Lecture 13

Question 1

Coefficient = ?

Answer 1

Moles of substance usually

Question 2

Mole ratio

Answer 2

Say you have 2 of X molecule and 1 of Y molecule. How many mols of X molecule can you get from 3 mols of Y molecule?

6 bc there is a 2:1 ratio.

3 mols Y x 2 mols what you want (X molecule) / 1 mol of what you have (2/1 the mole ration) = Total mols you can get for X molecule.

Question 3

1 mole = ?

Answer 3

molar mass in grams

Question 4

Moles to mass conversions

Answer 4

M1xV1=M2 x V2

Mol–>Mass–>Mol–>Mass

-Mass (g)/Molar mass g/mol= number of moles

-Moles x Molar Mass (g/mol) = Mass (g)

Question 5

Actual Yield=

Answer 5

Amt actually produced

Question 6

Theoretical yield=

Answer 6

amt that can be made

Question 7

Percent Yield=

Answer 7

Actual (g)/Theoretical (g) x 100% = %