Lec 55: Pharmacokinetics I Flashcards
Zero order kinetics
constant rate of absorption or elimination
-LINEAR, M=kt
- speed is constant, rate of absorptionis independent of concentration gradient
- transport mechanism is saturated
First order kinetics
- rate is proportional to the amount of drug still unabsorbed
- EXPONENTIAL, M= Mo(e)^(-kt)
- increase difference:increase speed
- [ ] is major determinant, gradient counts!
- not constant amount, constant fraction
order Applications: Drug Absorption/Drug Elimination
zero order elimination - duration of a therapeutically effective drug [] increases linearly with amount in body fluids
first order elimination - duration of a therapeutically effective drug [] increases as the log of the amount in the body fluids does
half life equation
half life = 0.693/ke
ke=rate constant of elimination
Volume of Distribution
-apparent Volume in which the drug is distributed (a concept, not a real number)
Vd=(mg drug in body)/([]in plasma mg/L)
- as plasma [] decreases, Vd increases
- can be much higher than the total body volume if drug is nonhomogenously distributed with high [] in extravasculartissues (plasma [ ] is low in this case)
Clearance
- expressed in L/hr or mL/min
- Volume of plasma cleared of drug
- CL is additive
CL=(rate of elimination in mg/hr)/([] drug in mg/L)
CL=(ke)(Vd)
half life=0.693Vd/CL
Bioavailability
-fraction of unchanged drug reaching systemic circulation after oral administation (F)
F=f(1-ER)
ER= extraction ration in liver
f=fraction absorbed from gut
Extent of absorption
ratio of drug entering blood circulation to total drug in digestive system
rate= extent *time
First Pass Elimination
presystemic hepatic elimination; passes through liver before system circulation and may be metabolized or excreted into bile
-drug is decreased by : QCi - QCo, where Q= 90 L/h hepatic blood flow and Ci=drug entering liver, and Co = drug leaving
Hepatic CL= Q*ER
***if ER is large, we can compensate for low oral bioavailability by 1) increasing dose and 2) use alternative administative routes
accumulation factor of a drug when the dosing interval is shorter than four half-live
accumulation factor = 1/(fraction lost in one dosing interval)
example: for a drug given once every half life, AF=2
Dosing Regimen Construction
- identify target [] that will produce desired effect - [] range between that causing ½ of greatest therapeutic effect (lower limit) and [] that will cause side effects in no more than 5-10% of all patients (uppe rlimit)
- determine Vd and CL
- maintenance dose
a. dosing rate = CL*Css , where Css= []at steady state - if intermittent doses are given, then maintenance dose is determined by:maintenance dose=dosing rate* dosing interval
- if target [] needs to be reached quick, and or elimination rate ke is small, loading doses might be applied: loading dose= Vd*Target []
- check for desired effect and adjust
Relate half lives to steady state
It takes 4-5 half lives to reach/change a steady state