Electromagnetic Radiation and Quantum Phenomena Flashcards

1
Q

What is the Photoelectric Effect?

A

When light hits a metal’s surface, it is bombarded by photons. If one of these photons collide with a free electron, the bonds holding it to the metal break and the electron is released.

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2
Q

What are the conclusions of the Photoelectric Effect?

A
  1. no photoelectrons are emitted if the radiation has a frequency below a certain value.
  2. photoelectrons are emitted with a variety of kinetic energies
  3. the number of photoelectrons is proportional to the intensity of the radiation.
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3
Q

What is Threshold Frequency?

A

The minimum frequency of incident electromagnetic radiation required to remove a photoelectron from the surface of a metal.

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4
Q

What are the Assumptions of the Wave Theory of Light?

A
  1. energy carried is proportional to the intensity
  2. the energy carried by the light would be spread evenly over the wavefront
  3. Each free electron would gain a bit of energy from each incoming wave.
    meaning eventually each electron would gain enough energy to leave the metal.
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5
Q

What is the equation for photon energy?

A

E=hf

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6
Q

How did Einstein model light?

A

-He suggested that light can only exist in discrete packets. (photons)
-photons of light have one-to-one, particle-like interaction with an electron, transferring all its energy to that one specific electron only.

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7
Q

What is the Work Function?

A

the energy needed to break the bonds holding the electron down

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8
Q

what is the equation for work function?

A

work function = threshold frequency x h

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9
Q

what is the equation for maximum kinetic energy?

A

Ekmax = hf - work function

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10
Q

Why is the kineti energy of the electron independent to intensity?

A

they can only absorb one photon at a time

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11
Q

What is n=1?

A

ground state

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12
Q

What is the electronvolt?
- 1 eV in Joules?

A

the kinetic energy carried by an electron after it has bee accelerated through a potential difference of 1 volt.
- 1.6 x 10^-19 J

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13
Q

How do Fluorescent tubes use excited electrons to produce light?

A
  • Fluorescent tubes contain a mercury vapour, across which a high voltage is applied. When electrons collide with the fast moving free electrons, they’re excited to a higher energy level. When these excited electrons return to their ground states, they emit photons in the UV range. A phosphorus coating on the inside of the tube absorbs these photons, exciting its electrons to higher energy levels. Once these electrons de-excite, they emit lower energy photons in the visible light range.
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14
Q

What happens when you split light from fluorescent tubes with a prism or diffraction grating?

A

Line Emission Spectra

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15
Q

How is the line spectrum seen?
- What does each line represent?

A

-seen as bright lines against a black background.
- each line is a particular wavelength of light emitted.

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16
Q

How does Absorption Spectra occur?

A

Shining white light through a cool gas

17
Q

What is continuous spectra?

A

when you split light up with a prism, the colours merge into each other, there aren’t any gaps in the spectrum

18
Q

How is light shown as a wave?

A

Interference and Differaction

19
Q

How is light shown as a particle?

A

the photoelectric effect and one-to-one interactions

20
Q

What is de Broglie’s equation?

A

λ=h/mv

21
Q

How is the wave nature of electrons shown?
-example?

A

Electron diffraction
- when accelerated electrons in a vacuum tube interact with the spaces in a graphite crystal

22
Q

According to the wave theory of light, how does the spread of lines in a diffraction pattern increase?

A

increase the wavelength

23
Q

According to the wave theory of light, how does the spread of lines in electron diffraction increase?

A

smaller accelerating voltage, i.e slower electrons