Lecture 8 Chapter 6 & 7 Protein Function Enzymes Flashcards
The velocity of a reaction is the quantity of the:
a. reactant that appears in a specified unit of time.
b. product that disappears in a specified unit of time.
c. solution color that disappears in a specified unit of time.
d. reactant that disappears in a specified unit of time.
e. solution color that appears in a specified unit of time.
d. reactant that disappears in a specified unit of time.
What is the reaction order if the reaction rate was doubled by doubling the reactant concentration?
a. zero order
b. first order
c. second order
d. pseudo-first order
e. pseudo-second order
b. first order
What is the reaction order if the reaction rate was increased by a factor of 4 by doubling the reactant
concentration?
a. zero order
b. first order
c. second order
d. pseudo-first order
e. pseudo-second order
c. second order
Which rate equation is TRUE if doubling the concentration of reactant A doubles the reaction rate and
doubling the concentration of reactant B has no effect on the rate?
a. V = k[A]
b. V = k[A][B]
c. V = k[A]2[B]1
d. V = k[A]2[B]
e. V = k[A]2
a. V = k[A]
Which statement about pseudo-first order reactions is FALSE?
a. Bimolecular reactions can be pseudo-first-order reactions.
b. The reaction rate will not appear to depend on the concentration of reactant A, whose concentration
greatly exceeds that of reactant B.
c. The reaction has a pseudo-first order if the concentration of one reactant greatly exceeds that of the
second one and if the second reactant is present at low concentrations.
d. The reaction rate will not appear to depend on the concentration of reactant A, whose concentration is significantly less than that of reactant B.
e. Unimolecular reactions cannot be pseudo-first-order reactions.
d. The reaction rate will not appear to depend on the concentration of reactant A, whose concentration is significantly less than that of reactant B.
Choose the CORRECT statement concerning the reaction order.
a. First-order rate constants have units M–1 s–1.
b. Biochemical reactions cannot have a zero order.
c. Bimolecular reactions are always second-order reactions.
d. Second-order reactions are usually unimolecular.
e. First-order rate constants have unit s–1.
e. First-order rate constants have unit s–1.
Which statement about enzyme kinetics is TRUE?
a. Michaelis–Menten enzymes have sophisticated regulatory properties.
b. The kinetic description of enzymatic activity is required to understand the structure of enzymes.
c. The action of allosteric enzymes increases the metabolic chaos.
d. Allosteric enzymes allow the efficient integration of metabolism.
e. All enzymes obey Michaelis–Menten kinetics.
d. Allosteric enzymes allow the efficient integration of metabolism.
Which characteristics are usually the first ones to be determined when studying enzyme activity?
a. Vmax and KM
b. V0 and KM
c. Vmax and V0
d. [S] and KM
e. Vmax and k2
a. Vmax and KM
In the Michaelis–Menten model:
a. the reaction equilibrium is attained with time, and the change in the concentration of the product
allows measuring of the reaction rate.
b. a unique characteristic of the enzyme is investigated when the enzyme concentration is relatively
constant and the product formation is negligible.
c. enzyme concentration is relatively constant only near the end of the reaction, so only in the
beginning of the reaction can the velocity be measured precisely.
d. only in the beginning of the reaction, there is no net change in concentrations of S and P, so the
reaction velocity can be measured precisely.
e. the initial velocity depends on [S] only when the entire enzyme is bound to the substrate but the
product has not accumulated yet.
b. a unique characteristic of the enzyme is investigated when the enzyme concentration is relatively
constant and the product formation is negligible.
The Michaelis constant:
a. depends on the concentration of the enzyme.
b. displays the maximal rate of the reaction, when it is much less than the substrate concentration.
c. describes the properties of the enzyme.
d. displays the maximal rate of the reaction, when it is equal to the substrate concentration.
e. displays zero-order kinetics, when the it is equal to the substrate concentration.
b. displays the maximal rate of the reaction, when it is much less than the substrate concentration.
Which statement about Vmax is TRUE?
a. Vmax is independent of enzyme concentration.
b. For Michaelis–Menten enzymes, the maximal velocity is approached asymptotically.
c. Vmax can be attained only when half of the enzyme is bound to the substrate.
d. The reaction velocity is maximal when the concentration of the substrate equals KM.
e. The reaction velocity is half Vmax when the entire enzyme is bound to the substrate.
b. For Michaelis–Menten enzymes, the maximal velocity is approached asymptotically.
What is the consequence of a high KM value of an enzyme?
a. Moderate concentration of the substrate will be enough for maximal enzyme activity.
b. This enzyme has high maximal velocity.
c. The enzyme is present in a large concentration in the cell.
d. High concentration of the substrate should be reached for maximal enzyme activity.
e. The velocity will be directly proportional to the substrate concentration.
d. High concentration of the substrate should be reached for maximal enzyme activity.
How can the reciprocal plot of initial velocity NOT be applied?
a. When it is half the maximal speed, the substrate concentration equals KM.
b. It gives a way to define KM when it is plotted against the reciprocal of the substrate concentration.
c. When it is plotted against the reciprocal of the substrate concentration, it allows KM/Vmax to be
defined as a slope of the graph.
d. It allows definition of the reciprocal of the maximal velocity in a double-reciprocal plot.
e. It is part of the Lineweaver–Burk equation.
a. When it is half the maximal speed, the substrate concentration equals KM.
