KERBOODLE SUMMARY QUESTIONS: OZ Flashcards
1
Q
State the main gases in unpolluted air
A
nitrogen
oxygen
argon
2
Q
State three human activities that add gases to the air
A
combustion of hydrocarbons
deforestation
cattle farming
landfill
changes in land use
3
Q
Calculate how many parts per million by volume of argon (1%) are in a typical sample of tropospheric air.
A
10 000ppm
4
Q
Calculate the percentage of neon (18.2ppm) in a typical sample of tropospheric air
A
0.00182%
5
Q
Calculate the volume of methane present in 1 dm3 of tropospheric air
concentration of methane in tropospheric air (1.8 ppm)
A
1.8 x 10-6 dm3
6
Q
Calculate the percentage of methane molecules in a sample of 1 dm3 of air
concentration of methane in tropospheric air (1.8 ppm)
A
0.00018%
7
Q
A beam of infrared radiation has an energy of 3.65 x 10-20 J per photon.
Calculate the frequency of the radiation
A
5.5 x 1013 Hz
8
Q
A beam of X-rays has a frequency of 2.60 x 1017 s-1
Calculate the wavelength of the X-rays
A
1.15 x 10-9 m
9
Q
Carbon dioxide is a greenhouse gas. It absorbs some of the infrared radiation given off from the Earth’s surface.
Explain why carbon dioxide molecules absorb only certain frequencies of infrared radiation
A
Specific frequencies corresponding to transitions between vibrational energy levels, making the bonds vibrate more
10
Q
Carbon dioxide is a greenhouse gas. It absorbs some of the infrared radiation given off from the Earth’s surface.
Explain why absorbing infrared radiation makes the atmosphere warmer
A
Molecules which have absorbed radiation have more kinetic energy. This energy is subsequently transferred to other molecules in the air by collisions
11
Q
To change 1 mole of molecular HCl from the lowest vibrational energy level (ground state) to the next vibrational level requires 32.7 kJ
Calculate the energy, in joules, gained by one molecule of HCl when energy is absorbed in this way
[Avagadro constant, NA = 6.02 x 1023 mol-1
Then calculate the corresponding frequencing of radiation. State the type of radiation this corresponds to.
Then calculate the wavelength of this radiation in metres.
A
- 43 x 10-20 J
- 20 x 10-13 Hz, infrared
- 66 x 10-6 m
12
Q
You want to heat up a cup of coffee in a microwave cooker.
The cooker uses radiation of frequency 2.45 x 109 Hz
The cup contains 150 cm3 of coffee, which is mainly water.
Calculate the energy needed to raise the temperature of the water by 30oC
[specific heat capacity of water = 4.18 J g-1 K-1]
The calculate the energy transferred to the water by each photon of microwave radiation
Then calculate the energy transferred by one mole of photons
Then calculate how many moles of photons are needed to supply the energy calculated to raise the temperature of water by 30oC
A
- 88 x 104 J
- 62 x 10-24 J
- 978 J
19 200 moles
13
Q
State whether or not the species F is a radical
A
yes
14
Q
State whether or not the species Ar is a radical
A
no
15
Q
State whether or not the species H2O is a radical
A
no
16
Q
State whether or not the species OH is a radical
A
yes
17
Q
State whether or not the species NO2 is a radical
A
yes
18
Q
State whether or not the species CH3 is a radical
A
yes
19
Q
The hydroxyl radical, HO•, is an important species in atmospheric chemistry. Reaction A shows one process in which HO• is produced. The reaction is brought about by radiation with a wavelength below 190nm.
Reaction A: H2O + hv –> H• + HO•
Hydroxyl radicals are very reactive and act as scavengers in the atmosphere. One set of reactions which involve stratospheric ozone is:
- *Reaction B:** HO• + O3 –> HO2• + O2
- *Reaction C:** HO2• + O3 –> HO• + 2O2
State whether reaction A is a homolytic or a heterolytic process
A
homolytic
20
Q
The hydroxyl radical, HO•, is an important species in atmospheric chemistry. Reaction A shows one process in which HO• is produced. The reaction is brought about by radiation with a wavelength below 190nm.
