RAPHEX IV Flashcards
what is responsible for nuc med imaging with 99mTc?
gamma rays
which of the following is true? I-131 and I-125 have…
a. have different chemical properties
b. have different Z values
c. have the same number of neutrons
d. none of the above
none of the above
chemically, all isotopes are identical. Isotopes have the same Z but different number of neutrons (and hence mass number)
there are 2 of these in a tritium nucleus
neutrons
H-3 has one proton and 2 neutrons
which of the following does NOT occur when a linac is changed from xray mode to electron mode?
a. target is removed
b. scattering foil placed in beam
c. monitor chamber is removed
d. electron applicator attached
e. beam current decreases
c monitor chamber remains
what is predominant reaction by which fast neutrons dissipate energy in tissue?
elastic collisions with H nuclei in tissue
Compton photon is backscattered at min energy, what angle is electron emitted relative to direction of initial photon?
photon at 180 degrees, electron at 0 degrees
dmax is approx equal to…
-d where kerma and dose are equal
-max range of secondary electrons
-depth at which CPE occurs
to convert R to mGy, factor for diagnostic xrays and muscle tissues is closest to?
-0.1
-5
-9
-2
-90
0.876 cGy/R = 8.76 mGy/R therefore 9
per TG51, do electron beams have to be calibrated with chambers having a electron calibration factor from NRC?
no, can be cross-calibrated with a NRC calibrated chamber
dose beyond dense bone in 6 MV beam, compared to that calculated without heterogeneity correction
6 % less
ie. 2%/cm
also bone density is 1.6X water; therefore 3 c bone is additional 1.8 cm of tissue
attenuation of 6 MV beam is 3.5%/cm
dmax of 6 MeV electrons
1.2 cm
patient with 10 MV POP fields, 20x20cm2, 100 cm SAD. 4500 cGy in 25 fractions. AP thickness is 26 cm. What is total dose per fx at dmax?
a. 162
b. 175
c. 180
d. 194
e. 216
total dose at dmax must be greater than midplane dose
For 10 MV xrays d is only reasonable answer./ (separation of 34 cm would be needed for 20% higher)
PDD for 10 MV at 10 cm depth is around 73%; 180/2 / 0.73 = 123 cGy (for one beam)
PDD for 20 cm is 0.46, 123 * 0.46 = 56 cGy
123 + 56 cGy = 179 cGy
d is reasonable
changing POPs from 100 cm SAD to 100 cm SSD while treating to the same Rx dose at patient midline would cause which of the following changes in MU and total dose at dmax?
As Rx moves farther away, MU must increase. Increasing SSD increases the PDD; therefore total dose at dmax is slightly smaller
all of the following statements are true for breast tangents with wedges expect:
a. wedges can reduce hot spot at apex
b.contralateral intact breast will receive less dose compared with open-field treatment because the wedge will block scatter dose from the gantry head
c.dynamic wedges do not harden the beam
d. dose scattered to the contra breast is less for dynamic wedges than for conventional wedges
b
although the wedge blocks some scatter from the tx head, the wedge produces low energy scatter so the contra breast recieves more dose
all of the following are true regarding dynamic wedges except
a. the wedge effect is created by closing one collimator jaw during irradiation
b.the field length in the non-wedged direction cab ne equal to the max collimator setting
c.the depth dose on the beam axis is the same as that of an open beam
d.for a wedge in the y direction, one of the collimators cannot be set to 0
d
a 10x10 photon beam is used to deliver 100 cGy at 100 cm depth. If a 2x2 cm central block with 5% narrow beam transmission is used to protect a crticial organ, what happens to the dose on the central axis at the same depth?
it is greater than 5 cGy due to scatter from surrounding tissue
electron field size required to treat a volume with a 5 cm width at treatment depth
7 cm- need 1 cm on either side
boost with 16 MeV electrons with 3 cm diameter cut-out in 6x6cm cone. Field must be treated at 115 cm SSD to avoid shoulder/ All the following are true except:
1. electron output (cGy/MU) is reduced compared to 6x6cm cone
2.penumbra width will increase, compared to that at 100 cm SSD
3.depth of the 90% isodose will be less than that of open 6x6 cm cone
4.output at 115 cm SSD will be (100/115)^2 times that at 100 cm SSD
d
for electrons, output can be corrected by IS law only when virtual SSD is used. Have to measure output for the actual cut-out and SSD to be used