Amines Flashcards

1
Q

Drawback of ammonolysis of alkyl halides

A

A mixture of compds are obtained

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2
Q

What will be formed when OH is used instead of H for hydrolysis in gabriel phthalimide synthesis?

A

The compound’s salt will be formed

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3
Q

Why can’t aromatic amines be formed by Gabriel reaction?

A

Due to difficulty of aryl group to react due to partial double bond, instability of phenyl cation, sp³ attached to sp² and presence of e’ rich benzene

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4
Q

Why is Fe/HCl preferred over Sn/HCl for reduction of nitro group?

A

Since HCl is produced as 1 of the products which can later be used by Fe again to give H+ used for reduction

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5
Q

Why can’t LiAlH4 be used with aliphatic compds?

A

It will not give amines

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6
Q

Why are aliphatic amines more basic than aromatic?

A

Since lone pair in aromatic is used for resonance

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7
Q

For acylation of amines, which doesn’t react?

A

3° amine since it doesn’t have H on it.

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8
Q

Hinsberg reagent

A

Benzene sulphonyl chloride

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9
Q

Hisnberg reagent will not react with?

A

3° amine since it doesn’t have H

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10
Q

Test to distinguish amines

A

Hinsberg reagent test which is not given by 3° amine

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11
Q

3methyl aniline to 3 nitrotoluene

A

Diazotization + NaNO2(Cu, heat)

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12
Q

aniline + benzoyl chloride

A

N phenyl benzamide

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13
Q

aniline to 1,3,5-tribromobenzene

A

Br2/H2O + Diazotization + Cu(H3PO3 + H2O)

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14
Q

distinguish ethylamine & aniline

A

azo dye test(HNO2 + HCl) + dil.NaOH

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15
Q

Distinguish Aniline & benzylamine

A

HNO2 + H2O

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16
Q

Why is pKb of aniline more than that of methyl amine?

A

E` pair is involved in conjugation so it is less available for protonation than methylamine

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17
Q

Why Ethylamine is soluble in water but aniline is not?

A

H bonding but in aniline, due to bulky part, bonding is less

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18
Q

Methyl amine in water reacts with FeCl3 to ppt rust

A

Methylamine is more basic than water so it accepts a proton from water

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19
Q

Why although amino group is o- & p- directing in aromatic electrophilic substitution, aniline on nitration also gives m-nitroaniline?

A

aniline gets protonated in the presence of conc. HNO3 & conc H2SO4 to form anilium ion which is m- directing

20
Q

Aniline doesn’t undergo Friedel Crafts reaction. Why?

A

Aniline begin a lewis base forms a complex with AlCl3, a lewis acid. So N of aniline becomes +ve & acts a strong deactivating group

21
Q

Diazonium salts of aromatic amines are more stable than those of aliphatic amines. Why?

A

Aromatic amines are resonance stabilised unlike in aliphatic amines.

22
Q

Gabriel phthalimide synthesis is preferred for synthesising primary amines. Why?

A

It produces primary amines only without traces of secondary or tertiary amines.

23
Q

ethanoic acid to methanamime

A

SOCl2 + NH3 + Hoffmann

24
Q

hexanenitrile to aminopentane

A

H3O(partial) + Hoffmann

25
Methanol to ethanoic acid
PCl5 + KCN + H3O
26
Ethanamine to methanamine
HNO2+ K2Cr2O7 + NH3 + hoffmann
27
Ethanoic acid to propanoic acid
LiAlH4 + P/I2 + KCN + H2O
28
Methanamine to ethanamine
HNO2 + P/I2 + KCN + Reduction
29
Nitromethane to dimethyl amine
Sn/HCl + carbylamine + [H]
30
Propanoic acid to ethanoic acid
NH3 heat + Hoffmann + HNO2 + K2Cr2O7
31
Nitrobenzene to benzoic acid
Sn/HCl + diazodization + CuCN + H2O
32
Benzene to m-bromophenol
Nitration + Bromination + Sn/HCl + Diazotisation + H2O
33
Aniline to 2,4,6-trobromoflurobenzene
3br2 + diazotisation + HBF4
33
Benzoic acid to aniline
NH3 + Hoffmann
34
Benzyl chloride to 2 phenyl ethanamide
KCN + 4[H]
35
Chlorobenzene to p-chloroaniline
nitration + Sn/HCl
36
Aniline to p-bromoaniline
(CH3CO)2O + Br2/CH3COOH + H3O
37
Benzamide to toluene
Hoffmann + diazotisation + H3PO2/H2O + acylation
38
Aniline to benzyl alcohol
Diazotisation + CuCN + 4[H] + HNO2
39
Hydrolysis of CN gives
acid
40
Partial hydrolysis of CN gives
amide group
41
reduction of CN gives
amine
42
Hydrolysis of diazonium salt gives
Phenol
43
Acyl group with NH3 gives
Amide
44
Heating of diazonium salt with water gives
Phenol
45
Phenol + PCl5 gives
Chlorobenzene
46
Acid + NH3 gives
Amide