Unit 2 Practice Exam Questions Flashcards
Small signaling molecules such as NO bind to surface receptors on target cells (T/F)
False, these small molecules interact directly with enzymes in the cytoplasm
If chorionic villus testing returns a result of 47,XY,+21, then it can be concluded that the fetus has down syndrome. TF?
False, results from CVS testing could reflect an anomoly in the placenta only (confined placental mosacism). All abnormal results from CVS must be confirmed by amniocentesis
23 . For the enzymatic reaction shown below, the following rate constants were determined: k1 = 10 mM-1 sec k2 = 20sec k3 = 40sec-1
What is the dissociation constant of the
enzyme-substrate complex?
dissociation constant = k2/k1
20/10 = 2nM
It has been shown that chromosomal breakage and rearrangement are key characteristics of cancer. A. True B. False
true
Hexokinase and glucokinase are isozymes that carry out the initial step of glucose metabolism, conversion of glucose to glucose-6-phosphate. Hexokinase has a Km for glucose of 0.1 mM and glucokinase has a Km
for glucose of 5 mM. Cytosolic glucose
(substrate) concentration is 2 mM in a fasting subject and 6 mM in a subject who has just eaten a large meal. Which of the following conclusions can be drawn from this in formation?
A. The rate of the hexokinase reaction will triple when the glucose concentration goes
from 2 mM to 6 mM.
B. The rate of the glucokinase reaction will triple when the glucose concentration goes
from 2 mM to 6 mM.
C. At 2 mM glucose, 2/7 of the active sites on glucokinase are bound to substrate.
D. All of the above are true.
E. None of the above are true
C, use equation Fe=[s]/(km+[s])
total enzyme concentration = 1nm
inhibitor = 2nm
Uninhibited enzyme = slope 4, y int of 1
+2mM inhibitor A = slope 8, y int of 1
+2mM inhibitor B = slope 8, y int of .5
what can be concluded from this data?
A.Both inhibitor A and inhibitor B are competitive inhibitors.
B. Both inhibitor A and inhibitor B have the same Ki
C.The plot for inhibitor A will have the same x intercept as the plot for the uninhibited
enzyme.
D.The Ki for inhibitor B will double if the total enzyme concentration is doubled
both have same Ki
both have same slope and same concentration
plug into alpha = 1+ I/Ki
Activated T cells express _______________, which binds to B7 with 20 times higher affinity than CD28 and results
in _____________ of T cell activity and proliferation.
CTLA, Suppression
Superantigens are…
bacterial toxins that activate T-cells at a 100x greater rate than other antigens
Describe the drug used for immune rejection
CTLA fused to Fc region of an Ig molecule
Patient had a helminth infection resulting in high levels of IFN gamma and activated macrophages. Patients serum had high levels of IgG. Pronogis?
Poor, due to prescence of a TH1 response.
Need TH2 for helminths (IgE)
A cyclin molecule can best be described as…
the regulatory subunit of a protein kinease
After prolonged exposure to a high concentration of a hormone, you find that a specific tissue shows a greatly
decreased response to the hormone (adaptation). What is most likely to be responsible?
a change in the number of receptors on each cell
patient presents with tumor, DNA reveals novel mutations in kknown/suspected receptors associated with tumor tissue. Which type of receptor is frequently the target of oncogenic mutations and therefor most likely to be linked to the tumor growth in this patient?
Receptor Tyrosine Kineases
EBV vs CMV?
EBV causes severe sore throat more often
Which of the following statements about herpesvirus latency is CORRECT?
A: Latency is a hindrance to vaccine development because the virus genome is maintained in the cell for the life of the infected
person.
B: Latency is established before symptoms of the primary infection are apparent.
C: Reactivation from latency may not be apparent to the infected person.
D: The genome is present in a cell but infectious virions are absent.
E: All of the above
F: None of the above
all of the above
After polio binds GI receptors. When does infection begin and what happens next?
infection begins when genome enters cytoplasm
Polio’s genome is +ssRNA which is recognized by ribosomes, so the next step involves translation of genomic mRNA into viral polyprotein by host ribosomes
child has recurrent infections with labs showing absence of large granular lymphocytes. Flow cytometry shoes normal numbers of CD3+, CD19+, and lack of CD56+ cells. What ist he probable mechanism?
mutation of an essential transcription factor
NK cells are “large granular lymphocytes” with a cd56+ receptor
Which statement about rotovirus is correct?
- incidence peaks during summer
- Gastroenteritis is most common in infants and toddlers
- icosahedral, enveloped, -ssRNA virus
- heat killed injectable rotovirus vaccine is used in the US; the live, attenuated, rotavirus vaccine is used in other countries
b - Gastroenteritis caused by the virus is most common in infants/toddlers