Exam 3 Practice test Flashcards
SN2 mechanism/product
Inverted, nucleophile replaced
SN1 mechanism/product
Retention and inverstion, nucleophile replaced
HX
Halo at mark, syn and anti
HBr ONLY, ROOR
Br at anti mark, syn and anti
Br2 or Cl2
Anti addn across DB
Br2 or Cl2 and H2O
Anti- OH at mark, halo at anti mark
H3O+ or H2O
OH at mark, syn and anti
- Hg(OAc)2, H2O
- NaBH4
OH at mark
- BH3, THF
- HOOH, NaOH
OH at anti mark across DB, syn
- Hg(OAc)2, MeOH
- NaBH4
MeO at mark
CHX3, KOH
Both ends of DB bind to C, 2X bonded to C, syn
CH2I2, ZnCu
Both ends of DB bind to C, 2X bonded to C, syn
H2, Pd/C or H2, PtO2
Erases DB
RCO3H
DB erase, just bonded to O on both sides (epoxide)
H3O+, H2O (epoxide)
Anti addn of OH across DB
OH, H2O (Epoxide)
Anti addn of OH across DB
- OSO4
- NaHSO3, H2O, (Or H2O2)
Syn OH across DB
KMnO4 (cold, dilute), OH, H2O
Syn OH across DB
HIO4, H2O
OH double bonds to C on both ends, cutting cyclowhatever
- O3
- Zn (H3O+) or (CH3)2S
OH double bonds to C on both ends, cutting cyclowhatever
- O3
- H2O2
Adds double bonded O across DB, cutting cyclowhatever. OH added at one end
Hot concentrated KMnO4, H3O+, H2O
Adds double bonded O across DB, cutting cyclowhatever. OH added at one endf
Bredt’s rule
Can’t have a double bond at a bridgehead carbon if the ring has less than 8 carbons
E1 mechanism and product
Leaving group removed, stable products
E2 mechanism and product
Leaving group left, stable product plus enantiomer
Vinyl
Radical over double bond
Allyl
Radical across from double bond
Homolytic cleavage
X-X –> 2.X
Addition to pi bond
X. + = –> X/.
Hydrogen abstraction
X. H-R –> X-H + R.
Halogen abstraction
R. X-X –> R-X + X.
Elimination
X/. –> X. =
Coupling
2X. –> X-X
Chlorination of methane
UV light causes homolytic cleavage of Cl2, H bonds to one radical, radical carbon grabs Cl radical, radicals react with each other
Where does Br attach to with peroxide?
End of DB
Relative reactivity
% yield/#Hs
Strongest CH bond
Connected to 2x bond, then 2C away, then 1c
NBS
Adds br at mark, forms low concentration of Br2
Bromination of DB
NBr broken, radical formed. Br and H form bond, leaving rad on cyclohexane. Then Br2 breaks, adding br to cyclohexane
Br2 and HV
BR added to mark
KOT HOT
Removes Br, creates db
PLEASE KNOW (PAGE 20)