Module 5.3 - Transitions Metals Flashcards
What happens in the reaction of aqueous Cu2+ ions and sodium hydroxide (and in excess)?
Blue solution to blue gelatinous precipitate
[Cu(H2O)6]2+(aq) + 2OH-(aq) –> [Cu(OH)2(H2O)4](s) + 2H2O(l)
no change in excess sodium hydroxide
What happens in the reaction between aqueous Cu2+ ions and ammonia (and in excess)?
Blue gelatinous precipitate formed that re-dissolves when excess ammonia to a dark blue solution
[Cu(H2O)6]2+(aq) + 2NH3(aq) –> [Cu(OH)2(H2O)4](s) + 2NH4+(aq)
In excess ammonia (forms a dark blue solution)
forms [Cu(NH3)4(H2O)2]2+
What happens in the reaction between aqueous Fe2+ ions and sodium hydroxide (and in excess)?
Pale green solution containing Fe2+(aq) forms a green ppt, turning rusty brown at its surface on standing in air (as oxidised to Fe3+)
Fe2+(aq) + 2OH-(aq) –> Fe(OH)2(s)
No change when excess NaOH added
What happens in the reaction between aqueous Fe2+ ions and ammonia (and in excess)?
Dark green ppt formed
[Fe(H2O)6]2+(aq) + 2NH3(aq) –> [Fe(OH)2(H2O)4](s) + 2NH4+(aq)
No change when excess NH3 added
What happens in the reaction between aqueous Fe3+ ions and sodium hydroxide (and in excess)?
Pale yellow solution containing Fe3+(aq) forms a rusty prown ppt - iron(III) hydroxide
Fe3+(aq) + 3OH-(aq) –> Fe(OH)3(s)
No change when excess NaOH added
What happens in the reaction between aqueous Fe3+ ions and ammonia (and in excess)?
Rusty brown ppt formed from a yellow solution
[Fe(H2O)6]3+(aq) + 3NH3(aq) –> [Fe(OH)3(H2O)3](s) + 3NH4+
No change when excess NH3 added
What happens in the reaction between aqueous Mn2+ ions and sodium hydroxide (and in excess)?
Pale pink solution –> brown ppt forms which darkens in air as it oxidises
[Mn(H2O)6]2+(aq) + 2OH-(aq) –> [Mn(OH)2(H2O)4](s) + 2H2O(l)
Mn ion can be summarised to Mn(OH)2. Oxidation can be summaries by:
4Mn(OH)2 + O2 –> 2Mn2O3 + 4H2O
No change when excess NaOH added
What happens in the reaction between aqueous Mn2+ ions and ammonia (and in excess)?
Pale pink –> brown ppt forms, which darkens in air as it oxidises
[Mn(H2O)6]2+(aq) + 2NH3(aq) –> [Mn(OH)2(H2O)4](s) + 2NH4+(aq)
No change when excess NH3 added
What happens in the reaction between aqueous Cr3+ ions and sodium hydroxide (and in excess)?
Violet solution (can appear green from impurities)–> green ppt forms, which re-dissolves in excess hydroxide
[Cr(H2O)6]3+(aq) + 3OH-(aq) –> [Cr(OH)3(H2O)3](s) + 3H2O
In excess (forming a dark green solution):
[Cr(OH)3(H2O)3](s) + 3OH-(aq) –> [Cr(OH)6]3- + 3H2O
What happens in the reaction between aqueous Cr3+ ions and ammonia (and in excess)?
Violet solution –> green ppt forms, which re-dissolves if excess ammonia added
[Cr(H2O)6]3+(aq) + 3NH3(aq) –> [Cr(OH)3(H2O)3](s) + 3NH4+(aq)
In excess (forming a purple solution):
[Cr(OH)3(H2O)](s) + 6NH3(aq) –> [Cr(NH3)6]3+ + 3H2O + 3OH-(aq)
Explain the reaction of aqueous copper(II) ions and ammonia.
-contains [Cu(H2O)6]2+ complex ions which have a characteristic pale blue colour
-when NH3(aq) added, pale blue changes + deep blue solution formes
[Cu(H2O)6]2+(aq) + 4NH3(aq) ⇌ [Cu(NH3)4(H2O)2]2+(aq) + 4H2O(l)
-4 H2O ligands replaced by 4 NH3 ligands
-product has 6 ligands so octahedral shape
-Cu-O longer than Cu-N so product has distorted octahedral shape
-2 changes observed in lab: on addition of small amount of NH3, pale blue ppt of copper(II) hydroxide forms as ammonia acts as alkali. When NH3 put into water forms NH4OH, which can partially ionise, releasing OH-
-on excess of NH3, pale blue ppt dissolves + deep blue solution formed containing [Cu(NH3)4(H2O)2]2+ ions
Explain the reaction of copper(II) ions and hydrochloric acid.
-when conc HCl added to Cu2+(aq), pale blue solution initially forms green solution before finally turning yellow
-reaction exists in equilibrium + can be reversed by addition water to yellow solution to return to original blue colour
[Cu(H2O)6]2+(aq) + 4Cl- ⇌ [CuCl4]2+(aq) + 6H2O(l)
pale blue solution ⇌ yellow solution
-Cl ligands have stronger repulsions than water so fewer Cl fit around central metal ion
-goes from octahedral shape to tetrahedral shape
-can apply Le Chatelier’s principle as in equilibrium
What is a transition element?
A d-block element that has at least one ion with an incomplete d sub shell
Which d-block elements are not transition elements and why?
- scandium: only forms Sc3+, where the d sub shell is empty
- zinc: only forms Zn2+, where d sub shell is full
Which 2 transition metals don’t fit the trend of electron configuration and why?
- chromium: 5 3d orbitals + 4s orbital all have 1 electron in, with none being full
- copper: 3d orbitals are full, but there’s only 1 electron in the 4s orbital
- in both, this electron arrangement means electron repulsion between outer electrons is minimised causing increased stability of the ions
What is the electron configuration of scandium?
1s22s22p63s23p64s23d1
What is the electron configuration of titanium?
1s22s22p63s23p64s23d2
What is the electron configuration of vanadium?
1s22s22p63s23p64s23d3
What is the electron configuration of chromium?
1s22s22p63s23p64s13d5
What is the electron configuration of manganese?
1s22s22p63s23p64s23d5
What is the electron configuration of iron?
1s22s22p63s23p64s23d6
What is the electron configuration of cobalt?
1s22s22p63s23p64s23d7
What is the electron configuration of nickel?
1s22s32p63s23p64s23d8