1d Flashcards

1
Q

whats an organometallic complex

A

a transition metal - Carbon!!!

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2
Q

describe zeise’s salt structure

A

u have Pt(2) as the metal

this is bonded to 3Cls
this is also bonded perpendicularly to an ethene !!

thats the structure but u can also put brackets around it and write K+ H2O if u wanna

+ being the charge on K.

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3
Q

whats Nickel tetracarbonyl

A

Ni(CO)4

its what ppl first used in order to purify Ni

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4
Q

example of a carbonyl anion cluster

A

[Fe(CO)13]^2-

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5
Q

describe ferrocene

A

cyclopentane
Fe
cyclopentane

cyclopentane = C5H5-
Fe = 2+
cyclopentane = C5H5-

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6
Q

why were ppl shocked about freeocene

A

bc its a compound made up of a metal,, and hydrocarbon chain,, but its so so stable??

so the bonding has to be unique bc whattt

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7
Q

describe sigma bonding between a metal and a ligand

A

ligand donating a lone pair to the metal

u have one overlap

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8
Q

describe pi bonding between a metal and a ligand

A

the ligand and metal empty p orbitals have constructive overlap forming a pi bond

u have 2 overlaps

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9
Q

describe a delta bond

A

its when the d orbitals of a metal and ligand all overlap with constructive overlap!!

the d orbitals are like wheels kinda,, so their middle is kinda pointing away from u

u have 4 overlaps!!

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10
Q

what block of orbitals can do pi and delta bonding

A

only the d block can be pi and delta bonding!!!

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11
Q

main group organometallics are what

A

metals of the s and p orbital

they can only do sigma bonding

no pi or delta bonding THERE ARE NO STABLE CARBONYL COMPOUNDS OF THE S AND P BLOCK

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12
Q

d block organometallics have a strong preference for what

A

they have a strong valence electron count preferance!!!

they prefer 18 and sometimes 16e-!!!

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13
Q

describe an octahedral complex with sigma bonding only

A

u have the a1g, t1u, eg bonding orbitals (12 e can fit here)

u have the t2g nonbonding orbital and the eg* orbitals

theres a small 🔺o meaning u can put e- in the t2g or the eg* and it doesnt rlly matter!! bc the eg* is only weakly antibonding.

so theres no preferance for the number of e- u have.

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14
Q

when u have an octahedral complex with only sigma bonding,, where are u e- coming from

A

the metal atomic orbitals d, s, p

the ligand sigma donor orbitals: 12e-

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15
Q

how many e- does a ligand offer

A

2e- each

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16
Q

in a octahedral complex with only sigma bonding,, u have 12e- from the ligand,, (filling up the a1g, t1u, eg) where do the metals e- go

A

either the t2g nonbonding or the eg* thats weakly antibonding,, tbh it rlly doesnt matter bc the 🔺o is so small it can go in either,, so the number of metal e- u have doesnt rlly matter,, bc the energy diff between the orbitals is so low.

17
Q

describe the e- diagram when u have sigma donors and pi acceptor ligands!!! where are u e- coming from

A

u have the d, s, p coming from the metal atomic orbitals

u have the ligand sigma donor orbitals

u have the empty ligand pi acceptor orbitals

18
Q

when u have sigma donors and pi acceptor orbitals:

what are higher in energy

A

the sigma donors are lower in energy and u have 12e- from here

then u have the empty pi acceptor orbitals which are higher in energy

19
Q

when u have sigma donors and pi acceptors,, what do the empty pi acceptor orbitals overlap with

A

they overlap with the t2g* and the t2g bonding

it therefore overlaps with the d orbitals from the metal

20
Q

when u have sigma donors and pi acceptor ligands,, what do the ligand sigma donor orbitals overlap with

A

they overlap with the the t2g and t2g* along with all the other orbitals aswell

21
Q

when u have sigma donors and pi acceptors,, why can the empty pi acceptor orbitals overlap with the t2g d orbitals

A

bc they have t2g symmetry

22
Q

when u have sigma donors and empty pi acceptor ligands, whats diff about the t2g orbitals when we compare them to just sigma donor orbitals

A

the t2g was nonbonding,, however it is now strongly bonding !!!

meaning u have a1g, t1u, eg and t2g as ur bonding orbitals,, giving u 9 bonding MO’s and therefore 18e- can go in here.

this therefore gives us a diff stability as we have 9BO instead of just 6BO.

23
Q

okay so when we have a sigma bonor and pi acceptor orbitals,, why is t2g now strongly bonding instead of non bonding

A

bc u have a crazy massive 🔺o!!!!

and this means u can have more than 18e- but lowks its bad news bc the eg* is insanely antibonding and very high in energy±

24
Q

why do sigma donor and pi acceptors like 18 e- or less

A

bc u have a large 🔺o

meaning u have 9 very strong bonding MO.

but the gap between the t2g and eg* is insanely big,, meaning eg* is a very high energy orbital!!! so putting e- in here is bad news.

25
Q

with good pi acceptor ligands,, what e- config becomes the best config for Oh complexes

A

when we have an octahedral complex with good pi acceptor ligands we look for 18e- configurations,, to fill all the 9 bonding MO’s!!!

and no more than 18 bc the first antibonding, eg* orbital is extremely high in energy and putting e- in here is bad news.

26
Q

why are Cr, Mo and W hexacarbonyl complexes colourless

A

bc their 🔺o is so large that the transition from t2g –> eg* requires energy from the UV region. which is higher in energy than the vis region

27
Q

we have the octahedral 18e-0 configuration for complexes with good pi acceptor ligands,, what other cstable config do we have

A

the 16e- square planar geometry where 1 d orbital is no longer appropriate in bonding.

28
Q

when we have a 16e- configuration in a square planar geometry how many e- do we get from everything

A

we get 8e- from the 4 ligands

meaning we need 8e- from the metal

but theres not many metals that give us 8e-

29
Q

what metals give us 8e-

A

RH1
Ir1
Pd2
Pt2

30
Q

what type of e- compound is zeise’s salt

A

its a 16e- compound

u have Pt2
bonded to 3 Cls

and an orthogonal ethene. and this is an anion so u need the square brackets and the - charge on the outside.

31
Q

what is preferred sterically,, square planar or tetrahedral

A

tetrahedral is preferred.

square planar is usually seen with 2nd and 3rd row d block metals bc theyre larger and allow the 4 ligands to be further away when theyre in the square planar geometry.