Ch 17 and 18 Flashcards

You may prefer our related Brainscape-certified flashcards:
1
Q

In a research article about alkaptonuria published in 1902, Garrod suggested that humans inherit two “characters” (alleles) for a particular enzyme and that both parents must contribute a faulty version for the offspring to have the disorder. Today, would this disorder be called dominant or recessive?

A

Recessive

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
2
Q

What polypeptide product would you expect from a poly-G mRNA that is 30 nucleotides long?

A

A polypeptide made up of 10 Gly (glycine) amino acids

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
3
Q

The template strand of a gene contains the sequence 3’-TTCAGTCGT-5’. Draw the nontemplate sequence and the mRNA sequence, indicating 5’ and 3’ ends of each. Compare the two sequences.

A

Template sequence (from problem): 3’-TTCAGTCGT-5’ Nontemplate sequence: 5’-AAGTCAGCA-3’ mRNA sequence: 5’-AAGUCAGCA-3’ The nontemplate strand and mRNA nucleotide sequences are the same except that there is T in the nontemplate strand of DNA wherever there is U in the mRNA.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
4
Q

Imagine that the nontemplate sequence in question 3 was transcribed instead of the template sequence. Draw the mRNA sequence and translate it using Figure 17.5. (Be sure to pay attention to the 5’ and 3’ ends.) Predict how well the protein synthesized from the nontemplate strand would function, if at all.

A

“Template Sequence” (from nontemplate sequence in problem, written 3’ to 5’): 3’-ACGACTGAA-5’ mRNA sequence: 5’-UGCUGACUU-3’ Translated: Cys-STOP-Leu (Remember that the mRNA is antiparrallel to the DNA strand.) A protein translated from the nontemplate sequence would have a completely different amino acid sequence and would most likely be nonfunctional. (It would also be shorter because of the stop signal shown in the mRNA sequence above- and possibly others earlier in the mRNA sequence.)

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
5
Q

Compare DNA polymerase and RNA polymerase in terms of how they function, the requirement for a template and primer, the direction of synthesis, and the type nucleotides used.

A

Both assemble nucleic acid chains from monomer nucleotides whose order is determined by complimentary base pairing to a template strand. Both synthesize in the 5’to3’ direction,antiparallel to the template. DNA polymerase requires a primer, but RNA polymerase can start a nucleotide start a nucleotide from scratch. DNA polymerase uses nucleotides with the sugar deoxyribose and the base T, whereas RNA polymerase uses nucleotides with the sugar ribose and the base U.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
6
Q

What is a promoter, and is it located at the upstream or downstream end of a transcription unit?

A

The promoter is the region of DNA to which RNA polymerase binds to begin transcription, and it is at the upstream end of the gene (transcription unit).

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
7
Q

What enables RNA polymerase to start transcribing a gene at the right place on the DNA in a bacterial cell? In a eukaryotic cell?

A

In a bacterial cell, RNA polymerase recognizes the gene’s promoter and binds to it. In a eukaryotic cell, transcription factors mediate the binding of RNA polymerase to the promoter. In both cases, sequences in the promoter bind precisely to the RNA polymerase, so the enzyme is in the right location and orientation.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
8
Q

Suppose X-rays caused a sequence change in the TATA box of a particular gene’s promoter. How would that affect transcription of the gene?

A

The transcription factor that recognizes the TATA sequence would be unable to bind, so the RNA polymerase could not bind and the transcription of that gene probably would not occur.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
9
Q

How can human cells make 75,000-100,00 different proteins, given that there are about 20,000 human genes?

A

Due to alternative splicing of exons, each gene can result in multiple different mRNAs and can thus direct synthesis of multiple different proteins.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
10
Q

How is RNA splicing similar to editing a video? What would introns correspond to in this analogy?

A

In editing a video, segments are cut out and discarded (like introns) and the remaining segments are joined together (like exons) so that the regions of joining (“splicing”) are not noticeable.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
11
Q

What would be the effect of treating cells with an agent that removed the cap from mRNAs?

A

Once the mRNA has exited the nucleus, the cap prevents it from being degraded by hydrolytic enzymes and facilitates its attachment to ribosomes. If the caps were removed from all mRNAs, the cell would no longer be able to synthesize any proteins and would probably die.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
12
Q

What two processes ensure that the correct amino aid is added to a growing polypeptide chain.?

