amaroso practice questions Flashcards

1
Q

A new zintyl phase was prepared by the reduction of tin with sodium in liquid
ammonia.
The compound was found to have an elemental composition of:
% Sn, 92.07; %Na, 7.93.
Mass spectrometry indicated that the anionic cluster has an average mass of 1068.3 a.m.u.
Give the structure of the anionic cluster. [8]

A
  • zintyl means cations and anions
  • so think of what is ur cation and what is ur anion
  • using the one with most info ,, try find how many of them are there
  • and then u need to find its charge,, and to find its charge u need to find out how many of the other one there is.
  • do think by working out how much 100% weighs
  • once u have the number of the species and the charge,, u can apply wades rules to it.
  • Sn is normally sp hybridised so 1 e- in the p orbitals and then an electron pair in an sp orbital,, meanign it gives 2e- for cluster bonding.
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2
Q

how do u figure out how many electrons smt has for cluster bonding,, use BH and CH as examples

A

BH = 3 valence electrons, but u use one of them to bond to the H,, so u have 3-1 so u have 2e- for cluster bonding.

CH = C has 4 valence electrons,, it uses one of them to bond with H,, so 4-1 = 3 ,, so CH gives u 3 electrons for cluster bonding.

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3
Q

are Boron Boron or Boron Carbon bridges preferred

A

boron boron bridges are preferred!!!

over than BC,, so if u need to add more hydrogens,, they do to the BB sides

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4
Q

what do we never see bridging between

A

we never see bridging between Carbon Carbon!!! unless we have to

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5
Q

when we want to see how many isomers there are of something,, what can we do to see,,, aka for the pentagonal bipyramid structure,, how many different isomers can there be if we have C2B4H8

A

if we have all those atoms we have 3 different isomers!!!

we can have a C at the 1 and then the 2 position.

we can have a C at the 2 and 3 position

we can have a C at the 2 and 4 position.

the last two are different bc tu have a CC bond in one but not in the other.

aka to see if things are different isomers,, u can look at if they have the same number of identical bonds,

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6
Q

when we’re asked to do the Boron nmr and we have 3 different boron environments,,, what do we need o do

A

we just need to be careful and make sure we acc figure out how many B environments there are.

bc we dont need to split the B’s with the B’s.

so if u just have 1 boron environment u get 1 singlet.

if u have 2 boron environments u get 2 singlets

if u have 3 boron environments u get 3 singlets

we dont need to do Boron Boron coupling,, bc its too complex

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7
Q

when we figure out the wade structure of a complex,, and we want to figure out how many peaks we get,,what do we ignore

A

we ignore Boron Boron coupling,, its too complex so we just say theyre singlets

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8
Q

when u have a 13C at the apex and a 13C at the bottom shape,, do these split a B// another atom by different amounts

A

yesss

they split the B by different amounts

so if a B is 1J bonded to 2 x 13C,, one in the apex and one in the bottom shape,, what will we see in B spec

u will see a doublet of doublets!! bc the first 13C splits it into a doublet and then the second 13C also splits the doublet into a doublet,, so u get a doublet of doublets

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9
Q

somthing being isolobal means what

A

it means their frontier orbitals have similar energy and therefore similar symmetry.

theyre also isoelectronic meaning the same number of valence electrons

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10
Q

when we have a metal carbonate as one of out compounds for a structure,, how do we figure out how many e- it donates for cluster bonding

A

CO gives 2 electrons,, and normally its (CO)3 so u do 2x3 = 6

and then u do the metal d electron count - 6
to figure out how many u have for cluster bonding

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11
Q

whats a zintyl compound thingy

A

an Sn and a p block element

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12
Q

when doing wades rules what do u need to rmemeber

A

after u divide by 2 u need to -1!!!!!

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13
Q

when u have a tricapped trigonal prism,, and 1 have 1 random atom, how many isomers can u make

A

u can have 2 diff isomers,, either with the random atomas a cap or the random atom as part of a prism.

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14
Q

boranes are made up of BH units,, describe the hybridisation of boranes

A

B is sp3 hybridised!!

meaning it has 2 sp orbitals,, remmeber the diff phasing for each bit of the orbital

and then it has 2 p orbitals

BH,, B is obvs sp and the small bit of the sp orbital is in phase with the H, the larger sp orbital bit we label as radial,, the 2 P orbitals we label as transgential

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15
Q

when ur doing the molecular formula from the analysis thing,,, when it doesnt add up to 0 what do u need to do

A

the part that missing goes to oxygen!!1

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16
Q

in the molecular analysis thing,, when u have Fe and C and O,, what do we nroamlly say it is

A

we says its Fe(CO)3

17
Q

up to now whenever theres been like 4.38 H’s we count it as how many

A

weve been rounding up no matter what

18
Q

how do we know PH gives 4 e- in the fragment.

A

we see P is in group 5, then it uses 1 to bond to H so u have 5-1 = 4.

