23. Compensating for Respiratory and Metabolic Disturbances Flashcards

1
Q

Two rules for compensation?

A

Compensation will never get me back exactly to normal

compensation must be made by other system

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2
Q

If there a respiratory acidosis, how would you compensate?

A

Use kidneys (metabolic) to release HCO3 to bring down concentration of H+ so the pH will increase

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3
Q

Glomerulus filters plasma for raw materials, then goes to proximal convoluted tubule where bulk operations in nephron occurs. Nephron takes back what it needs (glucose, proteins, etc). What is the next step?

A

The loop of Henle: concentrates interstitium, and lastly, the distal convoluted tubule and collecting duct make final adjustments/tuning to blood (ex absorb more sodium or water) *** acid base balancing occurs here for respiratory problems!!!

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4
Q

Why is the distal convoluted tubule and collecting duct important for respiratory acid/alkalosis?

A

Cells here are able to secrete HCO3 or H+ as conditions demand

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5
Q

If acidotic the DCT/CD cells will do what?

A

Move H+ ion to urine and take HCO3 and move it back to the blood, compensating for respiratory acidosis (plasma HCO3 levels will increase)

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6
Q

If respiratory alkalosis the DCT/CD cells will do what?

A

HCO3 will go to the urine and the H+ will go to the blood, so the HCO3 plasma levels will be lower and the pH will become more acidic

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7
Q

Is the problem is acute, there will be no compensation, if the problem is chronic, ?

A

There will be compensation

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8
Q

What is the equation for acute respiratory acidosis to calculate the expected [HCO3]?

A

Expected [HCO3] = 24 + ((PaCO2-40)/10)

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9
Q

What is the equation for chronic respiratory acidosis to calculate the expected HCO3 that will be compensating?

A

Expected [HCO3] = 24 + 4x((PaCO2-40)/10)

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10
Q

What is the equation for acute respiratory alkalosis to calculate the expected HCO3 (will decrease)?

A

Expected HCO3 = 24 - 2((40 - PaCO2)/10)

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11
Q

What is the equation for CHRONIC respiratory alkalosis to calculate the expected HCO3?

A

HCO3= 24- 5((40-PaCO2)/10)

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12
Q

Peripheral chemoreceptors are sensitive to H+ which is being altered by ?

A

the metabolic disturbance, so peripheral are major players

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13
Q

If there is an increase of H+ in the blood, the peripheral chemoreceptors will do what?

A

Increase ventilation to blow off more CO2 and reduce the PaCO2 and bring up pH

(opposite for when there is less H+)

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14
Q

If I have metabolic alkalosis, there will be less activation of the chemorecptors and?

A

a decrease in ventilation to retain CO2, increasing H+, decreasing pH

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15
Q

What is the equation for metabolic acidosis to calculate expected PaCO2?

A

(1.5[HCO3]+8) +/- 2

if between the certain range, the determine the compensation is adequate

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16
Q

What is the equation for metabolic alkalosis to calculate expected change PaCO2 to determine if respiratory compensation is adequate?

A

(0.5 to 1.0) x changeHCO3

if between this range, compensation is adequate

17
Q

Why do we ask if compensation is adequate? (2)

A
  1. respiratory response will be quick and occur before the condition can be chronic
  2. Resp system can only influence only a small part of total HCO3, so it never gets the pHa as close to normal as might be expected (switched)
18
Q

What are some causes of chage in HCO3?

A

Renal problems
GI tract secretes lots of HCO3 and H+, so vomitting and diarrhea
too much tums

19
Q

The anion gap equation is base on the rule that positive and negatively charged anions balance themselves out. What is the equation?

A

Anion gap= [Na+] - ([Cl-]+[HCO3-])

20
Q

From results of anion gap: if acid is made that is not measured by tests, the acid will ?

A

consumed HCO3 because of the HCO3 role as a buffer

21
Q

What is the normal anion gap?

A

equal to or less than 12

22
Q

An elevated anion gap means?

A

There are unmeasured chemicals presents

MUDPILES
methanol
uremia
diabetic ketoacidosis
paraldehyde
isoniazid/iron
lactic acidosis
ethylene glycol
salicylates (aspirin)
23
Q

Osmolarity of blood can be measured how?

Remember normal osmolarity is 290mOsmoles/L

A

Osmolarity = (2xserumNa) + (BUN/2.8) + (glucose/18)