Module 5: Solutions

Question 1

solubility of one substance in another depends on:

Answer 1

1. intermolecular forces (like dissolves like)
2. tendency to mix

Question 2

saturated solution

Answer 2

a solution in which the solvent holds the max amount of solute dissolved

Question 3

unsaturated solution

Answer 3

a solution in which the solvent holds less than the maximum amount of solute dissolved

Question 4

supersaturated

Answer 4

a solution in which the solvent holds more than the maximum amount of solute dissolved

Question 5

kilo-

Answer 5

1x10³
1000

ex) 1kg = 1000g

Question 6

centi-

Answer 6

1x10^-2
or 100

ex) 1g = 100cg
ex) 1cm = 1x10^-2m
ex) 1m = 100cm

Question 7

deci-

Answer 7

1x10^-1
or 10

ex) 1g = 10dg

Question 8

milli-

Answer 8

1x10^-3
or 1/1000

ex) 1mg = .001g
ex) 1g = .001mg (1/1000mg)

Question 9

micro-

Answer 9

1x10^-6
or
1/100,000

ex) 1g = 1,000,000mcg
ex) 1mcg = 0.0000001g

Question 10

nano-

Answer 10

1x10^-9
or 1/1,000,000,000
ex) 1ng = 0.0000000001g
ex) 1g = 1,000,000,000ng

Question 11

(w/w)

Answer 11

weight-weight
(% becomes the mass)/(100g)
assume 100g

ex) 0.9% saline solution = 0.9g/100g

Question 12

(v/v)

Answer 12

volume-volume
(% becomes ml)/(100ml)
assume 100ml

ex) 85% aqueous ethanol = 85ml/100ml

Question 13

(w/v)

Answer 13

weight-volume
(% becomes mass)/(100ml)
assume 100ml

ex) 5% (w/v) = 5g/100ml