7. Gene and genotype frequency calculations, gene mapping, QTL-analysis Flashcards

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1
Q

Which is not true in the Hardy-Weinberg role?

The sum of the genotype frequencies is equal to 1.00 (100%)

The frequency of homozygous genotypes (AA%, aa%) is equal to the allele frequency squared (AA% = p2, aa% = q2)

The frequency of heterozygous genotype (Aa%) is equal to twice the product of the allele frequencies (Aa% = 2pq)

The sum of the individuals by genotype is equal to the doubled population size (2N)

A

The sum of the individuals by genotype is equal to the doubled population size (2N)

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2
Q

Which condition is not true for a panmictic (random) population? Individuals which are forming it have the …

same vitality

same fertility

same mating chance

same genotype

A

same genotype

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3
Q

Which statement is false? The effective number of alleles…

is the lower the more equals are the allelic frequencies

calls the attention to the very rare allelic variants

takes the different allelic frequencies into consideration

generally shows lower values than the observed number of alleles

A

is the lower the more equals are the allelic frequencies

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4
Q

A population is in genetic equilibrium if …

its parental populations by gender carried the same allelic frequencies

the next generation will show the same gene- and genotype frequencies

the influence of the evolutionary processes there are not excluded

the difference between the observed and expected genotype frequencies is not significant

A

the influence of the evolutionary processes there are not excluded

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5
Q

Which is not true for a sex linked trait?

In females the allele frequency is equal to the square root of the genotype frequency

Sex-linked recessive genetic disease (XLGD) occurs more frequent in males than in females

Males are never affected because of the hemizygozity

In males the allele frequency is equal to genotype frequency (p = A% = AA%, q = a% = aa%)

A

Males are never affected because of the hemizygozity

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