Genetic Test 3 Ch. 5 Flashcards
1) Syntenic genes can assort independently when ________. <br></br>A) they are located on different chromosomes<br></br>B) they are far apart on a chromosome and crossing over occurs very rarely between the genes <br></br>C) they are far apart on a chromosome and crossing over occurs frequently between the genes<br></br>D) they are very close together on a chromosome E) crossing over occurs rarely between the genes
Answer: C
2) The alleles of linked genes tend to ________. <br></br>A) experience a higher rate of crossing over<br></br>B) be mutated more often than unlinked genes <br></br>C) assort independently<br></br>D) assort independently and show a higher rate of crossing over E) segregate together during gamete production
Answer: E
3) Genetic linkage leads to the production of a significantly greater than expected number of gametes containing chromosomes with ________.<br></br>A) dominant alleles<br></br> <br></br>B) recessive alleles<br></br>C) allele combinations that are different from parental combinations<br></br>D) mutant alleles<br></br>E) parental combinations of alleles
Answer: E
4) The syntenic genes B and T are linked. A cross between two parents, with genotypes BBtt and 4) bbTT, produces F1 progeny with the BbTt genotype. What are the possible arrangements of alleles on the F1 progeny’s chromosomes?<br></br>A) Bb/Tt<br></br> <br></br>B) BT/Bt or bt/bT<br></br>C) BT/bt<br></br>D) Bt/bT<br></br>E) B/T or b/t
Answer: D
5) In an individual that is dihybrid for completely linked genes, which alleles would you expect in the gametes?<br></br>A) only recombinant gametes<br></br>B) one parental allele combination occurring more frequently than another<br></br>C) one parental allele combination occurring more frequently than another and no recombinant gametes<br></br>D) two equally frequent gametes containing only parental allele combinations<br></br>E) two equally frequent gametes containing only parental allele combinations and no recombinant gametes
Answer: E
6) What is a two- point test cross, involving a dihybrid F1 fly, used for when mapping genes?<br></br>A) to determine if the F1 fly is homozygous dominant or heterozygous<br></br>B) to determine the allele combinations that a homozygous recessive fly can create<br></br> <br></br>C) to determine which alleles are dominant and which are recessive<br></br>D) to determine the recombination frequency between two genes<br></br>E) to determine the allele combinations that the F1 fly can produce
Answer: D
7) Genes A and B are 7.5 map units apart on one chromosome. Genes C and D are 8.0 map units apart on a second non- homologous chromosome. The recombination frequency between A and C is ________.<br></br>A) 0.003 B) 0.851 C) 0.155 D) 0.006 E) 0.500
Answer: E
8) In fruit flies, red eyes (pr+) are dominant to purple eyes (prpr) and normal wings (vg+) are dominant to vestigial wings (vgvg). The genes are located on the same chromosome. A pure breeding red- eyed fly with vestigial wings was crossed with a pure- breeding purple- eyed fly with normal wings. All of the F1 progeny had a WT phenotype. Which of the following represents the arrangement of alleles on the F1’s chromosome?<br></br>A) pr+vg+/pr+vg+<br></br> <br></br>B) prvg/prvg<br></br>C) prvg/pr+vg+<br></br>D) pr+vg/prvg+ <br></br>E) E) prpr+/vgvg+
Answer: D
9) In fruit flies, red eyes (pr+) are dominant to purple eyes (prpr) and normal wings (vg+) are dominant to vestigial wings (vgvg). The genes are located on the same chromosome. A pure- breeding red- eyed fly with vestigial wings was crossed with a pure- breeding purple- eyed fly with normal wings. All of the F1 progeny had a WT phenotype. The recombination frequency between the two genes is 15%. If an F1 individual were test crossed, what percentage of the progeny would you expect to have the WT phenotype?<br></br>A) 85% B) 50% C) 7.5% D) 92.5% E) 15%
Answer: C
10) What organism exhibits complete genetic linkage, meaning there is no recombination between homologous chromosomes?<br></br>A) Female Drosophila<br></br>B) Female Homo sapiens C) Male Drosophila<br></br>D) Male Homo sapiens<br></br>E) Zea mays (corn)
Answer: C
11) William Bateson and Reginald Punnett were not able to detect genetic linkage in sweet peas. Which of the following explains why Thomas Morgan was able to detect autosomal genetic linkage?<br></br>A) He performed Lod score analysis to determine the distance between the genes he was<br></br> <br></br>studying.<br></br>B) He crossed two heterozygous individuals and was able to determine offspring genotypes from their phenotypes.<br></br>C) He crossed a heterozygous individual with a homozygous recessive individual and was able to determine progeny genotypes from their phenotypes.<br></br>D) He sequenced the DNA and was able to determine the distance between the genes.<br></br>E) He performed a three- point test cross.
Answer: C
12) In sweet peas, the genes for flower color and pollen grain shape are 11 cM apart. A pure- breeding purple flowering plant with round pollen grains is crossed to a pure- breeding red flowering plant with long pollen grains. The resulting F1 offspring are all purple flowering plants with long pollen grains. What percent of offspring from a test cross analysis of the F1 individuals would you expect to be red flowering plants with long pollen grains?<br></br> A) 5.5 B) 89 C) 44.5 D) 39 E) 11
Answer: C
13) In sweet peas, the genes for flower color and pollen grain shape are 11 cM apart. A pure- breeding purple flowering plant with round pollen grains is crossed to a pure- breeding red flowering plant with long pollen grains. The resulting F1 offspring are all purple flowering plants with long pollen grains. What percent of offspring from a test cross analysis of the F1 individuals would you expect to be purple flowering plants with long pollen grains?<br></br>A) 11 B) 44.5 C) 39 D) 5.5 E) 89
Answer: D
14) If you are given a recombination frequency of 34% between genes X and Y and 27% between X andZ, can you predict the order of the three genes?<br></br>A) No; based on this data alone, the order could be X- Z- Y or Z- X- Y. <br></br>B) No; based on this data alone, the order could be Z- Y- X or X- Y- Z.<br></br>C) Yes; the order is Z- X- Y.<br></br>D) Yes; the order is X- Y- Z. E) Yes; the order is X- Z- Y.
Answer: A
15) What type of test would you use to determine whether observed data constitute evidence of genetic linkage or are simply a case of chance variation from expected values?<br></br>A) recombination frequency (r) calculation <br></br>B) chi- square analysis<br></br>C) two- point test cross<br></br>D) three- point test cross E) test cross
Answer: B