Transition Metals Flashcards
Fe^2+
Colour
Pale green solution
Fe^3+
Colour
Pale yellow solution
Mn2+
Colour
Pale pink solution
[Cu(H2O)6]^2+
Colour
Blue solution
Cu^2+
Colour
Blue solution
Fe(OH)2
[Fe(H2O)4(OH)2]
Colour + name
Green precipitate
Tetraaquadihydroxoiron(II)
Fe(OH)3
[Fe(H2O)3(OH)3]
Name and colour
Orange-brown precipitate
Triaquatrihydroxoiron(III)
Mn(OH)2
[Mn(H2O)4(OH)2]
Name and colour
Light brown precipitate
Tetraaquadihydroxomanganese(II)
[CuCl4]^-2
Name and colour
Yellow solution
Tetrachlorocuprate(II)
Cu(OH)2
[Cu(H2O)4(OH)2]
Name and colour
Blue precipitate
Tetraaquadihydroxocopper(II)
[Cu(NH3)4(H2O)2]^2+
Colour+ name
Dark blue solution
Tetraamminediaquacopper(II)
Cr^3+
Colour
Violet solution
Cr(OH)3
[Cr(H2O)3(OH)3]
Name and colour
Triaquatrihydroxochromium(III)
Green-grey precipitate
Cr(OH)6
Colour and name
Dark green solution
Hexahyrdoxochromium(III)
[Cr(NH3)6]^3+
Name and colour
Purple solution
Hexaamminechromium(III)
Fe^2+. +2OH^-
Product
Fe(OH)2
Fe^3+ + 3OH^-
Product
Fe(OH)3
Mn^2+. +2OH^-
Product
Mn((OH)2
[cu(H2O)6]^2+. +4Cl^-
Products
[CuCl4]^2- + 6H2O
Cu^2+ + 2OH^-
Product
CU(OH)2
If you add small amounts of dilute NH3 to to Cu^2+ it
Acts as a base and you get Cu(OH)2
If you add an excess of NH3 to Cu^2+ it
Dissolves the Cu(OH)2 and ligand substitution occurs
[Cu(H2O)6]^2+ + 4NH3
Product
[Cu(NH3)4(H2O)2]^2+
Cr^3+ +3OH^-
Product
Cr(OH)3
If you add excess OH^- to Cr^3+ it
Dissolves the green grey precipitate
Cr(OH)3. + 3OH^-
Product
Cr(OH)6^3-
If u add dilute NH3 to Cr^3+ it
Acts as a base
If you add an excess of concentrate NH3 to Cr^3+
Then ligand substitution occurs
[Cr(H2O)6]^3+. +6NH3
Products
[Cr(NH3)]^3+. + 6H2O
Convert Fe2+ to Fe3+ using
Acidified potassium manganate (VII)
Convert Fe3+ to Fe2+ using
Iodide ions ( I-)
Convert the Cr3+ in [Cr(OH)6] to CrO4 2- by
And colour change
Warming with hydrogen peroxide (H2O2)
Dark green to yellow
Convert chromate (VI) CrO4 ^2- to dichromate (VI) Cr2O7^2-
And colour change
Add dilute sulfuric acid
Yellow to orange
Reduce Cr2O7^2- to Cr^3+
Acidified zinc
Reduction of copper to and off white precipitate
Iodide ions form copper(I)iodide
Cu^+ spontaneously ……. to produce ….+…….
Disproportionates to Cu and Cu^2+