3d Flashcards

1
Q

what analytical technique is good at characterising M-CO compounds

A

IR is good at characterising CO compounds

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
2
Q

what analystical technique isnt good at characterising CO compounds and why

A

NMR isnt,, esp 13C NMR

bc theres no CH bonds,, meanign the intensity will be even smaller

the CO are also fluxional on the compound which means they move around

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
3
Q

why do bridging carbonyls look like and whats cool about them

A

bridging carbonyls are when the carbonyl is used as a bridge between other stuff.

so u3(CO) means the CO is bridging 3 diff things together while u2(CO) means ur bridging 2 diff things together using a CO.

bridging CO have an even small // slower stretching frequency bc theres more backbonding into its pi* orbital.

this is bc its bonded to more metals than if it was just a single bond.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
4
Q

how can we reduce the steric crowding in complexes with CO + how does this affect certain interactions

A

we turn terminal CO’s into bridging ones.

this weakens the sigma interaction but strengthens the pi interaction

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
5
Q

whats an example of bridging CO complexes

A

(CO)4 - Co – Co ( CO)4

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
6
Q

whats special about the terminal and bridging CO’s

A

theyre fluxional meaning they keep on changing places

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
7
Q

what must a stretching CO mode be in order to be IR active

A

the CO stretching mode must have a change in dipole moment for it to be IR active!!!

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
8
Q

what are 2 ways we can see if a CO stretching mode is IR active or not

A

drawing the moelcule out and putting arrows on the CO to represent their stretches and see if any of the arrows strengthen eachothers directionality, if they do,, its IR active bc that represents a change in dipole.

we can use point group character tables,, we find the reducible and irreducible operations and then see how many of these correspond to the moelcule,, then look at the end of the table and see if theyre IR or raman active. Ir is the LHs, while Raman is the RHS one.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
9
Q

if all stretches u find for ur complex using point group theory are IR active,, what does this mean

A

it means we should expect to see 4 Ir absorption bands.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
10
Q

what does raman require

A

a change in polarisability

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
11
Q

to look on the graph to see if our stretches are IR active,, what do we need to look for

A

we need to look for x, y , z on the LHS of the graph

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
12
Q

how many IR bands we have corresponds to what

A

how many of our stretches are IR active!!!

remember that stoichiometry affects this!!!

so if u have 2A1 + B1 + B2 and all are IR active,, u get 4 abs bands

How well did you know this?
1
Not at all
2
3
4
5
Perfectly