Practice Quiz-Lecture 6 Flashcards
Continuous variables can be summarized using
mean and standard deviation
P-value is
Probability of getting the observed absolute test statistic or something more extreme under the null hypothesis
A bivariate association examines
The relationship between two variables
A critical value corresponding to type I error alpha is
The percentile of a (standard normal or t) distribution such that the area under the distribution outside the critical value is equal to alpha
In the quinoa example given in slides 7 and 8 of your video, each individual provides 2 measurements
True
To compare blood pressure in the morning versus evening, I would use a paired t test
True
Given sample size n, the distribution and degrees of freedom of a paired t test statistic are
t distribution, n-1 degrees of freedom
In the computer output for the Quinoa example in slide 14, the value of the test statistic is
3.596
In the computer output for the Quinoa example in slide 14, the p-value is
0.001
Based on the p-value in slide 14, you will reject the null hypothesis at type I error of alpha
True
For the problem corresponding to the computer output given in slide 14, diet is a
categorical variable
For the probem corresponding to the computer output given in slide 30, blood sugar level is a
continuous variable
When performing a two group (or independent group) t test, the distribution of the test statistic has a
t distribution
For the example given in slide 31, the value of the test statistic is
3.519
For the example, when comparing the average blood sugar level in quinoa versus salmon diet group, the p-value is
0.001