Genetic Information, Variation & Relationships between Organisms Exam Qs Flashcards

You may prefer our related Brainscape-certified flashcards:
1
Q

A mutation of a tumour suppressor gene can result in the formation of a tumour. Explain how. (2 marks)

A
  1. (Tumour suppressor) gene inactivated / not able to control / slow down cell division;
    Ignore: references to growth
  2. Rate of cell division too fast / out of control.
    1 and 2 Accept: mitosis 1 and 2
    Reject: meiosis
How well did you know this?
1
Not at all
2
3
4
5
Perfectly
2
Q

Not all mutations result in a change to the amino acid sequence of the encoded polypeptide.
Explain why. (1 mark)

A
  1. (Genetic) code degenerate;
    Accept: codon for triplet
    Accept description of degenerate code, e.g. another triplet codes for the same amino acid
  2. Mutation in intron.
    Accept: mutation in non-coding DNA
How well did you know this?
1
Not at all
2
3
4
5
Perfectly
3
Q

Some cancer cells have a receptor protein in their cell-surface membrane that binds to a hormone called growth factor. This stimulates the cancer cells to divide.
Scientists have produced a monoclonal antibody that stops this stimulation.
Use your knowledge of monoclonal antibodies to suggest how this antibody stops the growth of a tumour. (3 marks)

A
  1. Antibody has specific tertiary structure / binding site / variable region;
    Do not accept explanations involving undefined antigen
  2. Complementary (shape / fit) to receptor protein / GF / binds to receptor protein / to GF;
    Ignore: same shape as receptor protein / GF
  3. Prevents GF binding (to receptor).
How well did you know this?
1
Not at all
2
3
4
5
Perfectly
4
Q

In the diagram above, the first codon is AUG. Give the base sequence of:
-the complementary DNA base sequence
-the missing anticodon
(2 marks)

A

TAC
UAC

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
5
Q

Aspartic acid and proline are both amino acids. Describe how two amino acids differ from one another. You may use a diagram to help your description. (1 mark)

A

Have different R group
accept in diagram

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
6
Q

Aspartic acid GAC, GAU
Proline CCA, CCG, CCC, CCU

Deletion of the sixth base (G) in the sequence shown in the diagram above would change the nature of the protein produced but substitution of the same base would not. Use the information in the table and your own knowledge to explain why. (3 marks)

A
  1. Substitution would result in CCA / CCC / CCU;
  2. (All) code for same amino acid / proline;
  3. Deletion would cause frame shift / change in all following codons / change next codon from UAC to ACC.
How well did you know this?
1
Not at all
2
3
4
5
Perfectly
7
Q

Messenger RNA (mRNA) is used during translation to form polypeptides. Describe how mRNA is produced in the nucleus of a cell. (6 marks)

A
  1. Helicase;
  2. Breaks hydrogen bonds;
  3. Only one DNA strand acts as template;
  4. RNA nucleotides attracted to exposed bases;
  5. (Attraction) according to base pairing rule;
  6. RNA polymerase joins (RNA) nucleotides together;
  7. Pre-mRNA spliced to remove introns.
How well did you know this?
1
Not at all
2
3
4
5
Perfectly
8
Q

Describe the structure of proteins (5 marks)

A
  1. Polymer of amino acids;
  2. Joined by peptide bonds;
  3. Formed by condensation;
  4. Primary structure is order of amino acids;
  5. Secondary structure is folding of polypeptide chain due to hydrogen bonding;
    Accept alpha helix / pleated sheet
  6. Tertiary structure is 3-D folding due to hydrogen bonding and ionic / disulfide bonds;
  7. Quaternary structure is two or more polypeptide chains.
How well did you know this?
1
Not at all
2
3
4
5
Perfectly
9
Q

Name the fixed position occupied by a gene on a DNA molecule. (1 mark)

A

Locus/loci;

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
10
Q

Describe how a gene is a code for the production of a polypeptide. Do not
include information about transcription or translation in your answer. (3 marks)

A
  1. (Because) base/nucleotide sequence;
  2. (In) triplet(s);
  3. (Determines) order/sequence of amino acid sequence/primary structure (in polypeptide);
How well did you know this?
1
Not at all
2
3
4
5
Perfectly
11
Q

Define the term exon. (1 mark)

