Exam 2: Lecture 5 Flashcards

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1
Q

Eukaryotic DNA Polymerases

A
  • there are five
  • responsible for generating RNA/DNA primers
  • elongate leading and lagging strands
  • replicate and repair mitochondrial genome and in DNA repair
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2
Q

Polymerase Alpha

A
  • plays important role in generation of short RNA/DNA primers that are required for replication initiation
  • lacks 3’-5’ exonuclease/proofreading activity (not required because used only to synthesize very short stretches of DNA)
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3
Q

Polymerase Beta

A
  • required to resynthesize short stretches of DNA during repair process
  • lacks proofreading activity (not required because used only to synthesize very sort stretches of DNA)
  • base-excision repair
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4
Q

Polymerase Gamma

A
  • used to replicate and repair mitochondrial genome

- tasked with replicating large stretches of DNA so requires proofreading activity

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5
Q

Polymerase Delta (looks like cursive g) and Polymerase Epsilon

A
  • tasked with synthesizing long stretches of DNA (leading and lagging strands) and therefore also require proofreading activity
  • essential for viability
  • Delta responsible for lagging-strand synthesis DNA repair
  • Epsilon responsible for leading-strand synthesis
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6
Q

Eukaryotic DNA Polymerases (Error Prone Polymerases)

A
  • encodes several DNA Polymerases that are prone to make mistakes when they are copying DNA
  • can be beneficial in certain circumstances
  • in some cases damage done to DNA is so severe that it prevents the canonical DNA polymerases from reading the template strand and synthesizing new strands
  • i.e. formation of thymine dimers (in response to UV light) if not corrected by cell canonical DNA polymerase will stall when it gets to this part of genome
  • when replication stalls, error prone DNA polymerases recruited to site of damage
  • binding pocket of error-prone polymerase can recognize and fit thymine dimers
  • some polymerases read it correctly and add two adenine residues to newly synthesized strand and others will ad one adenine and one cytosine residue
  • latter not ideal but it’s better than having replication stop completely
  • only 2% of genome contains protein-coding genes there’s 98% chance that AC pair will be located within a part of genome that does not code for protein
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7
Q

Polymerase Mistakes and Consequences

A
  • failure to correct mistakes in synthesis, end result is anomalous base pairing
  • if incorrect bases are not excised by DNA then they can become permanently incorporated into DNA of daughter cells
  • if these changes occur within regulatory regions (promoters and enhancers) could change expression pattern of gene
  • if changes occur within coding exon could change sequence of protein
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8
Q

Mismatch Repair System (What?)

A
  • tasked with following replication machinery during DNA synthesis and correcting mistakes made by DNA polymerase
  • bacterial version consists of MutS, MutL and MutH (additional proteins required are UvrD helicase, an exonnuclease, DNA polymerase and DNA ligase.
  • imperative for this system to fix distortions
  • if distortion made by DNA polymerase it will be permanently incorporated into genome of daughter chromosome
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9
Q

Mismatch Repair System (Process?)

A
  • when incompatible nucleotides are paired they make physical distortion in DNA double helix.
  • dimer of MutS proteins is continually scanning genome for mismatched nucleotide pairs
  • contact with physical distortion prevents MutS from continuing and induces conformational change within protein itself
  • MutS-DNA complex is sufficient to initiate repair of distortion
  • MutH generates a single-stranded nick within the newly synthesized strand
  • nick is made at the sequence GATC
  • four base sequence occurs on average every 256 bases
  • nick will be made (on average) roughly 256 bases away from the mismatched nucleotide pair and can be made 5 or 3 of the mismatched pair
  • single-strand nick is a signal for the cell to delete a portion of the DNA strand
  • in order to do this double helix must be unwound by UvrD helicase
  • unwound strand removed by exonuclease which removes DNA from the nick to the distortion
  • DNA polymerase fills in created gap and DNA ligase will seal polynucleotide chain via formation of phosphodiester bond
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10
Q

Strand Discrimination by MutH

A
  • in bacteria DNA methylation plays an important role in this process
  • in bacterial cells chromosomal DNA is methylated at GATC sequences by an enzyme called Dam methylase
  • prior to replication DNA is methylated on both strands
  • but during DNA synthesis newly synthesized strand is not immediately methylated therefore for a short period of time daughter duplexes contain methyl groups only on template strands (hemi-methylated DNA)
  • MutH recognizes and nicks the non-methylated strand
  • Eukaryotic DNA is not methylated to extent seen in bacteral systems so strand discrimination occurs via different mechanisms
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11
Q

Comparisons of Mismatch Repair System

A
  • has been identified in eukaryotic cells
  • similar to situation in prokaryotes, distortions in DNA that result from incompatible nucleotide base pairing are detected by homologs or MutS protein
  • eukaryotic genomes lack MutH homologs (makes double stranded nick)
  • eukaryotic homologs of MutL have acquired a nuclease domain which allows it to substitute for Mut H
  • not unheard of in prokaryotic world-few bacterial species have nuclease containing MutL homologs.
  • in these situations MutL is recruited to MutS-DNA complex and then makes a cut in newly synthesized DNA strand
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12
Q

Repetitive Sequences

A
  • DNA polymerase has trouble replicating regions of DNA that contain repetitive sequences.
  • errors that result often involve looping of either template strand or newly synthesized strand
  • if template strand loops out then newly synthesized strand will contain deletion
  • if new DNA strand loops out then new strand will be lengthened
  • addition or loss of nucleotides can often result in disruption of regulatory region or coding exon and can result in disease
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13
Q

Triplet expansion Diseases

A
  • one most studied examples of looping
  • ex: CAG sequence is repeated several times, if transcribed and translated properly this will code for protein that contains several Alanine amino acids.
  • if undergoes slippage then later after rounds of replication it is possible for this triplet to expand and for the protein to contain more than the normal number of alanine residues
  • results in several disorders like Huntington’s disease
  • caused by non-CAG type expansions
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