Reaction A: H2O + hv –> H• + HO•
Hydroxyl radicals are very reactive and act as scavengers in the atmosphere. One set of reactions which involve stratospheric ozone is:
- *Reaction B:** HO• + O3 –> HO2• + O2
- *Reaction C:** HO2• + O3 –> HO• + 2O2
Explain whether reactions A, B and C are initiation, propagation or termination
A
A is initiation
B and C are propagation
21
Q
The hydroxyl radical, HO•, is an important species in atmospheric chemistry. Reaction A shows one process in which HO• is produced. The reaction is brought about by radiation with a wavelength below 190nm.
Reaction A: H2O + hv –> H• + HO•
Hydroxyl radicals are very reactive and act as scavengers in the atmosphere. One set of reactions which involve stratospheric ozone is:
- *Reaction B:** HO• + O3 –> HO2• + O2
- *Reaction C:** HO2• + O3 –> HO• + 2O2
Write an equation which shows the overall result of reactions B and C
A
2O3 ⇌ 3O2
22
Q
The hydroxyl radical, HO•, is an important species in atmospheric chemistry. Reaction A shows one process in which HO• is produced. The reaction is brought about by radiation with a wavelength below 190nm.
Reaction A: H2O + hv –> H• + HO•
Hydroxyl radicals are very reactive and act as scavengers in the atmosphere. One set of reactions which involve stratospheric ozone is:
- *Reaction B:** HO• + O3 –> HO2• + O2
- *Reaction C:** HO2• + O3 –> HO• + 2O2
Write an equation which shows the overall result of reactions B and C
A
2O3 ⇌ 3O2
23
Q
The hydroxyl radical, HO•, is an important species in atmospheric chemistry. Reaction A shows one process in which HO• is produced. The reaction is brought about by radiation with a wavelength below 190nm.
Reaction A: H2O + hv –> H• + HO•
Hydroxyl radicals are very reactive and act as scavengers in the atmosphere. One set of reactions which involve stratospheric ozone is:
- *Reaction B:** HO• + O3 –> HO2• + O2
- *Reaction C:** HO2• + O3 –> HO• + 2O2
State the role of HO• in this process
A
catalyst
24
Q
The creation of nitrogen monoxide from human activities is of concern because it is thought to lead to a loss of ozone from the stratosphere. Reactions D and E show how this loss can occur.
- Reaction D:** NO• + O3 –> NO2• + O2 ΔH* = -100 kJmol-1
- Reaction E:** NO2• + O –> O2 ΔH* = -192 kJmol-1
State one human activity which leads to the production of a significant amount of NO.
A
oxidation of nitrogen in internal combustion engines
25
The creation of nitrogen monoxide from human activities is of concern because it is thought to lead to a loss of ozone from the stratosphere. Reactions D and E show how this loss can occur.
* *Reaction D:** NO• + O3 --\> NO2• + O2 Δ*H* = -100 kJmol-1
* *Reaction E:** NO2• + O --\> O2 Δ*H* = -192 kJmol-1
Deduce the overall effect of reactions D and E.
O3 + O --\> 2O2
26
The creation of nitrogen monoxide from human activities is of concern because it is thought to lead to a loss of ozone from the stratosphere. Reactions D and E show how this loss can occur.
* *Reaction D:** NO• + O3 --\> NO2• + O2 Δ*H* = -100 kJmol-1
* *Reaction E:** NO2• + O --\> O2 Δ*H* = -192 kJmol-1
State the role of NO in this process
catalyst
27
The creation of nitrogen monoxide from human activities is of concern because it is thought to lead to a loss of ozone from the stratosphere. Reactions D and E show how this loss can occur.