A

First, each aminoacyl-tRNA synthetase specifically recognizes a single amino acid and attaches it only to an appropriate tRNA. Second, a tRNA charged with its specific amino acid binds only to an mRNA codon for that amino acid

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
13
Q

Discuss the ways in which rRNA structure likely contributes to ribosomal function.

A

The structure and function of the ribosome seem to depend more on the rRNAs than on the ribosomal proteins. Because it is single-stranded, an RNA molecule can hydrogen bond with itself and with other RNA molecules. RNA molecules make up the interface between the two ribosomal subunits, so presumably RNA-RNA binding helps hold the ribosome together. The binding site for mRNA in the ribosome includes rRNA that can bind the mRNA. Also, complementary bonding within an RNA molecule allows it to assume a particular 3-dimensional shape and , along with the RNA’s functional groups, presumably enables rRNA to catalyze peptide bond formation during translation.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
14
Q

Describe how a polypeptide to be secreted is transported to the endomembrane system.

A

A signal peptide on the leading of the polypeptide being synthesized is recognized by signal-recognition particle that brings the ribosome to the ER membrane. There the ribosome attaches and continues to synthesize the polypeptide, depositing it in the ER lumen.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
15
Q

Draw a tRNA with the anticodon 3’-CGU-5’. What two different codons could it bind to” Draw each codon on an mRNA, labeling all 5’ and 3’ ends. Add the amino acid carried by this tRNA.

A

Because of the wobble, the tRNA could bind to either 5’-GCA-3’ or 5’-GCG-3’, both of which code for alanine (Ala). Alanine would be attached to the tRNA

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
16
Q

What happens when one nucleotide pair is lost from the middle of the coding sequence of a gene?

A

In the mRNA, the reading frame downstream from the deletion is shifted, leading to a long string of incorrect amino acids in the polypeptide, and in most cases, a stop codon will arise, leading to premature termination. The polypeptide will most likely be nonfunctional.

17
Q

Individuals heterozygous for the sickle-cell allele are generally healthy but show phenotypic effects of the allele under some circumstances. Explain in terms of gene expression.

A

Heterozygous individuals,said to have sickle-cell trait, have a copy each of the wild-type allele and the the sickle-cell allele. Both alleles will be expressed, so these individuals will have both normal and sickle-cell hemoglobin molecules. Apparently, having a mix of the two forms of β-globin has no effect under most conditions, but during prolonged periods of low blood oxygen (such as at higher altitudes) , these individuals can show some signs of sickle-cell discease.

18
Q

The template strand of a gene includes this sequence: 3’-TACTTGTCCGATATC-5’. It is mutated to 3’TACTTGTCCAATATC-5’. For both normal annd mutant sequences, draw the double-stranded DNA, the resulting mRNA, nad hte amino acid sequence each encodes. What is the effect of the mutation on the amino acid sequence?

A

Normal DNA sequence (template strand is on top): 3’-TACTTGTCCGATATC-5’

5’-ATGAACAGGCTATAG-3’

mRNA sequence: 5’-AUGAACAGGCUAUAG-3’

Amino Acid sequence:Met-Asn-Arg-Leu-STOP

Mutated DNA sequence (template strand is on top):

3’TACTTGTCCAATATC-5’

5’-ATGAACAGGTTATAG-3’

Amino Acid sequence: Met-Asn-Arg-Leu-Stop

No effect: the amino acid sequence is Met-Asn-Arg-Leu both before and after the mutation because the mRNA codons 5’-CUA-3’ and 5’-UUA-3’ both code for Leu. (The fifth codon is a stop codon.)

19
Q

Would the coupling of processes shown in Figure 17.25 be found in a eukaryotic cell? Explain.

A

No, transcription and translation are seperated in space and time in a eukaryotic cell, a result of the eukaryotic cell’s nuclear compartment.

20
Q

In eukaryotic cells, mRNAs have been found to have a circular arrangement in which proteins hold the poly-A tail near the 5’ cap. How might this increase translation efficiency?

A

When one ribosome terminates translation and dissociates, the two subunits would be very close to the cap. This could facilitate their rebinding and initiating synthesis of a new polypeptide, thus increasing the efficiency of translation.

