Lecture 3 - Carnot Cycle Flashcards

1
Q

How is the SFEE written for boilers and condensers, and why?

A

DetlaQ = h2-h1

They do no work on the fluid

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2
Q

How is the simplified SFEE written for turbines and compressors, and why?

A

-DeltaW = (h2-h1)
Kinetic energy changes are negligible so neglected
Processes are adiabatic (no heat transfer)

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3
Q

What equation can be used on a perfect gas in a turbine or compressor?
(Give rearranged version too)

A

cp = (dh/dT)p
Can also be written as
h2-h1 = cp(T2-T1)

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4
Q

How is the SFEE written for nozzles and diffusers?

A

(0.5C2^2-0.5C1^2) = (h1-h2)

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5
Q

Why can’t kinetic energy be neglected in the SFEE for nozzles and diffusers?

A

In these devices they may become significant terms

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6
Q

Why does the Carnot cycle accept heat at one max temp and reject it at a fixed lower temp?

A

The larger the average temperature difference, the greater the efficiency of the cycle. This system maintains the highest difference.

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7
Q

Which components are involved in the Carnot cycle?

A

Pump, boiler, turbine, condenser

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8
Q

What is required for an ideal thermodynamic cycle in the Carnot cycle?

A

Reversible isothermal processes

Reversible adiabatic processes (compression and expansion) - ie isentropic process

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9
Q

How would an ideal thermodynamic cycle be achieved in the Carnot cycle?

A

Using a fluid which is a condensable vapour.

Isothermal processes carried out at constant pressure and temperature, working fluid changes state

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10
Q

On a T-s diagram,, what are

4-1, 1-2, 2-3, 3-4?

A

4-1: pump, isentropic
1-2: boiler, isothermal
2-3: turbine, isentropic
3-4: condenser, isothermal

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11
Q

Give the SFEE for all processes of the Carnot cycle

A

Boiler: Q1-2 = h2-h1
Turbine: W2-3 = h3-h2
Condenser: Q3-4 = h4-h3
Pump: W4-1 = h4-h1

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12
Q

What is represented by:

T, s, h, Q, W, cp, U?

A
T = Temperature
s = entropy 
h = enthalpy 
Q = heat transferred 
W = work transferred 
U = internal energy
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13
Q

How is an ideal component’s thermodynamic state designated?

A

By a prime (ie 1’ for position 1) next to the actual numerical value on the graph

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14
Q

How does entropy change in ideal vs non-ideal fluid processes?

A

Ideal: no change

Non-ideal: increases

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15
Q

The higher the value of X, the more efficient the cycle.

What is X?

A

The maximum temperature

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16
Q

What is the temperature at which heat is rejected from the cycle at governed by?

A

Atmospheric considerations, ie temp difference between working fluid and sink

17
Q

What is the maximum working temperature of the Carnot cycle governed by?

A

Strength of materials- must be able to withstand pressures

18
Q

Why can the Carnot cycle not make the best use of material limits?

A

To operate in the wet region, the temp is limited to critical temp, 374C, whereas the materials can withstand 550-600C.

19
Q

What are the problems with using a mixture of liquid and vapour?

A

Impossible to get pump that works on two phase fluid

Liquid droplets can damage turbine blades due to high speeds

20
Q

Draw a Ts diagram of a carnot cycle?

A

Square box

1) isothermal expansion
2) Adiabatic expansion
3) Isothermal Compression
4) Adiabatic Compression

21
Q

Draw a pressure volume diagram of a carnot cycle?

A

1) isothermal expansion
2) Adiabatic expansion
3) Isothermal Compression
4) Adiabatic Compression

22
Q

How can you determine the properties of the fluids at different points within the carnot cycle?

A

If on saturated line - either completely liquid or vapour

Isentropic process therefore entropy will be the same at inlet and outlet of turbine and at the inlet and outlet of pump

23
Q

How can the wetness/dryness fraction initially be determined?

A

by using the known entropy of the fluid and calculating with the saturated entropy of the liquid and steam at that pressure

24
Q

What is the net work output of the carnot cycle?

A

Energy out of turbine - energy into pump

h2 - h3) - (h1 - h4

25
Q

What is the efficiency of the carnot cycle?

A

Net work out/Heat in or simplified to

Thot - Tcold / Thot

26
Q

How are turbine and compressor efficiencies taken into account

A

for turbine - change in enthalpy * efficiency - get less work out
for compressor - change in enthalpy/efficiency - have to put more work in