Transition Metals Flashcards by Lucy Lovell | Brainscape

Q

Fe^2+

Colour

A

Pale green solution

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Q

Fe^3+

Colour

A

Pale yellow solution

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Q

Mn2+

Colour

A

Pale pink solution

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Q

[Cu(H2O)6]^2+

Colour

A

Blue solution

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Q

Cu^2+

Colour

A

Blue solution

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Q

Fe(OH)2

[Fe(H2O)4(OH)2]

Colour + name

A

Green precipitate

Tetraaquadihydroxoiron(II)

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Q

Fe(OH)3

[Fe(H2O)3(OH)3]

Name and colour

A

Orange-brown precipitate

Triaquatrihydroxoiron(III)

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Q

Mn(OH)2

[Mn(H2O)4(OH)2]

Name and colour

A

Light brown precipitate

Tetraaquadihydroxomanganese(II)

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Q

[CuCl4]^-2

Name and colour

A

Yellow solution

Tetrachlorocuprate(II)

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Q

Cu(OH)2

[Cu(H2O)4(OH)2]

Name and colour

A

Blue precipitate

Tetraaquadihydroxocopper(II)

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Q

[Cu(NH3)4(H2O)2]^2+

Colour+ name

A

Dark blue solution

Tetraamminediaquacopper(II)

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Q

Cr^3+

Colour

A

Violet solution

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Q

Cr(OH)3

[Cr(H2O)3(OH)3]

Name and colour

A

Triaquatrihydroxochromium(III)

Green-grey precipitate

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Q

Cr(OH)6

Colour and name

A

Dark green solution

Hexahyrdoxochromium(III)

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Q

[Cr(NH3)6]^3+

Name and colour

A

Purple solution

Hexaamminechromium(III)

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Q

Fe^2+. +2OH^-

Product

A

Fe(OH)2

Q

Fe^3+ + 3OH^-

Product

A

Fe(OH)3

Q

Mn^2+. +2OH^-

Product

A

Mn((OH)2

Q

[cu(H2O)6]^2+. +4Cl^-

Products

A

[CuCl4]^2- + 6H2O

Q

Cu^2+ + 2OH^-

Product

A

CU(OH)2

Q

If you add small amounts of dilute NH3 to to Cu^2+ it

A

Acts as a base and you get Cu(OH)2

Q

If you add an excess of NH3 to Cu^2+ it

A

Dissolves the Cu(OH)2 and ligand substitution occurs

Q

[Cu(H2O)6]^2+ + 4NH3

Product

A

[Cu(NH3)4(H2O)2]^2+

Q

Cr^3+ +3OH^-

Product

A

Cr(OH)3

Q

If you add excess OH^- to Cr^3+ it

A

Dissolves the green grey precipitate

Q

Cr(OH)3. + 3OH^-

Product

A

Cr(OH)6^3-

Q

If u add dilute NH3 to Cr^3+ it

A

Acts as a base

Q

If you add an excess of concentrate NH3 to Cr^3+

A

Then ligand substitution occurs

Q

[Cr(H2O)6]^3+. +6NH3

Products

A

[Cr(NH3)]^3+. + 6H2O

Q

Convert Fe2+ to Fe3+ using

A

Acidified potassium manganate (VII)

Q

Convert Fe3+ to Fe2+ using

A

Iodide ions ( I-)

Q

Convert the Cr3+ in [Cr(OH)6] to CrO4 2- by

And colour change

A

Warming with hydrogen peroxide (H2O2)

Dark green to yellow

Q

Convert chromate (VI) CrO4 ^2- to dichromate (VI) Cr2O7^2-

And colour change

A

Add dilute sulfuric acid

Yellow to orange

Q

Reduce Cr2O7^2- to Cr^3+

A

Acidified zinc

Q

Reduction of copper to and off white precipitate

A

Iodide ions form copper(I)iodide

Q

Cu^+ spontaneously ……. to produce ….+…….

A

Disproportionates to Cu and Cu^2+