Physics Midterm Flashcards
Boyle’s Law
P1V1 = P2V2
Charles’ (Gay Lussac) Law
(V1/T1) = V2/T2
Don’s Law (3rd Gas Law)
P1/T1 = P2/T2
Ideal Gas Law
PV = nRT
STP (standard temp & pressure)
T = 273 K , 0* C
P = 760 mm Hg
RTP (room temp & pressure)
T = 293 K , 20* C
P = 760 mm Hg
BTP (body temp & pressure)
T = 310 K , 37* C
P= 760 mm Hg
Dalton’s Law of Partial Pressure
P(total) = P1 + P2
Therefore, (V(total) / P(total)) = v1/p1 = v2/p2
so, V2/V1 = P2/P1 (or the ratio of partial pressures of volume and partial volume is equal to ratio of total volume and pressure)
Dalton’s Law Example
20.93 kPa O2 + 79.07 kPa N2
100 kPa total
(20.93 % O2 and 79.07% N2)
Amount of O2 L in E cylinder
660 L
PSIg of E cylinder of O2
1900-2000 psi(G)
Amount of N2O L in E cylinder
1600 L
PSIg of E cylinder of N2O
745 psig
van der Waals forces?
(p + (n^2 x a) / V^2) ) (V - nb) = nRT
Water vapor pressure at BTP (37* C)
47 mm Hg
6.3 kPa
Avogadro’s Number
1 mol = 6.02214 x 10^23 molecules
1 mol at STP
22.4 L
1 mol at RTP
24.0 L
1 mol at BTP
25.4 L
Alveolar Oxygen Equation R Value
0.8
Partial pressure of O2 in lungs at room air
Pa O2 = 100 mm Hg
Partial pressure of O2 in lungs on 50% O2
Pa O2 = 300 mm Hg
Partial pressure of O2 in lungs on 100% O2
Pa O2 = 660 mm Hg
V-Q Mismatch in most patients
10%
(10-20%)
Common Pressure Units
1 bar = 1 atm = 14.7 psi = 101.33 kPa = 760 mm Hg
Critical Temperature
Temperature above which liquidification cannot occur however much much pressure is applied
(maximum temp at which liquid can be found)