Alkanes Flashcards
what are alkanes
- saturated hydrocarbons (each carbon is bonded 4x with maximum no. of H)
- CnH2n+2
what is the shape of an alkane
- tetrahedral around the carbon atom
- bond angle of 109.5
- the bonds repel each other equally
- electrons AFAP
size of molecule related to forces
- the bigger the molecule the more induced dipole-dipole forces as you have larger electron clouds
when boiling, what is being broken
- when you boil a liquid the weak induced dipole dipole forces are broken
- NOT the covalent bonds
effect of chain length on BP
- chain length increases
- BP increases
- molecules have larger SA
- more surface contact
- greater London forces
- more energy needed to overcome forces
effect of branching on BP
- lower BP
- fewer surface points of contact
- fewer London forces
- molecules cant get as close because branches are in the way
Describe the complete combustion of alkanes
- alkanes burn in oxygen completely to form co2 and water
why are alkanes good fuels?
- burn readily to produce large amounts of energy
- readily available
- easy to transport
- burn in plentiful o2 without producing any toxic products.
describe the incomplete combustion of alkanes
- limited oxygen = H-atoms in alkane are oxidised to water
- CO or C(soot) formed due to incomplete combustion of C
describe CO and soot
- poisonous, colourless and odourless gas
- binds to haemoglobin and prevents oxygen bonding
CO can be removed using a catalytic converter - soot can cause breathing problems
- dirty building
- clog up engines
Describe the reaction of alkanes with halogens
initiation:
- the covalent bond in the Halogen(Br2) is broken by homolytic fission
- energy for this bond fission is provided by UV
- each bromine takes an electrons from the shared pair forming 2 Br radicals:
Br-Br = Br• + Br•
propagation:
- the reaction propagates through 2 propagation steps - a chain reaction :
CH ₄ + Br• = •CH₃ + HBr
•CH₃ + Br₂ = CH₃Br + Br•
Termination:
- when 2 radicals collide, forming a molecule with all electrons paired
Br• + Br• = Br₂
•CH₃ + •Br = CH₃Br
why do alkanes lack reactivity
- C-C and C-H bonds are strong
- C-C bonds are non-polar
- EN of C+H is so similar that the C-H bond can be considered non-polar.
limitations of radical substitution
- further substitution occurs producing a variety of products (which have to be separated due to being impurities)
- substitution can occur at different points on the carbon chain (isomers)
how to reduce the further substitution in radical
- adding excess organic compound (methane)
- there is a greater chance of the halogen (chlorine) reacting with the methane.