A

Base/nucleotide/triplet sequence coding for polypeptide/sequence of amino acids/primary structure;

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
12
Q

Describe how a phosphodiester bond is formed between two nucleotides within a DNA molecule. (2 marks)

A
  1. Condensation (reaction)/loss of water;
  2. (Between) phosphate and deoxyribose;
  3. (Catalysed by) DNA polymerase;
    Reject if DNA polymerase joins AT/GC
    OR
    complementary nucleotides/bases
    OR
    forms hydrogen bonds
How well did you know this?
1
Not at all
2
3
4
5
Perfectly
13
Q

The two DNA strands of a particular gene contain 168 guanine bases between them. The relationship between the numbers of guanine bases (G), adenine bases (A), thymine bases (T) and cytosine bases (C) in these two strands of DNA is shown in the following equation.
G = 4(A + T) – C
Use this information and your understanding of DNA structure to calculate the maximum number of amino acids coded by this gene.
Show your working. (2 marks)

A

Correct answer for 2 marks = 70;;
Accept for 1 mark,
A = 42 and T = 42
OR
420 (total bases in gene)
OR
210 (bases in template strand)

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
14
Q

Name the protein associated with DNA in a chromosome. (1 mark)

A

Histone;

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
15
Q

Scientists investigated the genetic diversity between several species of sweet potato. They studied non-coding multiple repeats of base sequences.
Define ‘non-coding base sequences’ and describe where the non-coding multiple repeats are positioned in the genome. (2 marks)

A
  1. DNA that does not code for protein/polypeptides
    OR
    DNA that does not code for (sequences of) amino acids
    OR
    DNA that does not code for tRNA/rRNA;
    Accept the idea of not transcribed for ‘does not code for’.
    Do not credit ‘DNA that does not code for an amino acid’.
    Ignore reference to introns.
  2. (Positioned) between genes;
    Reject (positioned) ‘in introns’ or ‘between exons’.
    Accept ‘(Positioned) at the end of chromosomes’ or ‘(Positioned) in the telomeres’.
How well did you know this?
1
Not at all
2
3
4
5
Perfectly
16
Q

The nucleus and a chloroplast of a plant cell both contain DNA.
Give three ways in which the DNA in a chloroplast is different from DNA in the nucleus. (3 marks)

A

In chloroplasts
Must be comparative statements.
Accept alternatives in context of nuclear DNA

  1. DNA shorter;
    Accept smaller
  2. Fewer genes;
  3. DNA circular not linear;
    Accept DNA in a loop not linear
    Accept no chromosomes (in chloroplast) unlike nucleus
  4. Not associated with protein/histones, unlike nuclear DNA;
  5. Introns absent but present in nuclear DNA;
    Ignore references to double and single stranded DNA
17
Q

Not all mutations in the nucleotide sequence of a gene cause a change in the structure of a polypeptide.
Give two reasons why. (2 marks)

A

1.Triplets code for same amino acid
Accept: DNA/code/triplets are degenerate Reject: codons (as question states within genes)

  1. Occurs in introns /non-coding sequence;
    Reject: codons (as question states within genes) Ignore junk DNA
    Reject: multiple repeats
18
Q

Compare and contrast the DNA in eukaryotic cells with the DNA in prokaryotic cells. (5 marks)

A

Comparisons
1. Nucleotide structure is identical;
Accept labelled diagram or description of nucleotide as phosphate, deoxyribose and base
2. Nucleotides joined by phosphodiester bond;
OR
Deoxyribose joined to phosphate (in sugar, phosphate backbone);
3. DNA in mitochondria / chloroplasts same / similar (structure) to DNA in prokaryotes;
Accept shorter than nuclear DNA/is circular not linear/is not associated with protein/histones unlike nuclear DNA;

Contrasts
4. Eukaryotic DNA is longer;
5. Eukaryotic DNA contain introns, prokaryotic DNA does not;
6. Eukaryotic DNA is linear, prokaryotic DNA is circular;
7. Eukaryotic DNA is associated with / bound to protein / histones, prokaryotic DNA is not;

19
Q

In Figure 2 the chromosomes are arranged in homologous pairs. What is a homologous pair of chromosomes? (1 mark)

A

(Two chromosomes that) carry the same genes;
Reject ‘same alleles’
Accept ‘same loci’ (plural) or ‘genes for the same characteristics’