Chapter 4: Compounds and Stiochiometry Flashcards
Combination reaction
A + B → C
Decomposition reaction
A → B + C
Combustion reaction
oxidation (using O2 or similar) of a fuel (typically hydrocarbon
1 mole of any ideal gas at STP
22.4 L
1 mole of any substance
6.022 x 10^23 particles (Avogadro’s number)
1 mole of any substance
its molar mass in grams (from the periodic table)
Moles from mass
Moles = mass of a sample / molar mass
Gram equivalent weight
GEW= molar mass/ n
n = the number of particles of interest
Equivalents from mass
Equivalents = mass of compound / gram equivalent weight
Molarity from normality
Molarity = normality / n
n = the number of particles of interest
Percent Composition
% composition = [mass of elements in formula / molar mass ] x 100%
Percent yield
% yield = [actual yield / theoretical yield] x 100%