write as a partial fraction A/(x+1) + B(x-2) + C/(x-2)2 x-8=A(x-2)2 +B(x+1)(x-2) +C(x+1) A=-1, C=-2 to find B do x=3, B=1 =-1/x+1 + 1/x-2 - 2/(x-2)2

Further Partial Fractions Flashcards by Aneurin Quinn Evans

x-8/(x+1)(x-2)² =

write as a partial fraction

A/(x+1) + B(x-2) + C/(x-2)²

x-8=A(x-2)² +B(x+1)(x-2) +C(x+1)

A=-1, C=-2 to find B do x=3, B=1

=-1/x+1 + 1/x-2 - 2/(x-2)²

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