Chapter 3 - Complex numbers Flashcards

1
Q

Consider the two complex numbers z1 = (3a+2) + j(3b-1) and z2 = (b+1) - j(a+2-b).

If the two complex numbers are equal, what can we say about the real and imaginary parts of the complex numbers?

Describe in a few steps how to find a and b.

A

Since the two complex numbers are equal, z1’s and z2’s real pars must be equal, and their imaginary parts must be equal:

(3a+2) = (b+1)

and

(3b-1) = (a+2-b).

  1. What we have is a set of equations with the same variables, so we can manipulate the equations to get e.g. b alone on one side to describe it in terms of a, and implement the result in the other equation.
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2
Q

How to you add and subtract complex numbers?

E.g. z1 = 3 + j2 and z2 = 4 + j6.

A

You add/subtract two complex numbers by adding/subtracting their real parts together, and their imaginary parts together.

In this example, z1 + z2 = (3+4) + j(2+6) = 7 + j8.

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3
Q

How do you multiply two complex numbers?

E.g. z1 = 3 + j2 and z2 = 4 + j6.

A

When multiplying two complex numbers, the normal rules for multiplying out brackets hold.

In this example:

z1 * z2 = 3*4 + 3*j6 + j2*4 + j2*j6

= 12 + j18 +j8 + j212

= 12 + j26 + (-12)

= j26

(j2 equals -1)

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4
Q

What is the complex conugate of z = x + jy?

A

You get the complex conjugate by changing the sign of the imaginary part of z:

z = x + jy

z* = x - jy

(The complex conjugate is denoted by * (z*)).

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5
Q

How do you divide two complex numbers?

E.g. z1 / z2 = (x1+jy1) / (x2+jy2)

A

You multiply both the numerator and the denominator with the conjugate of the denominator:

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6
Q

Given the complex numbers z = x + jy and z* = x - jy,

complete these basic complex conjugate rules:

z + z* =

z - z* =

zz* =

(z1z2)* =

A

z + z* = 2x = 2 Re(z)

z - z* = 2jy = 2j Im(z)

zz* = (x + jy)(x - jy) = x2 + y2

(z1z2)* = z1*z2*

From the next to last result we can see that the product of a complex number and its complex conjugate is a real number.

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7
Q

What are the modulus and the argument of a complex number z?

A

The modulus of z is the length of OP (from (0,0) in the Argand diagram to the point of z). It’s denoted as “mod z” or |z|.

The argument of z is the angle between the positive real axis and OP. It’s denoted as “arg z”.

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8
Q

Consider z and r in an Argand diagram.

|z| = r can also be described as:

A

|z| = r = sqrt(x2+y2)

Note that the modulus of z is the square root of the sum of squares of x and y, NOT of x and jy. The j part of the number has been accounted for in the representation of the argand diagram.

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9
Q

The figure shows that the relationships between (x, y) and (r, Ø) are:

x = r cos Ø and y = r sin Ø

Hence the complex number z = x + jy can be expressed in the form (which is called(?)):

A

The polar form of the complex number:

z = r cos Ø + jr sin Ø = r(cos Ø + j sin Ø).

In engineering, it is frequently written as in the picture.

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10
Q

Consider the two complex numbers in polar form:

z1 = r1(cos Ø1 + j sin Ø1)

z2 = r2(cos Ø2 + j sin Ø2).

How do you multiply them?

A

The regular rules of multiplying complex numbers also apply when the numbers are given in polar form.

z1z2 = r1r2 (cos Ø1 + j sin Ø1)(cos Ø2 + j sin Ø2)

= r1r2 (cos(Ø12) + j sin(Ø12)).

Hence:

|z1z2| = r1r2 = |z1| |z1|

and

arg(z1z2) = Ø1 + Ø2 = arg z1 + arg z2

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11
Q

What is the representation of the imaginary number j on polar form?

A
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12
Q

How do you divide two complex numbers?

A
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13
Q

Describe Euler’s formula (picture)

A

eeeeh Euler’s formula (picture) links the exponential and circular functions.

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14
Q

How do you define the logarithm of a complex number?

A

ln z = ln |z| + j arg z

(ln |z| + j arg z + j2nπ, n = 0, +- 1, +- 2 etc.)

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15
Q

Define zn and z-n in terms of sine and cosine

A

zn = cos + j sin

and

z-n = cos nØ - j sin

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16
Q

Given the definitions of zn and z-n in terms of sine and cosine, complete the two equations:

zn + z-n =

zn - z-n =

A

zn + z-n = 2 cos

zn - z-n = 2j sin

Using these results, cosnØ and sinnØ can be expressed in terms of sines and cosines of multiple angles.

17
Q

Define de Moivre’s theorem

A

A complex number z may be expressed in terms of its modulus r and argument Ø in the exponential form

z = r ej<em>Ø</em>

Using the rules of indices and the property of the exponential function, we have, for any n,

zn = rn(e)n = rn ej(nØ)

so that (picture (de Moivre’s theorem)

18
Q

Manipulate de Moivre’s theorem to find z1/n expressed in polar form

A