12.2 Proteins and Enzymes Flashcards

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1
Q

Structure of amino acid

A
  • Amine group
  • R group
  • Carboxylic acid group
  • Hydrogen
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2
Q

What is a dipeptide?

A
  • Two amino acids joined
  • Via a condensation reaction
  • Joined by a peptide bond
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3
Q

Describe the structure of proteins

A
  • Polymer of amino acids;
  • Joined by peptide bonds;
  • Formed by condensation reactions;
  • Primary structure is number AND order of amino acids;
  • Secondary structure is folding of polypeptide chain into Alpha-helix and Beta-pleated sheets due to hydrogen bonding;
  • Tertiary structure is 3-D folding due to hydrogen bonding and ionic bonding and disulfide bridges;
  • Quaternary structure is two or more polypeptide chains joined together;
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4
Q

Describe how a peptide bond is formed between two amino acids to form a dipeptide

A
  1. Condensation (reaction) / loss of water;
  2. Between amine / NH2 and carboxyl / COOH;
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5
Q

Test for proteins

A
  • Place the sample in a test tube
  • Add equal volumes of Biuret solution
  • Colour change to purple shows protein is present
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6
Q

Enzyme

A
  • Globular proteins which act as biological catalysts
  • Increase the rate of reaction
  • Lowering the activation energy
  • Done by stressing AND distorting the bonds during the formation of the ESC
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7
Q

Lock & Key model

A
  • Active site is rigid and does not change shape
  • Substrate binds to enzymes active site
  • Substrate fits exactly to the complementary active site
  • Products are formed so are released as no longer fit the active site
  • Enzyme free to take part in another reaction
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8
Q

Induced fit model

A
  • Active site not complementary
  • Active site changes shape as the substrate binds
  • So stressed the substrate bonds to lower the Ea of the reaction
  • Active site returns to its original shape
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9
Q

Describe how an enzyme-substrate complex increases the rate of reaction

A
  1. Reduces activation energy
  2. Due to bending bonds OR Without the enzyme, very few substrates have sufficient energy for the reaction.
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10
Q

Describe how a change in the base sequence of the DNA coding for an enzyme may result in a non-functional protein.

A
  1. Change in primary structure changes
    sequence of amino acids;
  2. Hydrogen bonds and Ionic bonds and Disulphide bonds form in different positions;
  3. Alters the tertiary structure of the enzyme / alters shape of active site;
  4. No Enzyme-Substrate complexes can be formed;
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11
Q

Describe the induced fit model of enzyme action.(2)

A
  1. Active site not complementary;
  2. Active site changes (shape) / is flexible;
  3. (Change in enzyme allows) substrate to able to fit / Enzyme-Substrate complex to form;
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12
Q

Describe one way that the lock and key model is different from the induced fit model(2)

A
  1. Active site does not change (shape) / is fixed (shape) / is rigid / does not wrap around
  2. substrate / (already) fits the substrate / is
  3. complementary (before binding);
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13
Q

An enzyme catalyses only one reaction. Explain why.

A
  1. (Enzyme has) active site is a specific shape;
  2. Only one substrate fits / binds (the active site);
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14
Q

Diabetes mellitus is a disease that can lead to an increase in blood glucose concentration. Some diabetics need insulin injections. Insulin is a protein so it cannot be taken orally. Suggest why insulin cannot be taken orally.(2)

A
  1. Broken down by enzymes / digested / denatured (by pH) /too large to be absorbed;
  2. Insulin no longer functional
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15
Q

Sucrase does not hydrolyse lactose. Use your knowledge of the way in which enzymes work to explain why.(3)

A
  1. Lactose has a different shape/structure;
  2. Does not fit/bind to active site of enzyme/sucrase;
    OR
  3. Active site of enzyme/sucrase has a specific shape/structure;
  4. Does not fit/bind to lactose so no Enzyme-Substrate Complexes formed.
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16
Q

When a pathogen causes an infection, plasma cells secrete antibodies which destroy this pathogen.
Explain why these antibodies are only effective against a specific pathogen.(2)

A
  • Antigens (on pathogen) are a specific shape/ have specific tertiary / 3D structure;
  • Antibody fits/binds / is complementary to antigen/ antibody-antigen complex forms; OR Antibodies are a specific shape / have specific tertiary/ 3D structure;
  • Antigens (on pathogen) fit/ bind/ are complementary to antibody / antibody-antigen complex forms;
17
Q

Factors effecting enzyme action

A

Temperature
pH
Substrate conc
Enzyme conc

18
Q

Effect of temperature on ROR

A
  • Increase in temp
  • Increase in kinetic energy
  • More successful collisions
  • More ESC form per second
  • Denaturation: past the optimum the hydrogen/ionic bonds will break causing a change in tertiary structure causing a change in the active site
  • Active site is no longer complementary so less ESC
19
Q

Effect of pH on ROR

A
  • Enzymes have an optimal pH
  • If made more acidic or more basic
  • Charge on R groups are changed
  • Ionic bonds are broken
  • Tertiary structure is changed
  • Active site changes shape
  • No longer complementary
  • Less ESC formed
20
Q

Effect of substrate conc. on graph

A
  • Increases
  • Then plateaus
  • As enzyme becomes the limiting factor
21
Q

Effect of enzyme conc. on graph

A
  • Increases
  • Then plateaus
  • As substrate becomes the limiting factor
22
Q

Explain how a competitive inhibitor works

A
  1. Inhibitor is a similar shape to substrate;
  2. Inhibitor enters active site / competes with substrate;
  3. Less substrate binds/fewer enzyme-substrate complexes form per second.
23
Q

Describe how a non-competitive inhibitor works

A
  1. Attaches to the enzyme at a site other than the active site (allosteric site);
  2. Changes (shape of) the active site OR Changes tertiary structure (of enzyme);
  3. (So active site and substrate) no longer complementary so less/no substrate can fit/bind (‘no longer complementary so less/no enzyme-substrate complexes form’);
24
Q

What is the proteome of a cell?

A

The proteome is the full) range of / number of different proteins that a cell is able to produce (at a given time);
OR
(The proteome is the full) range of / number of different proteins the genome / DNA is able to code for;

25
Q

Describe & explain how you could use the biuret test to distinguish a solution of enzyme, lactase, from a solution of lactose(2)

A
  1. Add Biuret reagent to both solutions) – no
    mark;
  2. Lactase / enzyme will give purple / lilac / mauve;
    OR
  3. Lactose / reducing sugar will not give purple /
    lilac /mauve / will remain blue;
  4. Because Lactase is a protein;