Surface area to volume ratio Flashcards

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1
Q

what types of substances can be exchanged

A

oxygen + nutrients taken in
CO2 + urea secreted
heat to stay at roughly same temperature

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2
Q

ways in which substances can be transported

A

active transport

passive transport

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3
Q

smaller animals will have a …sf area: volume ratio

A

higher

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4
Q

why can’t direct diffusion be used for multi-cellular organisms

A
  • too slow

- cells too far away from exchange surface

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5
Q

how are substances exchanged in multi-cellular organisms and why

A

mass transport

as larger animals have lower sf area : volume ratio

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6
Q

how are substances exchanged in single-celled organisms and why

A

substances diffuse directly

- small distance of travel

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7
Q

a small distance of travels allows for a

A

quicker rate of diffusion

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8
Q

what 2 things does mass transport maintain

A

final concentration gradients

relatively stable environment

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9
Q

the rate of heat loss depends on

A

surface area of organism

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10
Q

how does being a larger animal affect heat loss and why

A

larger animal = larger volume, smaller surface area

harder to lose heat

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11
Q

how does being a smaller animal affect heat loss and why

A

smaller volume so larger surface area

heat is lost more easily

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12
Q

how is heat loss compensated for in smaller animals

A

higher metabolic rate

to generate enough heat to stay warm

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13
Q

how would having a compact shape benefit a smaller animal

A

smaller sf area

minimises heat loss

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14
Q

what is a compact shape dependent on

A

temperature

environment

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15
Q

how would a less compact shape affect an organism

A

greater sf area : volume ratio

increases heat loss

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16
Q

what are some adaptations for exchange

A

kidney adaptations in desert animals = less urine
due to high sf area: vol ratio
so water loss is compensated for

17
Q

what are the features of an efficient exchange surface

A

large sf area
short diffusion distance
maintain concentration gradient
animals : plentiful blood supply

18
Q

the rate of diffusion =

A

sf area difference in conc / length of diffusion path