Week 9 (Intro to Spectroscopy/Redox) Flashcards

1
Q

Oxidation State

A

-degree of oxidation for an atom compared to its elemental state
-applies to ions as well as atoms involved in covalent bonds

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2
Q

Positive Oxidation State

A

-indicates electrons have been lost or shared with more electronegative atoms

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3
Q

Negative oxidation state

A

-indicates electrons have been gained or shared from less electronegative atoms

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4
Q

Elemental form oxidation state

A

-oxidation state= 0
-occurs for diatomic atoms such as Cl₂

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5
Q

Single atom ions oxidation state

A

-oxidation state= charge
-Cl⁻ = -1

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6
Q

Atoms in covalent bonds oxidation state

A

-depends on other atoms present
-sum of oxidation states=overall charge

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7
Q

Common oxidation states

A

-do not usually change due to dramatic electronegativity
-F = -1
-O = -2
-Group 1 = +1
-Group 2 = +2
-Group 17= -1

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8
Q

Oxidation

A

-loss of electrons
-oxidation state increases

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9
Q

Reduction

A

-gain of electrons
-oxidation state decreases

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10
Q

Reducing agent

A

-electron donator, causes another atom to become reduced (gain electrons)
-loses electrons in process
-usually less electronegative (such as H, Group 1, and Group 2 metals)

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11
Q

Oxidizing agent

A

-electron receiver, causes another atom to become oxidized (lose electrons)
-gains electrons in process
-usually more electronegative (such as O, halogens (F, Cl, Br), and H₂O₂)

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12
Q

Oxidation number

A

-a book-keeping device used to keep track of the electrons “gained” or “lost” in an atom when it forms bonds with other atoms in molecules/polyatomic ions

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13
Q

number of possible oxidation numbers in an atom

A

-possible oxidation numbers can be determined from the number of valence electrons
-ex.) Cl: 7 valence electrons, lowest possible O.N. is -1, highest possible O.N. is +7 (how many valence electrons it can lose/gain)
-ex.) C: 4 valence electrons, lowest possible O.N. is -4, highest possible O.N. is +4

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14
Q

Guidelines for assigning O.N.

A
  1. O.N. of free elements is always 0, while O.N. of monoatomic ions are the same as its charge (O.N. of Al is 0, O.N. of Al⁺³ is +3)
  2. algebraic sum of O.N. of all atoms equals 0 for an electrically neutral molecule and equals the overall charge for an ionic species (NO₃⁻, 1(O.N. of N) + 3(O.N. of O) = -1)
  3. Metals have a positive O.N. (group 1= +1, group 2= +2)
  4. Nonmetals are assigned in such order (F= -1, H= +1, O= -2, group 17= -1, group 16= -2, group 15= -3)
  5. Any remaining O.N. are filled by following rule 2
  6. polyatomic ions can be used as a reference to break down larger molecules
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15
Q

Carbon oxidation state

A

-determine if atoms are more or less electronegative than carbon
-give electrons in bond to more electronegative atom (if connected to another carbon, they share electrons and each get -1 charge)
-every line = 2 electrons

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16
Q

Spectrophotometer

A

-instrument use to measure/study concentration of colored/light-absorbing chemicals in a solution
-shines light through sample and measures amount of light absorbed/transmitted
-1.00 cm path length is 2x length of 0.50 cm

17
Q

Steps for balancing redox reaction

A
  1. use changes in oxidation number of elements in reactants/products to identify which species is being oxidized/reduced
  2. write oxidation half-reaction and reduction half-reaction (balance elements whose oxidation numbers change, balance electrons gained/lost based on changes in oxidation number, balance net charges by adding H⁺ (when in acidic medium) or OH⁻ (when in basic medium) to either side, balance O and H by adding H₂O to either side)
  3. Make the number of electrons gained from reduction half-reaction equal to number of electrons lost in oxidation half-reaction (by multiplying one or both half-reactions)
  4. add the balanced oxidation and reduction half-reactions together such that the electrons gained cancel out the electrons lost
18
Q

Wavelength and Color

A

-the color of a species’s wavelength is the complementary (transmitted) color
-(ex. if a species absorbs yellow-green, it will appear violet)