Quiz 6 Flashcards
globular
soluble
fibrous
insoluble
primary level
sequence, covalent connection
secondary level
local structures, H bonds
tertiary level
overall 3D shape, all weak forces
quaternary level
subunit organization for multiple polypeptide chains
2,3,4 structures of proteins are formed and stabilized by
weak forces
how are the 2,3,4 structures of protein stabilized?
- hydrophobic bonds are formed wherever possible [directional]
- hydrophobic interactions drive protein folding [water entropy]
- ionic interactions are abundant on protein surfaces [opposite charges]
- van der Waals interactions are everything [best packing]
the tertiary structure or
fold of a protein
constraints in secondary structure
the planar character of the peptide group limits the conformational flexibility of the polypeptide chain
the alpha helix and the beta sheet allow
the polypeptide chain to adopt favorable phi and psi angles and to form hydrogen bonds
fibrous proteins
contain long stretches of regular secondary structure, such as the closed coils in a keratin and the stacked b sheets in b keratin
all peptide structure is based on the
amide plane
phi is the rotation angle around the
Ca-NH bond
psi is the rotation angle around the
Ca-CO bond
due to steric hinderance
some phi and psi angles are forbidden
G.N ramachandran
was the first to demonstrate the value of plotting phi, psi combinations from known protein structures
the entire path of the peptide backbone is know if
all phi and psi angles are specified
ramachandran plot
shows sterically allowed values for the angles phi and psi
conformation
changing shape without breaking a bond
configuration
requires breaking of a bond
secondary structures are the local backbone structures that are stabilized by
hydrogen bonds
- a helices
- b sheet
- b turns
the a helix
- stabilized by h bonds between backbone C=O and H-N groups
- because of amino acid chirality, the a helix has a right handed twist
H bonds between the amide carbonyl group of
Cai and the amide nitrogen [H] of Cai+4
pitch includes
3.6 residues[one turn], and at a 1.5A rise per amino acid residue, is equal to 5.4 A high
the a helix continued
- right handed twist
- residues per turn: 3.6
- rise per residue: 1.5A
- rise per turn, “pitch”: 3.6 x 1.5A = 5.4A
- h bonds between the amide carbonyl group and the amide nitrogen H
based on allowed phi-psi angles,
prolines angles are too restrictive
glycines angles are too permissive, flexible
B pleated sheets are composed of
B strands
antiparallel strands are connected by
a short turn
parallel strands are connected by
a longer loop
parallel b sheets are
less stable, bc they have imperfect H bond angles therefore >5 strands are requires
antiparallel b sheets
have straight short H bond, making them more stable. therefore <5 strands are required to form a sheet
the b turn or reverse turn
- allows the peptide chain to reverse reaction
- proline and glycine are prevalent in b turns
- carbonyl c of one residue is H bonded to the amide proton of a residue three residues away : C=O of a1 bonds with H-N of a4
fibrous proteins are usually
- insoluble[hair doesn’t dissolve in water]
they play a structural role in nature
3 types of fibrous proteins are discussed here
- a keratin
- b keratin
- collagen
a keratin
- a fibrous protein found in hair, fingernails, claws, horns and beaks.
- heptad repeat[7]: (a-b-c-d-e-f-g)n , where a and d are non polar, and b, c, e, f, and g are polar amino acid residues
- this primary structure promotes association of a helices to form coiled coils