Exam 2 Flashcards

1
Q

What are the basic structures of an Amino Acid?

A
  1. amino group
  2. r-group
  3. carboxyl group
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2
Q

R-group

A

provides chemical identity
20 different amino acids = 20 different r-groups

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3
Q

what are the 3 categories of amino acids?

A
  1. hydrophobic (non-polar)
  2. hydrophilic (polar)
  3. charged (acidic and basic)
    * define how the protein folds
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4
Q

how are amino acids are joined to form a polypeptide?

A

peptide bond (covalent bond)

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5
Q

peptide bond

A

forms between the carboxyl group and the amino group

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6
Q

if a polypeptide has 3 peptide bonds how many amino acids are there?

A

4 amino acids

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7
Q

polypeptide

A

chain of amino acids

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8
Q

what are the 4 levels of protein structures of an amino acid?

A
  1. primary: linear sequence; polypeptide; peptide bonds
  2. secondary: alpha helix and beta pleated sheets; hydrogen bonds
  3. tertiary structure: 3D/ includes primary and secondary; interactions of R-groups
  4. quaternary structure: interactions of r-groups of two or more polypeptides; only observed in some proteins
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9
Q

5 types of interactions

A
  1. covalent bonds: contains disulfide bonds between cytosine)
  2. hydrogen bonds: between polar r-groups
  3. ionic bonds: between charged r-groups
  4. non-polar bonds: hydrophobic effect, between non-polar r-groups
  5. van der waals interactions: tiny interactions between close atoms
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10
Q

folding

A

refers to a protein acquiring its 3D structure that only happens 2 ways:
1. spontaneously: immersing protein in water
2. aid of proteins called CHAPERONINS

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11
Q

what happens when a protein is denatured?
how is it denatured?

A
  • looses its 3D shape, only primary remains and cannot carry out its functions
  • by applying high heat, low pH
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12
Q

what are the 3 components of a nucleotide?

A
  1. sugar: 5 carbons- pentose
  2. phosphate group: PO4^-3
  3. nitrogenous base: A, G, C, T, U
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13
Q

what are the 2 sugars used in nucleic acids?

A
  1. ribose- RNA
  2. deoxyribose- DNA
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14
Q

ribose

A
  • in RNA
  • always going to have two OH (hydroxyl) group (3’ and 2’)
  • OH in 2’ allows RNA to interact with others
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15
Q

deoxyribose

A
  • in DNA
  • only has on OH group in 3’
  • H atoms in 2’
  • absence of OH in 2’ it what keeps it stable
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16
Q

DNA vs RNA nucleotide

A

DNA: has deoxyribose, bases are A, G, T, and C

RNA: has ribose, bases are A, G, U, and C

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17
Q

prymidines

A
  • 1 ring
  • cytosine (both), thymine (DNA), and uracil (RNA)
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18
Q

purine

A
  • 2 ring
  • adenine and guanine
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19
Q

How are nucleotides joined together?

A

polymerization

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20
Q

polymerization

A
  • uses dehydration rx to form phosphodiester bonds (covalent)
  • the next nucleotide is added to the 3’ end
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21
Q

what is the structure of DNA?

A

double helix that forms two strands in antiparallel configuration

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22
Q

antiparallel configuration

A

connected with hydrogen bonds between bases using complementary base pairing

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23
Q

complementary base pairing

A

A - T
G - C

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24
Q

chargaff’s rule

A

% of A = % of T (2 H-bonds)
% of G = % of C (3 H-bonds)

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25
Q

what are the 5 levels of DNA

A

nucleotides (covalent bond) -> strand (phosphodiester bond) -> double helix (H-bond) -> chromosomes (DNA + proteins) -> genome (all genetic info)

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26
Q

RNA function

A

decodes information from DNA

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27
Q

what are the 3 types of RNA

A
  1. messenger RNA (mRNA): carry instructions for protein synthesis
  2. transfer RNA (tRNA): delivers amino acids for protein synthesis
  3. ribosomal RNA (rRNA): part of ribosome, protein synthesis
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28
Q

what are the 4 levels of RNA

A
  1. nucleotide: stabilized by covalent bonds
  2. strand: stabilized by phosphodiester bonds
  3. hairpin loop: section of the sequence that are complementary to each other, stabilized by H-bonds
  4. final 3D structure: stabilized by H-bonds, further folding
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29
Q

gene expression

A

explains how a gene becomes a protein
* translation and transcription

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30
Q

CENTRAL DOGMA

A

DNA (gene) -> transcription -> mRNA -> translation -> protein

31
Q

prokaryotic central dogma

A

DNA -> transcription -> mRNA -> translation -> polypeptide -> protein folding -> protein
* all of this occurs in the cytoplasm

32
Q

eukaryotic central dogma

A

nucleus: DNA -> transcription -> pre mRNA -> RNA processing -> exits nucleus -> mature mRNA -> translation -> polypeptide -> protein folding -> protein

33
Q

what are the exceptions to central dogma?