19
Q

Explain what the Schlenk equilibrium for Mg alkyl species is and how it
can be confirmed

A

2MgRX <—> MgR2 + MgX2

u can use Mg NMR to confirm each species,,

theres an equilibrioum so taking the NMR we can see what theres more of using the peak chem shift.

u normally get an Mg-R-Mg bridge and u can get ligand exchange due to this

Mg-R-Mg bridge is usually 3c-2e,, like Al2Me6 or B2H6,, bc Mg is in group 2, meaning its e- deficinet unlike group 5

20
Q

Give the structure of tBuLi in hexane solution and explain how
spectroscopic methods can be used to confirm it.

A

draw it out if u cant figure out what they want. Li-C - (CH3)3

draw out the tetrameric structure

u can use Li NMR with 13C doped carbons whih will show that Li is bonded to 3 C!!

or u can use 13C nmr with 6Li to show u C is bonded to 3 Li.

21
Q

Explain how the products from the reaction of an amine with diborane may
be spectroscopically investigated. What products are typically formed

A
  • homoleptic
  • heteroleptic cleavage
  • 11B[H] NMR can be used to to identify the different products due to as one will only give a singlet as its only bonded to 4 H’s. which dont split the peak due to it being hydrogen decoupled.
22
Q

Explain the bonding in borazine and with reference to its reaction with a
nucleophile (e.g. Cl- in HCl) comment on the aromaticity of borazine

A

Show how sp2 hybridisation of B and N leads to benzene like structure ( 1
mark). Show how lone pair of N donates to empty p on B ( 1 mark).
Formally written as B-— N+ but actually B+— N- (1 mark). Cl- adds to
B not N. Reaction is addition not substitution. Does not try to retain
unsaturated nature. Not aromatic (up to 2 marks).

23
Q

Methyl aluminium gives an 1H NMR spectrum consisting of two peaks
when collected at -150˚C and one peak at 20˚C. Explain these
observations

A

Draw out dimeric structure (2 marks). Show there are 2 H environments.
(1 mark). Discuss fluxional behaviour (up to 2 marks)

24
Q

Explain why R2C=CR2 is a planar molecule, but R2Sn=SnR2 is not

A

Discuss non-classical double bond. Consider energy difference between s
and p orbitals. Show s to p bonding in Sn and sp2 hybridisation in C. up to
5 marks.

25
Boranes may be considered to be built up from BH units. Draw out the BH unit, stating and showing the hybridisation of the orbitals on the boron atom. On your diagram from part a), label the tangential and radial orbitals.
Draw sp hybridised B, bonded to H s orbital (1 mark). State sp hybridised ( 1 mark). Label used sp as radial (1 mark), label two p orbitals as tangential (1 mark).
26
Explain why the fragment [CH]+ is considered to be isolobal and isoelectronic to the BH fragment
Orbitals have similar shape/symmetry, energy and same number of valence electrons. (3 marks)
27
How many electrons does a ‘P’ atom contribute to cluster bonding?
5 valence electrons- 2(lone pair) = 3 electrons
28
The 11B{1H} NMR spectrum of the cluster 1 showed one doublet. With reasoning, identify the structure of the isolated cluster. : B4CH5P
In the 1,2 isomer there are two B environments, one couple to P, the other not. Hence this would give a doublet and a singlet. In the 1,6 isomer all four B couple to the P hence a single peak. A clear explanation of why its fits for the 1,6 isomer (2marks) and not for the 1,2 isomer (2 marks) is required.
29
Identify apparent valency of bridging C , in Al2Me6
pentavalent!!
30
Explain why the room temperature 1H NMR spectrum of AlMe3 consists of one singlet, but at low temperature, the spectrum consists of two singlets in a 2:1 ratio.
Due to fluxional behaviour not monomer:dimer equilibrium (1 mark) * Static structure of dimer has two environments (bridging to terminal 1:2), (1 mark) a dynamic structure at higher temperature has all Hs seen as the same. * Comment on the timescale of the measurement vs timescale of rearrangement (1 mark) .
31
How does the R–E–E bond angle change upon descending the Group 14 alkyne analogues (REER; E = C, Si, Ge, Sn, Pb)? Explain your answer.
the bond angle decreases down the group from linear to 90° * Discussion of the inert pair effect to explain the reluctance of the s- electrons to engage in bonding on descending the group. * Discussion of the “inert pair effect” and bond strength is needed. On descending the group the energy gap between the s and p orbitals increases. This leads to a large promotion energy which is not compensated for by the weaker bonds upon descending the group. Larger orbitals results in less efficient bonding. Therefore for tin the lone pair predominately resides on the individual atom and does not engage in Sn- Sn multiple bonding
32
State the number of electrons each B-Br moiety contributes to cluster
is sp hybridised. 3 valence electrons, one used to bond to Br. (1/2 mark) 2 electrons available for cluster bonding (1/2 mark)
33
Calculate the total number of polyhedral skeletal electron pairs available for cluster bonding in P2B4Br4.
7 PSEPS, so based on six vertices. Has 6 vertices, so CLOSO
34