How can the turnover number of an enzyme be determined?
a. as Vmax
b. when the enzyme is fully saturated
c. as [E]T
d. when half of the enzyme is occupied with the substrate
e. by the initial velocity
b. when the enzyme is fully saturated
Calculate the turnover of an enzyme if the maximal velocity is 0.2 M sec–1 and the product concentration
after the reaction is 1 M.
a. 0.2 sec
b. 0.2 sec–1
c. 5 sec
d. 0.5 sec
e. 0.5 sec–1
b. 0.2 sec–1
An enzyme has specificity constant values of 1.0 × 103, 1.1 × 104, and 4.0 × 10–1 for compounds A, B, and
C, respectively. For which compound does the enzyme have a higher efficiency and why?
a. Compound C; a low kcat value accounts for the high and specific rate of catalysis, while a high KM
value lowers the required concentration of the compound.
b. Compound B; a high KM value accounts for the high and specific rate of catalysis, while a low kcat
value lowers the required concentration of the compound.
c. Compound A; higher kcat accounts for the high and specific rate of catalysis, while a low KM value
lowers the required concentration of the compound.
d. Compound C; the least amount of the compound is required to saturate the enzyme, while having the
highest rate of catalysis.
e. Compound B; the least amount of the compound is required to saturate the enzyme, while having the
highest rate of catalysis.
e. Compound B; the least amount of the compound is required to saturate the enzyme, while having the
highest rate of catalysis.
Which constant represents the nature of the enzyme–substrate interaction?
a. specificity constant
b. constant of the catalysis rate
c. Michaelis constant
d. rate constant k1
e. allosteric constant
c. Michaelis constant
The specificity constant does NOT depend on the rate constant for the:
a. formation of the ES complex (kcat).
b. dissociation of the ES complex (k–1).
c. formation of the product (k2).
d. formation of the ES complex (k1).
e. formation of the product (kcat).
a. formation of the ES complex (kcat).
KM of the cytosolic isomer of fumarase is equal to 5 μM, whereas KM of the mitochondrial isomer is equal
to 50 μM. What should the value of k2 be for a less active isomer of the enzyme to achieve kinetic perfection?
a. from 5 × 108 to 5 × 109
b. from 2 × 107 to 2 × 108
c. from 1 × 108 to 1 × 109
d. from 5 × 102 to 5 × 103
e. from 2 × 106 to 2 × 107
d. from 5 × 102 to 5 × 103
What is the ternary complex for the enzyme (E) that converts pyruvate to lactate using NADH as a
cosubstrate?
a. E (lactate) (NAD+)
b. E (NADH) (pyruvate)
c. E (pyruvate) (lactate)
d. E (NADH) (NAD+)
e. E (lactate) (NADH)
e. E (lactate) (NADH)
hat is the reaction class if all substrates must bind to the enzyme in an arranged manner before any
product is released?
a. random sequential
b. ping-pong
c. ordered sequential
d. second order
c. ordered sequential
An example of a reaction of the double-displacement class is the:
a. conversion of pyruvate and NADH to lactate and NAD+ by lactate dehydrogenase with formation of
a ternary complex.
b. conversion of creatine and ATP to phosphocreatine and ADP by creatine kinase with ATP being
released before both substrates bind the enzyme.
c. conversion of aspartate and α-ketoglutarate to oxaloacetate and glutamate with formation of a ternary
complex.
d. cleavage of a peptide bond by chymotrypsin with the formation of a substituted intermediate on a
serine residue.
e. isomerization of dihydroxyacetone phosphate to glyceraldehyde 3-phosphate.
d. cleavage of a peptide bond by chymotrypsin with the formation of a substituted intermediate on a
serine residue.
What is NOT a feature of allosteric enzymes?
a. Their activity can be modified by environmental signals.
b. They have a sigmoidal dependence of the reaction velocity on the substrate concentration.
c. Each allosteric enzyme is capable of conducting multiple reactions.
d. Their activity isn’t regulated by a threshold effect.
e. They depend on alterations in the quaternary structure.
d. Their activity isn’t regulated by a threshold effect.
Judging by the given scheme of two metabolic pathways where en denotes different enzymes, give the name
of interactions that regulate the function of these pathways in a coherent fashion.
a. K inhibits e1 and e10 while F inhibits e1, and I inhibits e10.
b. F and I inhibit e1 and e10, respectively, and stimulate e10 and e1, respectively, whereas K inhibits e1and e10.
c. F stimulates e10 and I stimulates e1 while K inhibits e1 and e10.
d. K stimulates e1 and e10 while F inhibits e1, and I inhibits e10.
e. F and I stimulate e1 and e10, respectively, and inhibit e10 and e1, respectively, whereas K inhibits e1
and e10.
b. F and I inhibit e1 and e10, respectively, and stimulate e10 and e1, respectively, whereas K inhibits e1and e10.