Work Problems Flashcards
T/F: similar to rate problems, work problems use the formula rate*time=work?
True
for two objects working together: work1+work2 = ?
work_total
how do represent worker time for a problem where the workers start a job together but one of them stops working before the job is complete?
let the time for the worker who works less time be x, and the time for the worker who works longer be x+t, where t is the unknown difference in time between when the first worker stops and the job is complete
how do we handle the case where the time it takes an object to complete a job (or fraction of a job) is unknown?
let the rate contain the job(s) in the numerator and let the denominator be the variable t. ex: object A can complete 1 job in an unknown amount of time; the rate is 1/t
how do you figure out the percent of a job done by a certain worker?
first, find the total amount of work done. since w=r*t, find the contribution of each worker as a function of time (ex. worker 1 puts together 1 bookshelf every 4 hours, and worker 2 does 1 every 8 hours, so their work contributions are t/4, and t/8 respectively), then divide the contribution of the individual worker by the total (the t’s will cancel out)
how do you calculate two or more workers combined rate?
add them; if worker A can complete one bench in x hours and worker B can complete one bench in y hours, their combined rate is 1/x+1/y
how do you handle opposing worker problems, where one worker “dampens” the rate of work of the other worker?
you subtract the rate of the dampening worker to find the “net” work rate
how do you figure out how long it will take a subset (or superset) of an original group of workers whose rate you have been given to complete a job? ex: 5 workers working at same constant rate can complete a job together in 6 days, how long would it take 2 of them to complete the job?
first define rate of five workers: (1 job)/(6 days)
single worker method: find the rate of a single worker. since there are 5 workers, divide the groups rate by 5 -> (1/6)/5 = 1/30. then multiply that single rate by two since you want to know how long it takes to of them ->1/15
proportion method: set up a proportion-> (1/6)/(5) = (1/x)/(2) -> 5 people can do 1 job in 6 days, and two people can do one job in x days