A

retroviruses (i.e., HIV)
1. RNA goes through REVERSE TRANSCRIPTION caused by an enzyme names reverse transcriptase
2. goes to DNA then mRNA and then protein `

34
Q

gene

A

function: segment of DNA that encodes for one protein that determines a characteristic in an organism

35
Q

transcription

A

The process in which a particular segment of DNA is converted into mRNA

36
Q

promoter

A

sequence in the gene that marks the location on the template strand where transcription starts

37
Q

terminator

A

sequence that signals the end of transcription

38
Q

template strand (non-coding)

A

DNA strand that the mRNA uses as a template

39
Q

coding strand (non-template)

A

DNA strand that has the same sequence as the mRNA (but you switch out T for U)

40
Q

what are the 3 stages of transcription

A
  1. initiation
  2. elongation
  3. termination
41
Q

initiation stage
(prokaryotic)

A
  • recognition
    -carried out by two proteins: sigma factor and RNA polymerase
  • sigma factor binds to polymerase and delivers it to promoter
  • polymerase binds to DNA and starts transcription
  • sigma goes on its own way
42
Q

sigma factor

A

protein found in bacteria that binds to RNA polymerase and delivers it to the promoter

43
Q

RNA polymerase

A

enzyme that synthesizes strands of RNA

44
Q

elongation stage
(prokaryotic)

A
  • synthesis of mRNA from 5’ to 3’
  • RNA polymerase creates an open complex
  • mRNA is complementary and antiparallel to template strand
45
Q

termination stage
(prokaryotic)

A
  • RNA polymerase reaches the terminator sequence and transcribes it
  • a hair pin loop forms in the mRNA
  • triggers the separation of DNA, mRNA, and RNA polymerase
46
Q

end of transcription in…

A

prokaryotic cells: mRNA is ready to be used
eukaryotic cells: at the end we have pre- mRNA that needs to be modified to mature mRNA

47
Q

transcription in eukaryotes

A

genes have coding (exons) and non-coding (introns) sequences that are not interspersed with each other

48
Q

RNA processing

A
  1. capping
  2. tailing
  3. splicing
49
Q

capping

A
  • adds a 5’ cap to the 5’ end of pre-mRNA
  • f(x): helps mRNA exit the nucleus, prevents degradation, and helps it bind to ribosome
50
Q

tailing

A
  • adds a Poly-A tail on the 3’ end of pre-mRNA
  • poly-a tail: string of A’s
  • f(x): prevents degradation
51
Q

splicing

A
  • removal of introns and connection of exons
  • splicesome (RNA + protein): in charge of splicing
52
Q

why do we need RNA processing?

A
  1. removes non-coding information
  2. we do not want the mRNA to lose sequence
53
Q

genetic code

A

a molecular dictionary that shows the correspondence between a sequence of nucleotides and a sequence of amino acids

54
Q

codon

A

a 3 nucleotide sequence in mRNA
* includes 64 codons
- 61 of those codons specify for an amino acid
- 1 codon specifies for start (AUG) = methionine (MET)
- 3 codons mean stop (UAA, UAG, UGA) -> does not code for amino acid

55
Q

what are the 4 characteristics of genetic codes?

A
  1. unambiguous
  2. redundant
  3. conservative
  4. universal
56
Q

unambiguous

A

each codon specifies to only 1 amino acid

57
Q

redundant

A

each amino acid can be specified by more than 1 codon

58
Q

conservative

A

codons that specify for the same amino acid share the first two bases

59
Q

universal

A

all organisms (living and extinct) rely on the genetic code
* exceptions: arthropods, yeast, mitochondria in mammals

60
Q

tRNA

A

f(x): delivers amino acid (1 at a time) to ribosome during protein synthesis

61
Q

anticodon

A

complementary sequence to a codon and antiparallel
f(x): determine which amino acid attaches to the 3’ of tRNA

62
Q

ribosomes

A
  • made of RNA and protein
  • f(x): carry out the synthesis of protein
  • 2 subunits: large and small
63
Q

large subunit

A

f(x): form peptide bonds between amino acids
- forms polypeptide
- has site E, A and P

64
Q

small subunit

A

f(x): bind to mRNA and hold it in place

65
Q

Site A
(amino-acyl site)

A

holds the incoming amino-acyl tRNA

66
Q

Site P
(peptidyl site)

A

where peptide bonds are formed

67
Q

Site E
(exite site)

A

holds uncharged tRNA

68
Q

amino-acyl tRNA

A

tRNA + amino acid
- also called a charged tRNA

69
Q

translation

A
  • synthesis of a protein
  • ribosome (cytoplasm)
  • mRNA (instructions)
  • tRNA + amino acids
70
Q

what are the 3 stages of translation?

A
  1. initiation
  2. elongation
  3. termination
71
Q

initiation (translation)

A
  • mRNA binds to small subunit using ribosomal binding sequence
  • initiator amino-acyl tRNA binds to the start codon
  • large subunit binds to small subunit
72
Q

elongation (translation)

A
  • tRNA in site P holds the growing polypeptide
  • mRNA is read in site A
  • the next amino-acyl tRNA enters through site A
  • peptide bond forms between last amino acid in the growing polypeptide and the next amino acid
  • TRANSLOCATION: ribosome moved 1 codon down 5’ to 3’
  • uncharged tRNA leaves site P through site E
  • the “new” tRNA moves to site P
  • the next tRNA enters site A with a new amino acid
  • cycle repeats until stop codon is reached
73
Q

termination (translation)

A
  • stop codon is reached in site A
  • stop codon attracts the protein release factor
    -bond between polypeptide and the last tRNA breaks
  • small and large subunit disconnects
    -mRNA is released
  • polypeptide folds into a protein