Integrated Rate Laws Flashcards
What is the integrated rate law for a first order reaction?
ln ([A]0/[A]t) = kt
What is the half-life of a reaction?
The time for the reactant concentration to reach half of its initial value
For a first order reaction, are half-life and rate constant (k) directly or inversely proportional?
Inversely proportional: a large rate constant means a short half-life
For a first order reaction, does half-life depend on reactant concentration?
No
What is the equation for half-life for a first order reaction?
t(1/2) = ln(2)/k or 0.693/k
For a first order reaction, is half-life constant? If not, how does each half-life differ from the preceding one?
Half-life is constant
What is the integrated rate law for a second order reaction with one reactant?
1/[A]t - 1/[A]0 = kt
What is the equation for the half-life of a second order reaction with one reactant?
t(1/2) = 1/k[A]0
For a second order reaction, are half-life and rate constant directly or inversely proportional?
Inversely proportional
For a second order reaction, does half-life depend on reactant concentration? If so, is the relationship direct or inverse?
Half-life is inversely proportional to reactant concentration. High reactant concentration means short half-life.
For a second order reaction, is half-life constant? If not, how does each half-life differ from the preceding one?
No, each successive half-life is double the preceding one since [A] is halved during each half-life.
What is the integrated rate law for a zero order reaction?
[A]t - [A]0 = -kt
What is the equation for the half-life of a zero order reaction?
t(1/2) = [A]0/2k
For a zero order reaction, is half-life directly or inversely proportional to reactant concentration?
Directly proportional
Graphing ln[A]t against time yields a straight line with slope -k for a reaction of which order?
First order reaction
