Lecture 4 Flashcards

1
Q

Why proteins as a catalyst?

A

Greater reaction specificity (chirality), capacity for regulation (inhibitors), higher reaction rates, and milder reaction conditions

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2
Q

Enzymes

A

catalytically active biological macromolecules. Provide an active site within which a given reaction can proceed more rapidly

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3
Q

Michaelis complex

A

the enzyme substrate complex.

v = ( vmax * [S] ) / (Km + [S])

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4
Q

Transition state

A

fleeting molecular moment in which events such as bond breakage/formation or change formation have proceeded to the point where decay to either substrate or product is equally likely.

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5
Q

T or F: Rate is dependent on the magnitude of the activation energy

A

True. The higher the activation energy, the slower the reaction. And enzymes can affect the activation energy.

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6
Q

Transition state and free energy change

A

a large negative free energy change favors product formation and vice versa

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7
Q

Rate limiting step

A

step with the highest activation energy

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8
Q

3 ways enzymes lower activation energy

A

rearrangement of covalent bonds during catalysis, organize reactive groups into close proximity, and stabilizing the transition state

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9
Q

3 types of proximity effect and speed in relation to each other

A

bimolecular reactions, unimolecular reactions flexible, and unimolecular reactions inflexible

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10
Q

k(cat)

A

turnover number - number of substrate molecules that one enzyme can convert per second

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11
Q

K(m)

A

Michaelis constant = disappearance of the substrate complex / formation of the substrate complex.
Thus lower Km, the greater the affinity.

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12
Q

Sequential mechanism

A

enzyme reaction occurring in random or ordered method of substrate binding.

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13
Q

Ping-pong mechanism

A

The enzyme gets modified by the first substrate, releasing the product, allowing the second substrate to come. Think phosphorylation.

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14
Q

3 types of enzyme inhibition

A

competitive, uncompetitive, noncompetitive (mixed)

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15
Q

Competitive inhibition

A

substrate and inhibitor compete for the binding site of the enzyme. intersect at y-axis. Km increases and Vmax stays the same.

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16
Q

Uncompetitive inhibition

A

inhibitor binds to the substrate complex. Substrate will cause a conformational change of the enzyme allowing the inhibitor to bind at an allosteric site. Parallel lines. Km is increased and Vmax decreases.

17
Q

Noncompetitive inhibition (mixed)

A

The inhibitor can bind to the enzyme first or the substrate can bind to the enzyme first. left of y-axis. Km stays the same and Vmax decreases

18
Q

Chymotrypsin

A

produced in pancreas. Cleaves peptide bond on the C-terminal side of the aromatic amino acids. does through hydrolysis. Adjacent amino acid can’t be Pro

19
Q

Catalytic triad

A

Serine 195, Histidine 57, Aspartic acid 102.

20
Q

3 important aspects of Chymotrypsin

A

Catalytic triad, hydrophobic pocket confers substrate specificity, and oxyanion hole present to stabilize the transition state

21
Q

Oxyanion hole

A

Serine and glycine will hydrogen bond to the oxyanion, stabilizing the transition state

22
Q

General base catalysis

A

proton extraction by a weak base. Typically via groups other than -OH from water

23
Q

Specific base catalysis

A

Proton extraction by a strong base. Typically via the -OH group from water.

24
Q

Enolase and its cofactors

A

dehydration key in glycolysis. 2 Magnesium ions which stabilize the oxyanion

25
Q

Enolase’s important residues

A

Lysine and glutamate

26
Q

Lysozyme

A

cleavage of the cell wall leads to lysis of bacteria. Cleaves the glycosidic bond through hydrolysis

27
Q

Lysozyme’s important residues

A

Glutamate and aspartic acid