the purpose of tube c

A
  • for comparison / control
  • show enzyme in pineapple that digested gelatine boiling denatured
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19
Q

describe what is meant by a malignant tumour

A
  • mass of undifferentiated totipotent cells
  • uncontrolled cell division
  • metastasis
20
Q

give one reason for the change in death ratae from malignant skin tumours with increasing age

A

immune system weaker

21
Q

data for fair skinned and dark skinned people were collected differently

explain why skin colour was a factor likely to affect death rate

A

melanin prevents burning

  • less cancer risk
22
Q

what stimulates spiracles to open

A

increasing CO2 conc

23
Q

explain what causes oxygen conc in trachea to fall when spiracles are closed

A
  • oxygen used in resp
  • diffuses from trachae to tissues
  • oxygen unable to enter organism
24
Q

insects live in dry conditions

suggest an advantage of the pattern of spiracle movements shown in the diagram

A
  • spiracles not open all time
  • less water loss
25
Q

hydrolysis and condensation are important in the formation of new adult proteins

how

A

hydrolysis - breaks down proteins

condensation - forms new proteins

26
Q

most of protein stored in the body of a fly larva is a protein called calliphorin

explain why different adult proteins can be made using calliphorin

A

amino acids can be rearranged into diff sequences

27
Q

describe how you would expect the number of lysosomes in a pupa to change with age of pupa

A
  • fall, increase, fall
  • lysosomes associated with tissue breakdown
28
Q

suggest an explanation for the change in RNA conc in the first 40% of time spent in pupa

A
  • tissue cells being broken down
  • RNA hydrolysed
  • by enzymes from lysosomes
  • no new RNA made
29
Q

suggest an explanation for the change in RNA conc between 60 and 80 % of time spent as a pupa

A
  • RNA associated with making protein
  • new adult tissue forming
30
Q

explain why it is useful to give data for men and women separately

A
  • big differences
  • give eg
31
Q

data like these often given as percentages of people dying from each cause

explain the advantage of giving thses data as percentages

A
  • sample sizes roughly same for comparison
  • different numbers of people in each group
32
Q
A

cytoplasm of red blood cells filled with haemoglobin

33
Q
A
  • membrane has phospholipid bilayer
  • stain binds to phospholipid
  • on inside AND outside of membrane
34
Q
A
  • high to low using carrier / channel proteins
  • specific to substrate
  • down conc gradient
35
Q

explain difference between curve B and C

A
  • with comp inhib - enzyme sub collisions still inc
  • binding of comp - no change in shape of active
  • binding on non-comp - changing of active site
  • at high sub conc - enzyme active site available
  • at high sub conc with non comp - not available
36
Q
A
  • repeat soil sorting for diff times and record number of species collected
  • find optimum time beyond which no further sorting leads to inc in animal species found
37
Q
A
  • little digestion of starch by salivary amylase
  • amylase also secreted by pancreas
  • most starch digestion occurs in small intestine
38
Q
A
  • hydrogen bonds between pairs holds pairs together
  • MANY hydrogen bonds provide strength
39
Q
A

ribosomes assemble polypeptides using mRNA code

OR

DNA has 2 strands each with different base sequence

40
Q
A
  • stops translation
  • allows detachment of polypeptide from ribosome
41
Q

why grew in nutrient poor sand

A

no boron provided

42
Q

why grew in dark

A

no sucrose produced in leaves by photosynth

43
Q
A
  • evaporate all water
  • no burning
44
Q

do results support scientists hypothesis

A

YES

  • uptake of sucrose greater
  • transport to other parts of plant

NO

  • no evidence that boron reacts with sucrose
45
Q
A
  • take thin section of plant tissue
  • place against photographic film in dark for several hours
46
Q
A
  • antigen on surface of Nm binds to surface of protein on Bcell
  • B cell divides by mitosis
  • division stimulated by T cells
  • plasma cells release antibodies
  • B cells become memory cells
  • memory cells produce antibodies faster
47
Q
A
  • mutation
  • results in resistancy allele in Nm to ONE antibiotic
  • cell survives, reproduces and passes allele for resistancy onto offpsring
  • process repeated with diff genes - resistant to 2 antibiotics