B.O.D - Process Flashcards

1
Q

What is the name given to the method used to measure the amount of dissolved oxygen in a sample of water?

A

The Winkler Method

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2
Q

What is the Winkler Method

4

A

The collecting of a sample of water in a bottle

Stoppering the bottle

Ensuring no air is present in the bottle when collecting the water

i.e. the bottle must be completely filled to the top

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3
Q

Why is it important that no air is present in the bottle when collecting the water sample?

A

As this would raise the oxygen level and would give an incorrect result

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4
Q

What is added to the water?

3

A

Manganese (ii) sulfate solution

MnSO4

Alkaline potassium iodide solution (NaOH and KI)

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5
Q

What do the Mn2+ ions and the OH- ions from the alkali form when they react together?

A

They form a white precipitate of manganese (II) hydroxide

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6
Q

What is manganese (II) hydroxide?

A

A white precipitate formed when the Mn2+ ions and the OH- ions from the alkali react together

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7
Q

What does manganese (II) hydroxide react with to form a brown participate?

A

The dissolved oxygen in the water

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8
Q

What is formed when manganese (II) hydroxide reacts with dissolved oxygen in water?

A

A brown participate

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9
Q

What does it indicate if the the manganese (II) hydroxide does not turn brown in the water?

A

This indicates there is no oxygen present

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10
Q

What is added to the water after it has turned brown?

A

A small quantity of concentrated sulfuric acid is then added to the bottle

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11
Q

What happens when the sulfuric acid is added to the water?

A

The iodide ions from the alkaline potassium iodide (KI)react with the manganese hydroxide to liberate iodine

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12
Q

What colour change occurs when the sulfuric acid is added to the water?

A

Brown to red-brown colour of iodine

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13
Q

How is the amount of iodine present determined?

A

By titrating the water against a standard sodium thiosulfate solution

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14
Q

Why is the Winkler method not used for chlorinated water?

A

As chlorine, an oxidising agent, would react with the iodide ions of the potassium iodide to liberate iodine

Which would result in ‘extra; iodine which would give the titration figure a higher than true value

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