* *Reaction D:** NO• + O3 --\> NO2• + O2 Δ*H* = -100 kJmol-1
* *Reaction E:** NO2• + O --\> O2 Δ*H* = -192 kJmol-1
Calculat the value of Δ*H* for the overall process
(-100) + (-192) = -292 kJ mol-1
28
Reactions F to K show various processes involving ethane
**Reaction F:** C2H6 --\> 2CH3•
**Reaction G:** CH3• + C2H6 --\> CH4 + C2H5•
**Reaction H:** C2H5• --\> C2H4 + H•
**Reaction I:** H• + C2H6 --\> H2 + C2H5•
**Reaction J:** 2C2H5• --\> C2H4 + C2H6
**Reaction K:** 2C2H5• --\> C4H10
State whether these reactions are initiation, propagation, or termination
* initiation
* reaction F
* propagation
* reaction G
* reaction H
* reaction I
* termination
* reaction J
* reaction K
29
Reactions F to K show various processes involving ethane
**Reaction F:** C2H6 --\> 2CH3•
**Reaction G:** CH3• + C2H6 --\> CH4 + C2H5•
**Reaction H:** C2H5• --\> C2H4 + H•
**Reaction I:** H• + C2H6 --\> H2 + C2H5•
**Reaction J:** 2C2H5• --\> C2H4 + C2H6
**Reaction K:** 2C2H5• --\> C4H10
For most of these reactions, you would need information about bond enthalpies in order to decide whether the process is exothermic or endothermic. But a few of the reactions can be classified by inspection. Explain which reactions are endothermic and which are exothermic
* endothermic
* reaction F
F is endothermic because C-C bond broken
* exothermic
* reaction K
K is endothemric because C-C bond is formed
30
Reactions F to K show various processes involving ethane
**Reaction F:** C2H6 --\> 2CH3•
**Reaction G:** CH3• + C2H6 --\> CH4 + C2H5•
**Reaction H:** C2H5• --\> C2H4 + H•
**Reaction I:** H• + C2H6 --\> H2 + C2H5•
**Reaction J:** 2C2H5• --\> C2H4 + C2H6
**Reaction K:** 2C2H5• --\> C4H10
State the names and formulae of the chemical species in the reaction sequence which are radicals
CH3•
methy radical
C2H5•
ethyl radical
H•
hydrogen radical
31
The radical chain reaction of methane (CH4) with chlorine in the presence of sunlight is given below:
CH4 + Cl2 --\> CH3Cl + HCl
Suggest a mechanism for the reaction showing clearly which reactions correspond to the initiation, propagation, and termination stages
Cl2 --\> 2Cl•
initiation
CH4 + Cl• --\> CH3• + HCl
propagation
CH3• + Cl2 --\> CH3Cl + Cl•
propagation
Cl• + Cl• --\> Cl2
termination
CH3• + CH3• --\> C2H6
termination
32
The radical chain reaction of methane (CH4) with chlorine in the presence of sunlight is given below:
CH4 + Cl2 --\> CH3Cl + HCl
Explain why the reaction product also contains some CH2Cl, CH3Cl and CCl4
The chloromethane can react with Cl• radicals
CH3Cl + Cl• --\> CH2Cl• + HCl
CH2Cl• + Cl2 --\> CH2Cl2 + Cl•
Further substitution produces CHCl3 and CCl4
33
Use the collision theory to explain why coal burns faster when it is finely powdered than when it is in a lump
Greater surface area, so more frequent collisions
34
Use the collision theory to explain why nitrogen and oxygen in the atmosphere do not normally react to form nitrogen oxides
Insufficient energy to overcome the activation energy
35
Use the collision theory to explain why reactions between two solids take place very slowly
Particles are in fixed positions and number of collisions is low
36
Use the collision theory to explain why flour dust in the air can ignite with explosive violence
Very high surface area and a spark will easily overcome the activation energy
37
The collision theory assumes that the rate of a reaction depends on:
* *A:** the rate at which reactant molecules collide with one another
* *B:** the proportion of reactant molecules that have enough energy to react once they have collided
Which out of A and B, explains that reactions in solution go faster at higher concentrations
**A:** the rate at which reactant molecules collide with one another
38
The collision theory assumes that the rate of a reaction depends on:
* *A:** the rate at which reactant molecules collide with one another
* *B:** the proportion of reactant molecules that have enough energy to react once they have collided
Which out of A and B, explains that solids react faster with liquids or gases when their surface area is greater
