Activation Energy 42-43 Flashcards

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1
Q

The average thermal energy per particle is given by what?

A

Thermal energy = KT K is the Boltzmann’s constant, k = 1.38 x 10-23. T is the temperature in kelvin.

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2
Q

What do you do to convert from kT to Jmol-1 ?

A

Multiply by Avogadros constant (6.02 x 10-23).

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3
Q

What do you do to convert kT to eV ( electron-volts)?

A

Divide by the charge on the electron ( 1.6 x 10^-19)

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4
Q

Explain some processes involving particles with activation energies.

A

1) A change of state: the particles need enough energy to break the forces between them.
2) Thermionic emission: if you heat up a conductor, electrons are released from the surface. These electrons need enough enery to escape from the attraction of the positive nuclei.
3) Ionisation in a candle flame: the molecules in the air need enough energy to split up into individual atoms and ions. This is a similar process to thermionic emission.
4) Conduction in a semiconductor: semiconductors will only start to conduct once there are electrons in a high-energy state called the “conduction band” , so electrons need enough energy to jump from the ground state to this higher-energy state.

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5
Q

What is activation energy?

What is the ratio that allows us to see if we can overcome it?

A

Particle in matter are held together by bonds. The energy needed to break these bonds in a given substance is the activation energy E. ( the Greek “epsilon”).

In the ratio E/kT, when kT is big enough compared with E, the bonds are broken and the matter comes apart.

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6
Q

What happens if the ratio between the activation energy and the average energy of the particles is too high?

A

Nothing happens.

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7
Q

Explain how is f is the fraction of particles with an extra energy E, what will be the fraction of particles with an energy of 2E?

A

To get a particle with an average extra energy of about E. So the fraction of particles with an extra energy of 2E will be:

f x f = f2

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8
Q

What are the fraction of particles with the extra energy of 3E and 4E?

A

3e = f3

4e = f4

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