Topic 11: Further equilibrium

Question 1

The partial pressure of a gas in a mixture of gases is

Answer 1

the pressure that the gas would exert if it alone occupied the volume of the mixture.
wA(g) + xB(g) ⇌ yC(g) + zD(g)
partial pressure of gas A = w (number of moles of gas A) / w + x + y + z (total number of moles of gas)
this equals the mole fraction of A which is then multiplied with the total pressure of the mixture