GCSE Chemistry C2 - Section 3 Amount of substance and analytical techniques Flashcards
The yield of a reaction is . . .
how much product is made
In a reversible reaction the products can . . .
react to make the original reactants
The law of conservation of mass says . . .
we end up with the same total mass of atoms in the products as we started with in the reactants
The yield of a reaction is . . .
how much product is made
(H) The empirical formula is . . .
the simplest whole number ratio of the atoms in the compound
(H) We work out the mass ratio of reactants and products in a reaction using the . . .
balanced symbol equation
The relative formula mass of a compound is found by . . .
adding the relative atomic masses of all of the atoms in the formula
Mixtures in gas chromatography separate because . . .
each component takes a different amount of time to pass through the column
The relative mass of protons and neutrons is . . .
1
The % composition of an element in a compound is found by . . .
dividing the total mass of the element in the compound by the relative formula mass
Compounds can be identified using . . .
a mass spectrometer
The number of protons in an atom is equal to . . .
the number of electrons (or the atomic number)
2 disadvantages of modern instrumental analytical techniques are . . .
they’re expensive and require special training to use them
The relative mass of protons and neutrons is . . .
1
The number of protons in an atom is equal to . . .
the number of electrons (or the atomic number)
In a reversible reaction the products can . . .
react to make the original reactants
The law of conservation of mass says . . .
we end up with the same total mass of atoms in the products as we started with in the reactants
3 factors affecting the yield of a reaction are . . .
product being left behind in the apparatus, difficulty seperating the product from the mixture, incomplete reactions
(H) We work out the mass ratio of reactants and products in a reaction using the . . .
balanced symbol equation
(H) The empirical formula is . . .
the simplest whole number ratio of the atoms in the compound
2 disadvantages of modern instrumental analytical techniques are . . .
they’re expensive and require special training to use them
3 advantages of modern instrumental analytical techniques are . .
they’re fast, sensitive and accurate
The relative formula mass of a compound is found by . . .
adding the relative atomic masses of all of the atoms in the formula
The number of protons added to the number of neutrons is . . .
the mass number
The % composition of an element in a compound is found by . . .
dividing the total mass of the element in the compound by the relative formula mass
Compounds can be identified using . . .
a mass spectrometer
3 advantages of modern instrumental analytical techniques are . .
they’re fast, sensitive and accurate
3 factors affecting the yield of a reaction are . . .
product being left behind in the apparatus, difficulty seperating the product from the mixture, incomplete reactions
(H) The relative molecular mass of a compound can be found using . . .
the molecular ion peak in a mass spectrum
Mixtures in gas chromatography separate because . . .
each component takes a different amount of time to pass through the column
(H) The % yield of a reaction is calculated by . . .
dividing the actual yield by the maximum possible yield
Atoms of the same element with different numbers of neutrons are called . . .
isotopes
Paper chromatography can be used to . . .
find how many components are in a mixture
1 mole of any substance has a mass equal to . . .
the relative formula mass in grams
The number of protons added to the number of neutrons is . . .
the mass number
(H) The % yield of a reaction is calculated by . . .
dividing the actual yield by the maximum possible yield
Paper chromatography can be used to . . .
find how many components are in a mixture
Atoms of the same element with different numbers of neutrons are called . . .
isotopes
(H) The relative molecular mass of a compound can be found using . . .
the molecular ion peak in a mass spectrum
1 mole of any substance has a mass equal to . . .
the relative formula mass in grams
