Chapter 4: Electrolysis Flashcards
What is electrolysis?
the breakdown of an ionic compound, molten or in an aqueous solution, by the passage of electricity.
What is an important feature of the electrolysis substance?
the substance needs to be molten or dissolved in something.
What are the two electrodes in electrolysis called?
anode (+)
cathode (-)
What is the molten or dissolved substance called and what is it’s purpose?
It’s called the electrolyte and it’s purpose is to conduct the electricity which is why it needs to be molten so that we have mobile ions moving around.
When can we electrolyze molten compounds?
only if they are ionic.
What happens at the cathode during the electrolysis of molten lead (ii) bromide?
Lead cations move to cathode
they pick up electron and discharge to form molten lead
Pb2+ (l) +2e- —> Pb (s)
Reduction at cathode
What happens at the anode during the electrolysis of molten lead (ii) bromide?
bromide ions move to anode
they loose electrons and discharge becoming neutral bromine gas
2Br- (l) —> Br2 (g) + 2e-
oxidation at anode
What happens at the anode during the electrolysis of concentrated sodium chloride solution?
anions (Cl- and OH-) move to anode
Cl- ions oxidize
OH- ions remain in solution
2Cl- —> Cl2 + 2e-
What happens at the cathode during the electrolysis of concentrated sodium chloride solution?
cations (Na+ and H2) move to cathodes
H+ ions reduce by discharging
Na+ ions stay on the solution
2H+ + 2e- —> H2
How do you tell which type of ion will be discharged at the cathode on a dissolved substance?
-ions of reactive metals will stay in solutions
-less reactive metals discharge and reduce at cathode to form a metal solid
How do you tell which type of ion will be discharged at the anode on a dissolved substance?
-usually OH- ions discharge and oxidize to form oxygen gas
-UNLESS… the ion from the compound is a halide then the halide discharges and oxidizes.
Electrolysis of hydrochloric acid:
at cathode: 2H+ +2e- —> H2
at anode: 2Cl- —> Cl2 +2e-
Electrolysis of dilute sulfuric acid:
at cathode: 2H+ + 2e- —> H2
at anode: 4OH- —> 2H2O + O2 + 4e-