**A:** the rate at which reactant molecules collide with one another
39
The collision theory assumes that the rate of a reaction depends on:
* *A:** the rate at which reactant molecules collide with one another
* *B:** the proportion of reactant molecules that have enough energy to react once they have collided
Which out of A and B, explains that catalysts increase the rate of reactions
**B:** the proportion of reactant molecules that have enough energy to react once they have collided
40
The collision theory assumes that the rate of a reaction depends on:
* *A:** the rate at which reactant molecules collide with one another
* *B:** the proportion of reactant molecules that have enough energy to react once they have collided
Which out of A and B, explains that increasing the temperature increases the rate of a reaction
**Mainly B:** the proportion of reactant molecules that have enough energy to react once they have collided
**with A to a minor extent A:** the rate at which reactant molecules collide with one another
41
For the reaction of magnesium with hydrochloric acid
Mg(s) + 2HCl(aq) --\> MgCl2(aq) + H2(g)
State which of the following factors might affect the rate
**A)** temperature
**B)** total pressure of gas
**C)** concentration of solution
**D)** surface area of solid
A, B, C and D
42
For the reaction of nitrogen with hydrogen in the presence of an iron catalyst
N2(g) + 3H2(g) --\> 2NH3(g)
State which of the following factors might affect the rate
**A)** temperature
**B)** total pressure of gas
**C)** concentration of solution
**D)** surface area of solid
A and B
43
For the decomposition of aqueous hydrogen peroxide
2H2O2(aq) --\> 2H2O(l) + O2(g)
State which of the following factors might affect the rate
**A)** temperature
**B)** total pressure of gas
**C)** concentration of solution
**D)** surface area of solid
A, B and C
44
A mixture of hydrogen and oxygen doesn't react until it is ignited by a spark - then it explodes. The mixture also explodes if you add some powdered platinum
The energy of a spark is tiny, yet it is enough to ignite any quantity of a hydrogen/oxygen mixture, large or small.
Suggest an explanation for this.
The reaction has a high activation enthalpy that prevents it occuring at a significant rate at room temperature. However, the reaction is exothermic and once the spark has provided the energy needed to get it started, the reaction produces enough energy to sustain itself regardless of how much is present.
45
A mixture of hydrogen and oxygen doesn't react until it is ignited by a spark - then it explodes. The mixture also explodes if you add some powdered platinum
Explain why platinum makes the hydrogen/oxygen reaction occur at room temperature
The platinum catalyst offers an alternative pathway with a lower activation enthalpy close to the thermal energy of molecules at room temperature
46
The activation enthalpy for the decomposition of hydrogen peroxide to oxygen and water is +36.4 kJ mol-1 in the presence of an enzyme catalyst and +49.0 kJ mol-1 in the presence of a very fine colloidal suspension of platinum. The overall reaction is exothermic.
Sketch, on the same enthalpy diagram, the enthalpy profiles for both cataylsts
Reaction profile shows reactants at higher enthalpy than products, and two lines showing activation enthalpy for uncatalysed reaction higher than activation enthalpy for catalysed reaction
X-axis: progress of reaction, y-axis: enthalpy. Ea for cataylsed reaction marked as +36.4 kJ mol-1 and for uncatalysed marked as +49.0 kJ mol-1.
47
The activation enthalpy for the decomposition of hydrogen peroxide to oxygen and water is +36.4 kJ mol-1 in the presence of an enzyme catalyst and +49.0 kJ mol-1 in the presence of a very fine colloidal suspension of platinum. The overall reaction is exothermic.
How will the rate of the decomposition of hydrogen peroxide differ for the two catalysts at room temperature?
Explain your answer
The rate will be faster for the catalysed reaction as the activation enthalpy is significantly lower, so more molecules have sufficient energy to react.
