proteins Flashcards

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1
Q

Describe the general structure of an amino acid

A
  • Contains a COOH group
  • Contains an R variable group
  • Contains an NH2 amino group
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2
Q

Describe a method to test for proteins in a sample

A
  1. Add equal volumes of dilute sodium hydroxide (NaOH) to a sample at room temperature
  2. Add drops of dilute copper (II) sulfate solution (CuSO4), swirl to mix
  3. A negative result = solution remains blue, a positive result is when the colour changes from blue to purple
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3
Q

How many amino acids are there and how do these differ from each other

A

20

differ by side ‘R’ group

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4
Q

Explain how do dipeptides and polypeptides form?

A
  • Condensation reaction forms a peptide bond between (-CONH-) and eliminates a molecule of water
  • Dipeptides are formed from 2 amino acids
  • Polypeptides are formed from 3 or more amino acids
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5
Q

How many levels of protein structure are there

A

4

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6
Q

Describe the primary structure of a protein

A
  • Sequence, number and type of amino acids in the polypeptide
  • Determined by a sequence of codons on mRNA
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7
Q

Describe the secondary structure of a protein

A
  • Hydrogen bonds form between negatively charged nitrogen, oxygen and positively charged hydrogen
  • Causes polypeptide chain to fold into an alpha helix or a beta pleated sheet
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8
Q

Describe the tertiary structure of a protein

A
  • 3D structure formed by further folding of polypeptide due to: disulfide bridges, ionic bonds or hydrogen bonds
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9
Q

Describe disulphide bridges in the tertiary structure of proteins

A

Strong covalent S-S bonds between molecules of amino acid cysteine

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10
Q

Describe ionic bonds in the tertiary structure of proteins

A

Strong bonds between charged R groups

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11
Q

Describe hydrogen bonds in the tertiary structure of proteins

A

Numerous and easily broken

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12
Q

Describe the quaternary structure of a protein

A
  • Forms when there is more than one polypeptide chain
  • Held together by disulphide bridges, hydrogen bonds or ionic bonds to form an alpha helix and a beta-pleated sheet
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13
Q

Describe the structure and function of globular protein

A
  • Spherical and compact
  • Hydrophilic R groups face outwards and hydrophobic R groups face inwards so are water soluble
  • Involved in metabolic processes
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14
Q

Describe the structure and function of fibrous protein

A
  • Can form long chains or fibres
  • Insoluble in water
  • Useful for structure and support
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15
Q

Define enzymes

A

Biological catalysts for intra and extracellular reactions

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16
Q

What determines the shape of an enzyme active site

A

The tertirary structure

17
Q

How is the activation energy of metabolic reactions lowered

A

The formation fo enzyme-substrate complexes lowers the activation energy of metabolic reactions

18
Q

Explain the induced fit model of enzyme action

A
  • The enzyme active site isn’t completely complementary to the substrate
  • Active site shape changes as substrate binds and enzymes-substrate complex forms in an ideal binding agreement
  • This stresses/distorts the bonds in the substrate which maximises the ability of the enzyme to catalyse the reaction
19
Q

Explain the lock and key model of enzyme action

A
  • The active site is a rigid, fixed shape
  • The active site is completely complementary to 1 substrate
  • After a collision, enzyme-substrate complex forms leading to a reaction.
20
Q

Name 5 factors that affect the rate of enzyme-controlled reactions

A
  1. Enzyme concentration
  2. Substrate concentration
  3. Concentration of inhibitors
  4. pH
  5. Temperature
21
Q

How does substrate concentration affect the rate of an enzyme-controlled reaction?

A
  • As the number of substrate molecules increases, the likelihood of enzyme-substrate complex formation increases
  • If the enzyme concentration remains fixed but the amount of substrate is increased, all active sites will become saturated and the substrate concentration will not increase the reaction rate
  • When the active sites of enzymes are all saturated, any substrate molecules that are added will have nowhere to bind in order to form an enzyme-substrate complex
22
Q

How does enzyme concentration affect the rate of an enzyme-controlled reaction?

A
  • The higher the enzyme concentration in a reaction mixture, the greater the number of active sites available and the greater the likelihood of enzyme-substrate complex formation
23
Q

How does a low temperature affect the rate of enzyme-controlled reactions

A
  • Molecules move relatively slow and lower the frequency of successful collisions between substrates
  • There are less frequent enzyme-substrate complex formations.
  • Substrate and enzymes collide with less energy, making it less likely for bonds to be formed or broken which stops the reaction from occurring.
24
Q

How does a high temperature affect the rate of enzyme-controlled reaction

A
  • Molecules move more quickly and there is a higher frequency of successful collisions between substrate molecules and the active site of enzymes. There are more frequent enzyme-substrate complex formations.
  • Substrate and enzyme collide with more energy, making it more likely for bonds to be formed or broken which allows the reaction to occur.
25
Q

How does pH affect the rate of enzyme-controlled reaction

A
  • Enzymes are denatured at extremes of pH.
  • The hydrogen and ionic bonds that hold the tertiary structure of the protein together can break
  • Altering the shape of the active site so enzyme-substrate complexes form less easily
26
Q

Compare competitive and non-competitive inhibitors

A
  • Competitive inhibitors have a similar shape to the substrate so bind to the active site, non-competitive inhibitors bind at the allosteric binding site
  • Competitive inhibitors do not stop reactions, enzyme-substrate complexes form when an inhibitor is released, and non-competitive stop reactions because they trigger to change in shape
  • Competitive inhibitors = increasing substrate concentration decreases their effect, non-competitive inhibitors = increasing substrate concentration has no impact on their effect
27
Q

How can you reduce the effect of the competitive inhibitor?

A

Increasing substrate concentration reduces the effect of the inhibitor as the level of inhibition is dependent on relative concentrations.

28
Q

Why are enzymes specific?

A
  • The shape of the active site (and its specificity) is determined by the ternary structure of the protein that makes up the enzymes