Exam 2 Lecture #2 (Enzyme Kinetics and Function) Flashcards
Draw a graph of the speed of an enzyme as a function of substrate concentration
Explain Km and Vmax
Vmax is the enzyme’s top speed
Km is [S] at 1/2 vmax
Km is related to affinity
low Km means high affinity for substrate
high Km means low affinity for substrate
Draw the reaction proceedings for a competitive inhibitor. How does a competitive inhibitor work?
How can you overcome competitive inhibition?
Competitive inhibitor binds reversible to the enzyme, depleting the population of enzymes that are able to bind to the substrate and make product.
This has the virtual effect of reducing the amount of substrate. Increasing the amount of substrate can overcome the competitive inhibition.
Draw the reaciton proceedings for a uncompetitive inhibitor. How does an uncompetitive inhibitor work?
Uncompetitive inhibition binds reversible to Enzyme Substrate complex. It does not help to increase the amount of substrate because inhibitor binds to ES.
Draw the reaction pathway for a mixed inhibitor. What does a mixed inhibitor do? What is a noncompetitive inhibitor?
Mixed inhibitor: inhibitor binds reversibly to enzyme AND enzyme substrate complex. The EI complex can also bind substrate and produce product, but at a slower rate.
A special example of mixed inhibition is a “noncompetitive inhibitor.” This binds equally well to both E and ES. This has the virtual effect of reducint the amount of enzyme.
Draw the Linweaver Burkplot for a Competitive Inhibor. What does a competative inhibitor do to Km and Vmax?
Competitive inhibitor increases Km. No change to vmax.
Draw the linweaver burkplot for an uncompetitive inhibitor. What does an uncompetitive inhibitor do to Km and Vmax?
Uncompetitive inhibitor: Decrease Km, Decrease Vmax
Draw the lineweaver burk plot for a noncompetitive inhibitor. What happens to Km and Vmax?
Noncompetitive Inhibitor: Vmax DECREASES, no change in Km
Draw the normal plot (enzyme velocity as a function of [S]) for the effects of a competitive inhibitor?
Competitive Inhibitor: Increase Km (reduces apparent affinity for substrate)
NO change in vmax
Draw a normal plot (velocity of enzyme as a function of [S]) for uncompetitive inhibition.
Uncompetitive inhibition: decreases both Km and Vmax
Draw a normal plot (enzyme velocity as a function of [S]) for noncompetitive inhibition.
Noncompetitive inhibition: decreases Vmax without changing Km
Explain what cooperativity means.
Cooperativity: Substrate binding increases the affinity for binding of more substrate
This can be due to multiple binding sites on the enzyme or multiple enzymes in a complex that interact with each other.
For Cooperativity and Hill’s coeffecient, what does it mean when Hill’s coeffecient = 1
Hill’s = 1 means NO COOPERATIVITY
What happens to cooperativity when Hill’s coeffectient is GREATER than 1
Hill’s coeffecient greater than one (example Hill’s = 2) means positive cooperativity.
What happens to cooperativity when Hill’s coeffecient is LESS than one
Hill’s < 1 means negative cooperativity
What are five ways that enzymes can be regulated? Name the five enzyme regulation mechanisms.
- covalent modification (eg. phosphorylation)
- allosteric control (eg ATP binding to a sensor)
- Enzyme concentration (eg gene expression increased to make more enzyme when needed)
- Activators and Inhibitors (adenylate cyclase activated by a G protein)
- Compartmentation (eg translocation of kinase to a specific target site to increase its effective activity and selectivity)