48
The enthalpy profiles A-D represent four different reactions - all diagrams are drawn to the same scale
State which of the enthalpy profiles A-D represents exothermic reactions
B and C
49
The enthalpy profiles A-D represent four different reactions - all diagrams are drawn to the same scale
State which of the enthalpy profiles A-D represents endothermic reactions
A and D
50
The enthalpy profiles A-D represent four different reactions - all diagrams are drawn to the same scale
State which of the enthalpy profiles A-D shows the largest activation enthalpy
D
51
The enthalpy profiles A-D represent four different reactions - all diagrams are drawn to the same scale
State which of the enthalpy profiles A-D shows the smallest activation enthalpy
B
52
The enthalpy profiles A-D represent four different reactions - all diagrams are drawn to the same scale
State which of the enthalpy profiles A-D represents the most exothermic reaction
B
53
The enthalpy profiles A-D represent four different reactions - all diagrams are drawn to the same scale
State which of the enthalpy profiles A-D represents the most endothermic reaction
D
54
The reaction of chlorine atoms with ozone in the upper atmosphere (stratosphere) is thought to be responsible for the destruction of the ozone layer:
Cl + O3 --\> ClO + O2
The chlorine atoms are produced by the action of high energy solar radiation on CFCs.
Use collision theory to explain how an increase in the concentration of chlorine atoms increases the rate of reaction with ozone.
Increases in concentration mean more collisions so that there are more collisions with the minimum energy to react
55
The reaction of chlorine atoms with ozone in the upper atmosphere (stratosphere) is thought to be responsible for the destruction of the ozone layer:
Cl + O3 --\> ClO + O2
The chlorine atoms are produced by the action of high energy solar radiation on CFCs.
The activation enthalpy for the reaction of chlorine atoms with ozone is relatively small. Explain what effect you would expect a change of temperature to have on the rate of this reaction
As the activation enthalpy is small, an increase in temperature will mean that many more collisions will have the minimum energy to react and so the rate of reaction increases rapidly
56
The diagram below shows the energy distribution for collisions between Cl atoms and O3 molecules at temperature T1. Ea is the activation enthalpy for the reaction of Cl atoms and O3 molecules. Copy the diagram and shade the area of the graph to indicate the number of collisions with sufficient energy to lead to a reaction
The shaded area in underneath the T1 curve and to the right of Ea
57
The diagram below shows the energy distribution for collisions between Cl atoms and O3 molecules at temperature T1. Ea is the activation enthalpy for the reaction of Cl atoms and O3 molecules.
Indicate the energy distribution for collisions between Cl atoms and O3 molecules when the temperature of the reactants is increased by 10 K to T2. Shade the area under the graph to indicate the number of collisions with sufficient energy to lead to a reaction at T2
The area shaded is underneath the T2 curve and to the right of Ea. The T2 curve has a lower and broader maximum than the T1 curve and the maximum value is shifted to the right. It tails off above the T1 curve.
58
The breakdown of ozone in the stratosphere is catalysed by chlorine atoms. The overall reaction is:
O3 + O --\> 2O2
The Cl atoms act as a homogeneous catalyst in this process.
State the meaning of the term homogeneous
Homogeneous means same physical state. Here the catalyst and reactants are gases
59
The breakdown of ozone in the stratosphere is catalysed by chlorine atoms. The overall reaction is:
O3 + O --\> 2O2
The Cl atoms act as a homogeneous catalyst in this process.
The enthalpy profiles for the catalysed and uncatalysed reactions are shown below.
Explain why the enthalpy profile for the catalysed reaction has two humps
It is a two step reaction with an activation energy for each step
60
The breakdown of ozone in the stratosphere is catalysed by chlorine atoms. The overall reaction is:
O3 + O --\> 2O2
The Cl atoms act as a homogeneous catalyst in this process.
The enthalpy profiles for the catalysed and uncatalysed reactions are shown below.
