4. The Current Ethernet Specification Flashcards
- On an ethernet switched network, what address does one host computer use to communicate with another?
a. IP Address
b. MAC Address
c. Street Address
d. HUB Address
b. On an ethernet network, the MAC address (hardware address) is used for one host to communicate with another.
- Which of the following can run full-duplex and achieve 200 Mbps with Cat 5e cable?
a. 100BaseF
b. 100BaseTX
c. 1000BaseF
d. 1000BaseT
b. 100BaseTX uses Cat 5e and can run 200 Mbps when using full duplex.
- How many devices in a collision domain have to listen when a single host talks?
a. Two
b. Three
c. One
d. All
d. When one device sends a packet out on a network segment, all other devices on the same physical network segment must wait and let it be transmitted.
- If you are using a cable medium called 10Base2, what does this mean?
a. That you are running ethernet over HDMI
b. That you are running ethernet over fibre
c. That you are running ethernet over thicknet
d. That you are bundling multiple connections
e. That you are really old and using thinnet coax for your LAN medium.
e. 10Base2 was one of the very first Ethernet network physical mediums and is a thinner coax.
- What network access control method helps devices share the bandwidth evenly without having two devices transmit at the same time on the network medium? (choose two)
a. TCP/IP
b. CSMA/CD
c. HTTPS
d. TFTP
e. CSMA/CA
b, e. Option B carrier sense multiple access with collision detection (CSMA/CD) helps packets that are transmitted simultaneously from different hosts share bandwidth evenly. You might think that CSMA/CD would be the only correct answer, but always think in terms of what is the best answer out of all the options, and B and E (CSMA/CA) are both correct. The exam will never have cut-and-dry answers.
- What is the maximum distance of 10GBaseSR?
a. 100 meters (328 feet)
b. 302 meters (990 feet)
c. 305 meters (1,000 feet)
d. 1,593 km (990 miles)
b. A 10GBaseSR cable can have a maximum distance of 990 feet (302 meters).
- How many wire pairs are used with half-duplex?
a. Two
b. One
c. Four
d. None of the above
b. With half-duplex, you are using only one pair at a time, with a digital signal either transmitting or receiving.
- How many wire pairs are used with 100BaseTX full-duplex?
a. Two
b. One
c. Four
d. A or C
a. Full-duplex ethernet uses two pairs of wires at the same time.
- What is the maximum distance of 10GBaseLR?
a. 1 mile
b. 3 miles
c. 6 miles
d. 25 miles
c. A 10GBaseLR implementation can go a distance of up to 6 miles.
- What is the effective total throughput increase with a full-duplex connection?
a. None
b. Twice as much
c. Four times as much
d. Ten times as much
b. Double up! You can get 20 Mbps with a 10Mbps ethernet running full-duplex or 200Mbps for fast Fast Ethernet
- What device can you not use full-duplex communication with?
a. Host
b. Hub
c. Switch
d. Router
b. Full-duplex communication can not be used with a hub because a hub is a half-duplex single communication device. A host, switch and router have the ability to process traffic (frames), whereas a hub is a multi-port repeater.
- What is the decimal equivalent of this binary number: 11000000.10101000.00110000.11110000?
a. 192.168.48.92
b. 192.168.48.240
c. 192.168.64.224
d. 192.168.32.248
b. 11000000 is 192, 10101000 is 168, 00110000 is 48, and 11110000 is 240.
- Which IEEE standard is used for ethernet over power lines?
a. 802.3p
b. 1901
c. 802.16
d. 1918
b. In February 2011, the IEEE finally published a standard for broadband over Power Line (BPL) called IEEE 1901; this is also referred to as Power Line Communications (PLC) or even Power Line Digital Subscriber Line (PDSL).
- How is the decimal value 10 represented in binary?
a. 1000
b. 1001
c. 1010
d. 1011
c. Nibble values are 8+4+2+1 giving us a maximum of 15. If we have a decimal value of 10, that means the 8 bit and the 2 bit are turned on.
- What is the decimal value for the binary number 11101000?
a. 128
b. 194
c. 224
d. 232
d. The 128, 64, 32 and 8 bits are on, so just add the values 128 + 64 + 32 + 8 = 232.