Redox and Electrode Potentials Flashcards

1
Q

What are the steps to construct redox equations

A

Write half equations
Balance hydrogens
Balance electrons

Form full equation - electrons cancel out

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2
Q

What are the two common redox titrations you need to know

A

Potassium manganate (VII) (KMnO4(aq)) under acidic conditions

Sodium thiosulfate (Na2S2O3(aq)) for determination of iodine (I2(aq))

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3
Q

What are the examples of manganate(VII) titrations

A

Iron(II) ions (Fe2+)

Ethanedioic acid (COOH)2

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4
Q

In iodine/ thiosulfate titrations what is oxidised and what is reduced
What are the 2 half and overall equations

A

Thiosulfate are oxidised
Iodine is reduced

Oxidation: 2S2O3^2-(aq) -> S4O6^2- + 2e-

Reduction: I2(aq) + 2e- -> 2I-(aq) + S4O6^2-

Overall: 2S2O3^2- + I2(aq) -> 2I-(aq) + S4O6^2-(aq)

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5
Q

What is a voltaic cell

A

A type of electrochemical cell that converts chemical energy into electrical energy

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6
Q

What are half-cells

A

Half cells contain chemical species present in a redox half-equation

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7
Q

How can you make a voltaic cell

A

By connecting together two different half cells which allows electrons to flow

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8
Q

What are the two types of half cells

A

Metal/ metal ion

Ion/ ion

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9
Q

How do you know which electrode has a greater tendency to gain or lose electrons

A

In a cell with two metal/metal ion half cells connected, the more reactive metal releases electrons more readily and is oxidised

Operating cell

  • electrode with more reactive metal loses electrons - is oxidised Operating cell- negative electrode
  • the electrode with the less rreactive metal gains electrons and is reduced - positive electrode
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10
Q

Define standard electrode potential

A

The tendency to be reduced and gain electrons
With standard conditions -
- solutions have a concentration of exactly 1 moldm-3
- temperature is 298K
- pressure is 100kPa (1bar)

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11
Q

How do you measure standard electrode potential

A

Half-cell connected to a standard hydrogen electrode
- the two electrodes are connected by a wire to allow a controlled flow of electrons

  • the two solutions are connected with a salt-bridge which allows ions to flow. The salt bridge typically contains a concentrated electrolyte solution that does not react with either solution
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12
Q

If an electrode potential is more negative:

A
  • the greater the tendency to lose electrons and undergo oxidation
  • the less the tendency to gain electrons and undergo reduction
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13
Q

The more positive the electrode potential:

A
  • the greater the tendency to gain electrons and undergo reduction
  • the less the tendency to lose electrons and undergo oxidation
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14
Q

How do you calculate standard cell potential from standard electrode potentials

A

Cell potential = positive electrode potential - negative electrode potential

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15
Q

How do you construct overall equations from half equations

A

The redox system with more positive electrode potential will react from left to right - gain electrons

System with more negative will react from right to left - lose electrons

Reduction half equation is same way around
Oxidation half equation is reversed

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16
Q

What effect does cis-platin have on bacteria

A

Binds with DNA and stops replication

17
Q

What angle do two identical ligands need to be a trans-isomer

A

180 degrees

18
Q

Define ligand substitution

A

When a ligand in a complex ion is replaced with another ligand

19
Q

What ligand substitutions do we need to know

A

[Cu(HO)6]2+ with NH3

[Cu(H2O)6]2+ with HCl

[Cr(H2O)6]3+ with NH3

20
Q

Cu2+ ammonia reaction

A

Copper sulfate forms pale blue octahedral complex ion [Cu(H2O)6]2+

Ammonia is acting as a base and forms the pale blue precipitate

21
Q

What is the overall equation for Cu2+ ammonia reaction

A

[Cu(H2O)6]2+ + 4 NHH3 —> [Cu(NH3)4(H2O)2]22+. + 4 H2O

22
Q

What is the result of the Cu2+ chloride reaction

A

Yellow [CuCl4]2- complex ion forms

Chlorides are larger than H2O so can fit around the Cu2+

The solution appears green when there is an equal amount of each complex ion (yellow and blue)

23
Q

What is the Cu2+ chloride reaction equation

A

[Cu(H2O)6]2+ + 4 Cl- <—> [CuCl4]2- + 6 H2O

24
Q

Results for the Cr3+ ammonia reaction
What happens when you add excess ammonia

A

Grey green precipitate of Cr(OH)3] + 3NH4+

Excess ammonia dissolves the precipitate to form the dark purple complex ion [Cr(NH3)6]3+

25
Equation for the Cr3+ ammonia reaction
[Cr(H2O)6]3+ + 6 NH3 —> [Cr(NH3)6]3+ + 6 H2O
26
Colour change when Cu2+ is mixed with NaOH or NH3
Starts blue Forms blue ppt. Dissolves in excess NH3
27
Colour change when Fe3+ is mixed with NaOH or NH3
Starting colour = pale green Changes to green ppt.
28
What colour change occurs when Fe3+ is mixed with NaOH or NH3
Starting colour = pale yellow Orange-brown ppt.
29
What is the colour change when Mn2+ is mixed with NaOH or NH3
Starting colour = pale pink Changes to light brown ppt.
30
Colour change when Cr3+ is mixed with NaOH and NH3 What happens in excess NaOH or NH3
Starting colour = violet Changes to grey green Excess NaOH = soluble (dark green) Excess NH3 = soluble (purple)
31
Reaction and colour change for [Cu(H2O)6]2+ with dilute NH3
[Cu(H2O)6]2+ + 2 NH3 <—> [Cu(H2O)4(OH)2] + 2NH4+ Colour change from blue to blue ppt
32
Explain the importance of iron in haemoglobin
Is a transition metal so has 4 dative bonds with nitrogen atoms in the Haem group, a fifth to a nitrogen on the protein and a sixth with a water molecule Carbon monoxide can substitute the water molecule in haemoglobin to form carboxyhaemoglobin The CO bond with Fe2+ is much greater than that of O2 and so can’t be removed