Describe what is happening at the peaks and troughs on the two curves
peaks: enough energy has been put in to start the reaction
troughs: intermediate step
61
Name the haloalkane CHCl3
trichloromethane
62
Name the haloalkane CH3CHClCH3
2-chloropropane
63
Name the haloalkane CF3CCl3
1,1,1-trichloro-2,2,2-trifluoroethane
64
Name the haloalkane CH3-CHCl-CF3
2-chloro-1,1,1-trifluoropropane
65
Name the haloalkane CH3-CHCl-CBr2-CH3
2,2-dibromo-3-chlorobutane
66
Explain why noble gases have very low boiling points
In the solid or liquid state, noble gas atoms are held together by weak instantaneous dipole - induced dipole bonds. It takes very little energy to break these bonds and this results in very low melting and boiling points
67
Draw skeletal formulae showing how two molecules of pentane can approach close to one another. Now do the same for both of its structural isomers, 2-methylbutane, and 2,2-dimethylpropane
68
Explain the boiling points of the isomers below in terms of the strength of the intermolecular bonds present
Pentane is a straight-chain and its molecules can approach each other closely so there are strong intermolecular forces
Methylbutane and dimethylpropane have respectively more branching and cannot approach as closely, so the instantaneous dipole - induced dipole forces are weaker
The stronger the intermolecular bonds, the more energy is required to break them
69
Explain the difference in strength of the intermolecular bonds of the isomers below
Pentane has the strongest intermolecular bonds and hence the highest boiling point. Dimethylpropane has the weakest intermolecular bonds and hence the lowest boiling point
70
Explain whether CO2 possesses a permanent dipole, considering the shape of the molecule and the electronegativity of its atoms
no dipole
71
Explain whether CHCl3 possesses a permanent dipole, considering the shape of the molecule and the electronegativity of its atoms
dipole
72
Explain whether C6H12 (cyclohexane) possesses a permanent dipole, considering the shape of the molecule and the electronegativity of its atoms
no dipole
73
Explain whether CH3OH possesses a permanent dipole, considering the shape of the molecule and the electronegativity of its atoms
dipole
74
Explain whether (CH3)2CO possesses a permanent dipole, considering the shape of the molecule and the electronegativity of its atoms
dipole
75
Explain whether benzene possesses a permanent dipole, considering the shape of the molecule and the electronegativity of its atoms
no dipole
76
Silane, SiH4, boils at 161 K whereas hydrogen sulfide, H2S, boils at 213 K
State the number of electrons in each molecule
```
SiH4 = 18
H2S = 18
```
77
Silane, SiH4, boils at 161 K whereas hydrogen sulfide, H2S, boils at 213 K
Explain the strengths of instantaneous dipole - induced dipole bonds in the two compounds
The attractions will be similar because the number of electrons is the same
78
Silane, SiH4, boils at 161 K whereas hydrogen sulfide, H2S, boils at 213 K
Explain whether either molecule possesses a permanent dipole
H2S has a permanent dipole - it is a bent molecule with two lone pairs. SiH4 does not have an overall permanent dipole as it is a symmetrical molecule
79
Silane, SiH4, boils at 161 K whereas hydrogen sulfide, H2S, boils at 213 K
Explain the different boiling points of these two compounds
Both compounds have similar instantaneous dipole - induced dipole bonds
However H2S also has permanent dipole - permanent dipole bonds
So its boiling point is higher than that of SiH4
80
Explain why the O-H bond is polar.
Oxygen is more electronegative than hydrogen
81
State whether or not the covalent bond C-F will be polar. If so, show which atom is positive and which is negative using the 𝛿+ and 𝛿- convention
C𝛿+--F𝛿-
polar
82
State whether or not the covalent bond C-H will be polar. If so, show which atom is positive and which is negative using the 𝛿+ and 𝛿- convention
C--H
non polar
83
State whether or not the covalent bond C-S will be polar. If so, show which atom is positive and which is negative using the 𝛿+ and 𝛿- convention
C--S
non polar
84
State whether or not the covalent bond H-Cl will be polar. If so, show which atom is positive and which is negative using the 𝛿+ and 𝛿- convention
H𝛿+--Cl𝛿-
polar
85
State whether or not the covalent bond H-N will be polar. If so, show which atom is positive and which is negative using the 𝛿+ and 𝛿- convention
H𝛿+--N𝛿-
polar
86
State whether or not the covalent bond S-Br will be polar. If so, show which atom is positive and which is negative using the 𝛿+ and 𝛿- convention
S--Br
non polar
87
State whether or not the covalent bond C-O will be polar. If so, show which atom is positive and which is negative using the 𝛿+ and 𝛿- convention
C𝛿+--O𝛿-
polar
88
Hydrogen bonding can occur between different molecules in mixtures. Draw a diagram to show where the hydrogen bonds form in a NH3 and H2O mixture
89
Hydrogen bonding can occur between different molecules in mixtures. Draw a diagram to show where the hydrogen bonds form in a CH3CH2OH and H2O mixture
90
Explain why water exhibits a greater degree of hydrogen bonding than other substances
Water has two O-H bonds and two lone pairs on the oxygen so more hydrogen bonding is possible
91
When 1-chloropropane is heated under reflux with aqueous sodium hydroxide solution, a nucleophilic substitution reaction occurs, forming propan-1-ol
Write a balanced equation for this reaction
CH3CH2CH2Cl(l) + NaOH(aq) --\> CH3CH2CH2OH(aq) + NaCl(aq)
92
When 1-chloropropane is heated under reflux with aqueous sodium hydroxide solution, a nucleophilic substitution reaction occurs, forming propan-1-ol
Explain why this is a substitution reaction
The chlorine atom in 1-chloropropane has been replaced by a hydroxyl group, OH.
