5.4.2 - electrolysis of aqueous compounds Flashcards
what happens to water molecules and what does this mean for electrolysis
they can break apart to form H+ and OH- ions
H2O(l) -> H+(aq) + OH-(aq)
extra ions complicate electrolysis - which ions react and which don’t?
what are the rules for finding out which ion reacts at the anode
if a halide ion (Cl-/Br-/I-) is present, that element is produced as per normal
eg. 2Br- -> Br2 + 2e-
otherwise, O2 and H2O are produced, according to the following half equation:
4OH- -> O2 + 2H2O + 4e-
what are the rules for finding out which ion reacts at the anode
if the metal is less reactive than hydrogen, that element is produced as per normal
(how to remember - ANYTHING IN JEWELLERY WILL GO TO CATHODE AND BE DISCHARGED OVER H+, eg. copper, silver, gold, platinum)
eg. Cu2+ + 2e- -> Cu
otherwise, H2 is produced according to the following half equation:
2H+ + 2e- -> H2
what happens to ions that did not react at anode or cathode
they remain leftover in the solution as a third product
what would happen at the anode in molten electrolysis of NaCl
chlorine (Cl-) is a halide ion, so reacts at the anode:
2Cl- -> Cl2 + 2e-
bubbles of pale green gas would be observed
what would happen at the cathode in molten electrolysis of NaCl
sodium (Na) is more reactive than hydrogen so we get hydrogen instead:
2H+ + 2e- -> H2
bubbles of colourless gas would be observed
what would be leftover in solution in molten electrolysis of NaCl
the Na+ (from NaCl) and OH- ions (from H2O) didn’t react
sodium hydroxide (NaOH) is leftover