cystic fibrosis Flashcards

1
Q

general information

A
  • a monogenic disease
  • fibrocystic disease of the pancreas
  • a malabsorption syndrome with chronic pulmonary infection
  • median survival >40 years.
  • carrier frequency 1 in 25 in Caucasian population
  • autosomal, recessive disease
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2
Q

different CF mutations

A

3 quarters of pateints hace same mutation: F508 in CFTR [a deletion of phenylalanine 508]. over 200 other CT mutations known.

  • screening for F508 is by PCR amplification of relevant CFTR region.
  • mutation frequencies vary geographically
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3
Q

clinical presentations

A

respiratory symptoms, often associated with respiratory infection.
malnutrition. steatorrhea. intestinal obstruction. electrolyte imbalance.

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4
Q

FVC- forced vital capacity

A

the amount of air that can be exhaled from a deep breath. in CF mean FVC is ~85% normal

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5
Q

FEV1

A

forced expiratory volume in 1 sec [of FVC test]. in CF mean FEV1 is ~72% of normal

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6
Q

CFTR gene

A

located on long arm of chromosome 7. encodes CFTR- the 1480aa cystic fibrosis transmembrane conductance regulator. chloride transporter

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7
Q

what is CFTR

A

an epithelial chloride channel:

  • Na+ reabsorption normally accomplished by an active Na+,K+-ATPase
  • failure to transport Cl- in the same direction as Na+ results in membrane hyperpolarization leading to reduced Na+ transport. sweat of sufferers tastes salty
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8
Q

possible defects in CFTR

A
  • defective assembly/ folding leading yo reduced cell-surface protein levels. lack of CFTR leads to severe effect
  • failure of chloride channel opening- defective ATP binding- dyregulation of channel opening
  • altered chloride transport- mutations in membrane-spanning region result in symptoms of variable severity
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9
Q

delta-F508 mutation

A

deletion of 3bp [CTT] in 10th exon of the CFTR gene. product is missing single aa [i.e. no frame-shift] but stability and surface expression significantly reduced.

delta is shorthand for deletion

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10
Q

PCR test for delta-F508 mutation

A

WT- 97bp
heterozygote carrier- 97bp and 95bp
homozygote CF sufferer [94bp].
if negative for this test, chanced of being CF carrier reduced to 1:100

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11
Q

amplification refractory mutation system [ARMS]

A

relies on the absolute requirement for complementary at 3’ end of PCR primers. primers match: product formed and vice versa

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12
Q

PCR basic steps

A

1) denaturation: 2 sreands of DNA separated [melt down] to form single stranded DNS
2) annealing: annealing of primer to each strand
3) extension: DNA polymerase adds dNTPs complementary to templates strands at 3’end of primer.
4) step 1-3 repeat cycle 35-40 times

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13
Q

a primer

A

a primer is a short oligonucleotide which is the reverse complement of a region of a DNA template. it would anneal to a DNA strand to facilitate the amplification of the targeted DNA sequence

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14
Q

designing a PCR primer

A

1) primers are complementary to their target sequences, and both forward and reverse primers should be written 5’ to 3’
2) primers tend to be >15nt
3) the part that matches the target sequence should have a melting temperature [Tm]
of around 50-65C
4) [A+T]
2 + [G+C}*4=Tm in degrees centigrade

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