93
When 1-chloropropane is heated under reflux with aqueous sodium hydroxide solution, a nucleophilic substitution reaction occurs, forming propan-1-ol
Draw the mechanism of the reaction, showing the relevant lone pairs and partial charges
Curly arrow from lone pair of electrons on OH- to carbon in C-Cl bond
Curly arrow from C-Cl bond to chlorine.
Propanol and Cl- formed
𝛿+ on carbon of C-Cl and 𝛿- on chlorine of C-Cl bond
94
Write balanced equations for the nucleophilic substitution reaction of iodoethane and OH- ions, showing the structures of the reactants and products clearly
C2H5I + OH- --\> C2H5OH + I-
95
Write balanced equations for the nucleophilic substitution reaction of bromoethane and CN- ions, showing the structures of the reactants and products clearly
C2H5Br + CN- --\> C2H5CN + Br-
96
Write balanced equations for the nucleophilic substitution reaction of chlorocyclopentane and OH- ions, showing the structures of the reactants and products clearly
C5H9Cl + OH- --\> C5H9OH + Cl-
97
Write balanced equations for the nucleophilic substitution reaction of 2-chloro-2-methylpropane and H2O, showing the structures of the reactants and products clearly
CH3C(CH3)ClCH3 + H2O --\> CH3C(CH3)(OH)CH3 + HCl
98
Write balanced equations for the nucleophilic substitution reaction of 1,2-dibromoethane and OH- ions, showing the structures of the reactants and products clearly
CH2BrCH2Br + 2OH- --\> CH2OHCH2OH + 2Br-
99
Write balanced equations for the nucleophilic substitution reaction of bromomethane and C2H5O- (ethoxide) ions, showing the structures of the reactants and products clearly
CH3Br + C2H5O- --\> CH3OC2H5 + Br-
100
Write balanced equations for the nucleophilic substitution reaction of 2-chloropropane and CH3COO- (ethanoate) ions, showing the structures of the reactants and products clearly
CH3CHClCH3 + CH3COO- --\> CH3CH(OOCCH3)CH3 + Cl-
101
Concentrated ammonia solution reacts with 1-bromoethane when heated in a sealed tube
Write a balanced equation for this reaction
CH3CH2Br + NH3 --\> CH3CH2NH2 + H+ + Br-
102
Concentrated ammonia solution reacts with 1-bromoethane when heated in a sealed tube
Draw out the mechanism for this reaction
103
Concentrated ammonia solution reacts with 1-bromoethane when heated in a sealed tube
How would you explain the mechanism of this reaction in words
Ammonia is the nucleophile because of its lone pair. It attacks the partial positive charge on the carbon atom and substitutes the bromine atom. There is a partial positive charge because bromine is more electronegative than carbon. After the NH3 attacks the 1-bromoethane, a hydrogen ion is lost from the molecule to give the product ethylamine
104
Concentrated ammonia solution reacts with 1-bromoethane when heated in a sealed tube
Give definitions of nucleophile, electronegativity, substitution, and curly arrow
Nucleophile: a species with a lone pair that can form a covalent bond
Electronegativity: the power to attract electrons in a covalent bond
Substitution: where one atom or group replaces another atom or group
Curly arow: device to show the movement of a pair of electrons
