Past edta Mock Calculations Questions Flashcards
In the experiment it was found that 100cm3 portions of the water sample required an average titre of 7.8cm3 of 0.010M edta reagent solution.
Calculate the number of grams of the disodium salt of edta needed to make 250cm3 of a 0.010M solution
Mr=336
In the experiment it was found that 100cm3 portions of the water sample required an average titre of 7.8cm3 of 0.010M edta reagent solution.
Calculate the number of moles in the 7.8cm3 of the edta reagent solution
3.36 g to make one litre
In the experiment it was found that 100cm3 portions of the water sample required an average titre of 7.8cm3 of 0.010M edta reagent solution.
Calculate the number of moles of calcium and magnesium ions (Mn2+) in the 100cm3 portion of water
0.84g to make 250cm3 of 0.001
In the experiment it was found that 100cm3 portions of the water sample required an average titre of 7.8cm3 of 0.010M edta reagent solution.
Calculate the grams per litre expressed in terms of CaCO3
7.8cm3 = 0.01 x 7.8 / 1000
= 0.000078g
In the experiment it was found that 100cm3 portions of the water sample required an average titre of 7.8cm3 of 0.010M edta reagent solution.
Calculate the ppm in terms of CaCO3
100 cm3 = 0.000078g moles of Ca2+
- 00078 x 100 = 0.078g/L
- 078 x 1000 = 7.8 p.p.m
In the experiment it was found that 100cm3 portions of the water sample required an average titre of 9.2cm3 of 0.010M edta reagent solution.
Calculate the total hardness in the sample in moles per litre
100 x X = 9.2 x 0.01
Therefore x = 0.00092
In the experiment it was found that 100cm3 portions of the water sample required an average titre of 9.2cm3 of 0.010M edta reagent solution.
Calculate the total hardness in the sample in grams per litre expressed in terms of CaCO3
0.00092 x 100 = 0.092
In the experiment it was found that 100cm3 portions of the water sample required an average titre of 9.2cm3 of 0.010M edta reagent solution.
Calculate the total hardness in the sample in p.p.m expressed in terms of CaCO3
0.092 x 1000 = 92
