Chapter 24 Particle physics Flashcards

1
Q

What was Thompson’s original model of the atom , plum pudding , features (2)

A

The atom was a cloud of POSITIVE CHARGE, with negative electrons dotted around
- the atom was overall NEUTRAL everywhere

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
2
Q

So what did Rutherford exoeieemnt to try prove / disprove Thompson model entail

A

To fire alpha particles which are positive being helium nuclei at thin sheet of gold foil.

Observations would be collected on thr positon of where they ended up, using an observer that could measure the angle

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
3
Q

If Thompson model correct what was expected to happen when alpha particles were fired through

And why!

A

Because the charge was supposedly neutral overall, the alpha particles weren’t supposed to be deflected at all and PASS STRAIGHT THROUGH

However as some were deflected, we now know to reject this model

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
4
Q

What instead happened in the alpha scattering experiment, what three key observations were made

A

Instead if all passing through

1) most past through
2) about 1 / 2000 were deflected by a small angle
3) 1/10000 were deflected more than 90° back

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
5
Q

Explain what the observations meant and how it changed rhe model

A

1) most of the particles going through = the atom was mostly empty space
2) the fact that some got deflected a bit = there is some mass in the centre of the atom , most of the mass = nucleus . Fact that most went through means most of the mass must be concentrated in the middle

3) the fact some deflected 90 = the mass in the centre must be POSITIVE

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
6
Q

Why does the third observation explain that nuckeus had to be positive and not the second?

A

This is because even if the nucleus was negative, then there would be some small deflection as it gets ATTRACTED to the nucleus and deflected from straight path

But the atoms would not be completely rebounded, if the nuckeus was negative. This can ONLY HE ACHIEVED DUE TO REPULSION, AND THUS THE NUCLEUS MUST BE POSITIVE

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
7
Q

What are considerations of the alpha particle source

4 reasons!

A

1) each particle must have same speed as the slower ones would be deflected more (more time to be deflected)
2) chamber must be vacuum or they will be stopped by air molecules different amounts
3) foil must be ideally one sheet thick so multiple scatterings don’t happen
4) half life of thr source must be long enough so that later readings don’t disappear due to radial active decay

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
8
Q

Summary of alpha scattering
- objective
- observations
- conclusions

Considerations for experiment

A

Objective
To disprove Thompson, if this moons correct alpha particles go straight through if the charge overall neutral

Observations
1) most went straight through
2) 1/2000 deflected by small angle
3) 1/10000 deflected by more than 90°

Conclusions
1) most of atom empty space
2) there is some mass in the centre, most of the mass cocnentrsted there = nucleus
3) musr be positive if some deflected 90° back, otherwise did negative it would’ve been attracted and none would come complete way back

Considerations about alpha source
1) same speed or slower ones will be deflected more
2) gold sheet ideally one atom thick so doesn’t get deflected more than once
3) vacuum so not bump into air molecules
4) half life long enough ti record without decaying

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
9
Q

How ti use method of CLOSEST APPROACH in two ways to estimate the UPPER LIMIT of radius of an atom , usign gold experiment

A

1) usign energy ideas
- an alpha particle travelling at a certain KE, would be transferred fully to EPE when it MOMENTARILY STOPS and starts to get deflected.
- thus = 1/2mv2 to Qq/4 pi e0 r, and rearrange ti find the closest approach

2) using potential ideas
- at the closest distance, the potential of both particles will be the same, nuckeus and alpha
- so equate them and find the distance r

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
10
Q

What’s the problem about using closest approach? (2 ) big problems

A

-Is that more energetic alpha particles with higher energy will get closer to the atom
- only takes into account protons , due to their repulsion, whereas an isotope of an atom will have a bigger radius , but these calculations ignoring the neutrons will ignore this tok

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
11
Q

What was misconception to why distance if closest approach gives radius of nuckeus rather than atom?

A

Distance if closest approach means the nuclei can pretty much TOUCH EACH OTHER, thus it refers to the radius of the nuckeus rather than the radius of the atom

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
12
Q

Why did Rutherford exepiekrn give an upper limit, why is the nuckeus of the radius actually smaller?

A

Because he used the natural max ke an alpha particle could have , and thus the distance was a certain amount.

More energetic alpha particles will get closer, thus the actual raidus / diameter will be shorter, but it will be maximum 10-14 which he concluded at least

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
13
Q

So what is the radius tuehrrford concluded and what is the acc raidus of nuckeus and atom

A

Radius Rutherford nucleus = 10^-14
Radius actual with more energetic alpha = 10^-15

Radius nuckeus is 10^-10, thus atom is 100000 bigger

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
14
Q

What is the equation for raidus of a NUCLEUS

A

R = ro x A ^1\3

Wheee Ro is a cinstsnt

As you can see the higher the nucleon number rhe higher the radius

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
15
Q

What is the mass of a nuckeus gonna be

A

As neutron and proton roughly have same mass = 1u

Mass gonna be nucleon number x u = AU

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
16
Q

So what is density of all nuckei pretty much

A

It’s a cinstsnt due to things cancelling out

Use d = m/v, AU/ 4/3 pi r3

Where r = r0x A^1\3

See they cancel down!

17
Q

What’s the density of an atom then how to work out ?

A

We know the mass as AU

And volume gonna be 4/3 pi r 3, this time r is roughly 10^-10 meters!

18
Q

What’s is femto meter prefix

A

10^-15

19
Q

Why does graph of ln R against ln A have a y intercept when R against A ^1\3 is straight through origin (use r equation)

A

Natural logging gives you a constant ln Ro which is y intercept

20
Q

Take a look closer into the helium nuckeus of two protons and two neutrons

What two forces we know of acting on it
- is it possible for the nuckeus to remain stable with these two forces alone?

A

1) electric force of repulsion by coloumb law = 230N
2) gravatioanl force of attraction which is negligible between the two masses

Thus question is surely the grav can’t balance the reclusion alone what else acts on it?

21
Q

The string nuclear force is the extra force that’s in play between nucleons . What is it

A

It is a force that acts over very short distances, max till 3fm
- it’s what simultaneously prevents the nucleons from being repelled from each other,
- but also from them getting TOO CLOSE TO EACH OTHER TOO

22
Q

What is the nature of the string nuclear force (ranges)

How does this show on a GRAPH (+-?)

A

From 0 to 0.5 fm distance, it is REPULSIVE

From 0.5 fm to 3fm, it is ATTRACTIVE

And it tends to 0N passed 3 fm

2) on a graph of force vs distance it goes positive to negative to 0, this is because psotive force means REPULSION and negative means ATTRACTION remember!

23
Q

So how does nature if string nuclear force explain why the nucleons are stable in helium

A

As the distance between protons is 1 fm, the force acting by string nuclear is ATTRACTIVE, and this is what manages to counter the electrostatic force of repulsion, keeping it stable!

  • the fact that it’s repulsive from 0.5 onwards PREVENTS the particles from getting too close and crashing into each other
24
Q

Again how are the nucleons prevented from crashing into each other?

A

String nuclear force less then 0.5fm is repulsive so they don’t crash