21
Q

How does the binding of *trp *corepressor and the lac inducer to their respective repressor proteins alter repressor function and transcription in each case?

A

Binding by the trp corepressor (tryptophan) activate the trp repressor, shutting off transcription of the trp operon ; binding by the lac inducer (allolactose) inactivates the lac repressor, leading to the transcription of the lac operon.

22
Q

Describe the binding of RNA polymerase,repressors,and activators to the lac operon when both lactose and glucose are scarse. What is the effect of these scarcities on transcription of the lac operon?

A

When glucose is scarce, cAMP os bound to CAP and CAP is bound to the promoter, favoring the binding of RNA polmerase. However, in the abscence of lactose, the repressor is bound to the operator, blocking RNA polymerase binding to the promoter. Therefore, the operon genes are not transcribed.

23
Q

A certain mutation in *E.coli *changes the lac operator so that the active repressor cannot bind. How would this affect the cell’s production of β-galactosidase?

A

The cell would continuously produce β-galactosidase and the two other enzymes for lactose utilization, even in the abscence of lactose, thus wasting cell resources.

24
Q

In general, what is the effect of histone acetylation and DNA methylation on gene expression?

A

Histone acetylation is generally associated with gene expression, while DNA methylation is generally associated with lack of expression.

25
Q

Compare the roles of general and specific transcription factors in regulating gene expression.

A

General transcription factors function in assembling the transcription initiation complex at the promoters for all genes. Specific transcription factors bind to control elements associated with a particular gene and, once bound, either increase (activators) or decrease (repressors) transcription of that gene.

26
Q

Suppose you compared the nucleotide sequences of the distal control elements in the enhancers of three genes that are expreessed only in muscle tissue. What would you expect to find? Why?

A

The three genes should have some similair or identical sequences in the control elements of their enhancers. Because of this similarity , the same specific transcription factors in muscle cell could bind to the enhancers of all three genes and stimulate their expression coordinately.

27
Q

Once mRNA encoding a particular protein reahces the cytoplasm, what are the four mechanisms that can regulate the amount of the protein that is active in the cell?

A

Degradation of the mRNA, regulation of translation, activation of the protein (by chemical modification, for example), and protein degradation.

28
Q

Examine figure 18.11 and suggest a mechanism by which the yellow activator protein comes to be present in the liver cell but not in the lens cell.

A

Expression of the gene encoding the yellow activator (YA) must be regulated at one of the steps shown in Figure 18.6. The YA gene might be transcribed only in liver cells because the necessary activators for the enhancer of the YA gene are found only in liver cells,

29
Q

As you learned in chapter 12, mitosis gives rise to two daughter cells that are genetically identical to the parent cell. Yet, you, the product of many mitotic divisions, are not composed of identical cells. Why?

A

Cells undergo differentiation during embryonic development, becoming different from each other; in the adult organism, there are many highly specialized cell types.

30
Q

Explain how the signalling molecules released by an embryonic cell can induce changes in a neighboring cell without entering the cell.

A

By binding to a receptor on the receiving cell’s surfaceand triggering a signal transduction pathway, involving intracellular molecules such as second messengers and transcription factors that affect gene expression.

31
Q

Why are fruit fly maternal effect genes also called egg-polarity genes?

A

Because their products, made and deposited into the egg by the mother, determine the head and tail ends, as well as the back and belly, of the embryo (and eventually the adult fly)

32
Q

In the blowup box in figure 18.17b , the lower cell is synthesizing signalling molecules, whereas the upper cell is expressing receptors for these molecules. In terms of gene regulation, eplain how these cells came to synthesize different molecules.

A

The lower cell is synthesizing signalling molecules because the gene encoding them is activated, meaning that the appropriate specific transcription factors are binding to the gene’s enhancer. The genes encoding these specific transcription factors are also being expressed in this cell because the transcription activators that can turn them on were expressed in the precursor to this cell. A similair explanation also applies to the cells expressing the receptor proteins. This scenario began with specific cytoplasmic determinants localized in specific regionsof the egg. These cytoplasmic determinants were distributed unevenly to daughter cells, resulting in cells going down different development pathways.